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Edexcel GCSE Computer Science (1CP2) Exam Questions

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10 questions · 33 marks

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1Multiple choice1 markSecondary Memory Swap Remove

A company stores films on optical media.

Identify the optical storage medium that can store the most data.

[1 mark]
  • ABlu-ray Disc
  • BCD
  • CDVD
  • DMagnetic tape
Mark scheme
  • A Blu-ray Disc (1)
  • The only correct answer is A. The correct answer is Blu-ray Disc.
  • B is not correct because a CD stores less data than a Blu-ray Disc, up to about 700 MB
  • C is not correct because a DVD stores less data than a Blu-ray Disc, up to about 4.7 GB (single-layer) or 8.4 GB (dual-layer)
  • D is not correct because magnetic tape is not an optical storage medium
Example answers and how they were marked
Full marks1/1

A Blu-ray Disc

Why: Correct option (1): a Blu-ray Disc has the greatest capacity of the optical media.

No marks0/1

C DVD

Why: Near miss scoring 0: a DVD is optical but stores less than a Blu-ray Disc (mark scheme line C). Only A is credited.

No marks0/1

D Magnetic tape

Why: Misconception scoring 0: candidates pick tape for its large capacity but magnetic tape is not an optical storage medium (mark scheme line D).

2Multiple choice1 markStored Program Computers Swap Remove

Identify the component of the CPU that carries out arithmetic and logical operations.

[1 mark]
  • AArithmetic logic unit
  • BControl unit
  • CMain memory
  • DRegister
Mark scheme
  • A Arithmetic logic unit (1)
  • The only correct answer is A. The correct answer is arithmetic logic unit.
  • B is not correct because the control unit decodes instructions and controls the CPU
  • C is not correct because main memory is not part of the CPU and stores data and instructions
  • D is not correct because a register stores small amounts of data within the CPU
Example answers and how they were marked
Full marks1/1

A Arithmetic logic unit

Why: Correct option: the arithmetic logic unit carries out arithmetic and logical operations (1).

No marks0/1

B Control unit

Why: Control unit is a CPU component but its role is to decode and control, not perform arithmetic or logical operations, so no mark.

No marks0/1

D Register

Why: Register stores data but does not carry out operations; a common misconception that any CPU component performs calculations, so no mark.

3Multiple choice1 markStored Program Computers Swap Remove

Identify the function of the control unit in the fetch-decode-execute cycle.

[1 mark]
  • ADecodes instructions
  • BPerforms arithmetic operations
  • CStores data and instructions
  • DTemporarily stores data being processed
Mark scheme
  • A Decodes instructions (1)
  • The only correct answer is A. The correct answer is Decodes instructions.
  • B is not correct because the arithmetic logic unit performs arithmetic operations
  • C is not correct because main memory stores data and instructions
  • D is not correct because registers temporarily store data being processed
Example answers and how they were marked
Full marks1/1

A Decodes instructions

Why: Correct option: the control unit decodes instructions during the fetch-decode-execute cycle (1).

No marks0/1

C Stores data and instructions

Why: Main memory stores data and instructions, not the control unit; this is a common distractor, so no mark.

No marks0/1

B Performs arithmetic operations

Why: Arithmetic operations are performed by the ALU, not the control unit; a common confusion between CPU components, so no mark.

4Describe2 marksPrimary Memory Swap Remove

Computers use main memory (RAM).

Describe the role of main memory (RAM) in the von Neumann stored program concept.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • Holds/stores the data and instructions of the program currently being run (1) to be fetched by the CPU during the fetch-decode-execute cycle (1)
  • Instructions and data are loaded/copied from secondary storage into RAM (1) before they can be processed by the CPU (1)
  • Stores the program that is currently running (1) together with the data that it uses (1)
  • Holds the data and instructions that the CPU needs next (1) so the CPU can access them quickly (1)

Allow a response that describes both that RAM holds the current program and that the program was loaded from secondary storage into RAM, provided each statement is linked to a development.

Do not accept responses about cache or registers as the store of the current program.

Do not accept responses that say RAM stores data permanently or that RAM is read-only.

Do not accept 'RAM is where the CPU processes data' (this describes the ALU/registers), or 'RAM stores the operating system' unless it is linked to the program currently being run.

Do not award a second mark for a response that only states that RAM holds data and instructions with no linked development.

Example answers and how they were marked
Full marks2/2

RAM holds the data and instructions of the program that is currently running (1) so that the CPU can fetch them during the fetch-decode-execute cycle (1).

Why: Linked point (1): holds data and instructions of the current program, plus linked development (1): fetched by the CPU in the cycle.

Some marks1/2

RAM holds the data and instructions that the computer is using at the moment.

Why: States the role (1) but gives no linked development, so only the first mark is awarded.

No marks0/2

RAM is the secondary storage, so the program is kept there when the power is switched off.

Why: Confuses main memory with secondary storage and says contents are kept without power; both near-misses are named in the 'Do not accept' lines, so no mark.

5Describe2 marksSecondary Memory Swap Remove

A laptop uses a solid state drive (SSD) for secondary storage.

Describe how data is stored on a solid state drive.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • Data is stored on (flash) memory chips/cells (1) as a pattern of electrical charges (1)
  • A current/voltage forces electrons through a barrier (1) so that they are trapped (or not trapped) to hold/represent a value (1)
  • Cells with a trapped charge and cells with no trapped charge (1) represent 1s and 0s/binary (1)
  • The trapped charge remains when the power is turned off (1) so the data is not lost/it is non-volatile (1)

Do not accept responses that describe magnetic storage, e.g. magnetised platters, spinning disks or read/write heads, or optical storage, e.g. lasers, pits and lands.

Do not award a mark for 'it is solid state' or 'it has no moving parts' without a description of how the data is stored.

Do not award a mark for restating the stem, e.g. 'a laptop uses an SSD' or 'an SSD uses flash memory'.

'Data is stored as electrical charges' on its own, with no reference to memory chips/cells or to how the charge is held, earns a maximum of one mark (1).

A response that only describes electrons being trapped, with no link to how the value/data is represented, earns one mark (1). The second mark needs a link such as trapped and not trapped charge representing 1s and 0s, or the trapped charge being kept so the data is not lost.

Example answers and how they were marked
Full marks2/2

A current is used to force electrons through a barrier so that they become trapped, and a cell with a trapped charge or a cell with no trapped charge represents a 1 or a 0.

Why: Linked description: a current forces electrons through a barrier (1) and trapped/not trapped charge represents 1s and 0s (1).

Some marks1/2

The data is stored in flash memory chips.

Why: Gives the creditworthy point that data is stored on flash memory chips (1) but does not develop it, e.g. by saying the data is held as electrical charges or by describing trapped electrons.

No marks0/2

The data is stored as magnetised areas on a spinning platter.

Why: This describes magnetic storage, which the mark scheme says not to accept for a solid state drive.

6Explain2 marksSecondary Memory Swap Remove

A hard disk drive stores data on a spinning magnetic platter.

Explain how data is read from a magnetic hard disk.

[2 marks]
Mark scheme

Award up to two marks for a linked explanation such as:

  • The read/write head moves over the surface of the platter (1) and detects whether each area of the disk is magnetised (1)
  • The platter spins/rotates (1) so the read/write head can pass over the whole surface/tracks of the disk (1)
  • The pattern of magnetised and non-magnetised areas detected by the read/write head (1) is read as binary 1s and 0s (1)
  • The drive head detects the direction of magnetisation of each area (1) so the data can be read as binary (1)

For both marks, the expansion must follow/associate with the statement.

Allow one mark for stating that data is read magnetically / that the read/write head detects the magnetisation of the disk without a linked reason.

Do not accept answers that describe how data is written to the disk, such as the head magnetising the platter, rather than how it is read.

Do not accept 'a laser reads the pits and lands' - this describes optical storage, not magnetic storage.

Example answers and how they were marked
Full marks2/2

The platter rotates so the read/write head passes over the whole surface of the disk (1) and it detects whether each area is magnetised or not (1). The pattern of magnetised areas is then read as 1s and 0s.

Why: Linked point (1) rotation of the platter with reason (1) the head reaches the whole surface, and the second line about magnetised areas is also present.

Some marks1/2

The read/write head detects the magnetic charges on the disk.

Why: Allow line (1): states the head detects the magnetisation of the disk, but gives no linked reason (e.g. the platter rotating so the head covers the whole surface), so only one mark.

No marks0/2

A laser shines onto the disk and reads the pits and lands, then the data is sent to the CPU.

Why: Describes optical storage. Do not accept 'a laser reads the pits and lands' - a magnetic disk is read by a head detecting magnetisation.

7Discuss6 marksFetch Decode Execute Cycle Swap Remove

A small robotics company is designing a new robot. The robot's computer uses von Neumann architecture. The engineers are explaining how programs are stored and run.

Discuss how the von Neumann stored program concept and main memory (RAM) are used during the fetch-decode-execute cycle.

Your answer should include:

  • what is meant by the stored program concept
  • the role of RAM in the cycle
  • why the stored program concept is useful.
[6 marks]
Mark scheme

Indicative content

Stored program concept

  • Instructions and data are stored together in the same main memory (RAM).
  • Instructions are fetched one at a time from memory and executed in sequence.
  • The program can be changed by loading different instructions into RAM.
  • The CPU can only execute instructions that are in main memory.

Role of RAM

  • RAM holds the program instructions and the data being used.
  • The address of the next instruction is held in the program counter (PC).
  • The instruction is fetched from RAM using the address bus.
  • The data bus carries the instruction from RAM to the CPU.
  • RAM is volatile, so programs are lost when power is off.
  • RAM is directly accessible by the CPU, unlike secondary storage.

Benefits

  • The same hardware can run many different programs.
  • Programs can be loaded and changed quickly.
  • No need to rewire the computer for a new task.
  • Makes general-purpose computers possible.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)
Example answers and how they were marked
Full marks6/6

The von Neumann stored program concept means that both the program instructions and the data are stored together in the same main memory, RAM. During the fetch-decode-execute cycle, the CPU fetches an instruction from RAM, decodes it in the control unit, and then executes it. The program counter holds the address of the next instruction, and this address is sent along the address bus to RAM. RAM then returns the instruction along the data bus to the CPU. RAM is volatile, so it only holds the program while the robot is powered on. The stored program concept is useful because the robot's computer can run different programs without changing any hardware; new instructions can simply be loaded into RAM. This makes the computer general-purpose and flexible.

Why: Comprehensive understanding: defines stored program concept, explains RAM role with PC, address bus and data bus, applies to robot, and gives benefits. Sustained lines of reasoning. Level 3.

Some marks3/6

The stored program concept is when instructions and data are stored in RAM. The CPU fetches instructions from RAM. The program counter keeps the address of the next instruction. RAM holds the program. The benefit is that you can change the program without rewiring the computer.

Why: Adequate understanding: correct basic points about stored program concept and RAM, with some linkage, but little development or application to the robot's fetch-decode-execute cycle. Level 2.

Some marks1/6

The von Neumann stored program concept is that the CPU uses RAM to store the program. The fetch-decode-execute cycle fetches, decodes and executes. RAM is random access memory. The benefit is that it is fast.

Why: Basic independent points only; no real linkage or application to the robot. Level 1.

8Discuss6 marksPrimary Memory Swap Remove

A school is buying new computers for its IT room. The computers the technician has ordered have 16 GB of RAM and a large hard drive.

Discuss why main memory (RAM) is needed for programs to run on these computers.

Your answer should include:

  • the role of RAM in the stored program concept
  • what happens to a program when it is opened
  • why the CPU cannot execute a program directly from secondary storage.
[6 marks]
Mark scheme

Indicative content

the role of RAM in the stored program concept

  • In the von Neumann stored program concept, a program's instructions and the data it uses are held together in main memory.
  • RAM holds the instructions and data of the program that the CPU is currently processing.
  • The CPU fetches each instruction from RAM during the fetch-decode-execute cycle, so a program must be in RAM before it can be run.
  • RAM is directly accessible by the CPU, so instructions can be fetched quickly enough for the CPU to keep working.

what happens to a program when it is opened

  • When a program is opened, a copy of its instructions and data is transferred from secondary storage, such as the hard drive, into RAM.
  • The operating system loads the program into RAM so that the CPU can start fetching and executing its instructions.
  • When the program is closed, it is removed from RAM, and the space it used is free for another program.
  • If a computer does not have enough RAM, the program may not open, or another open program has to be closed first.

why the CPU cannot execute a program directly from secondary storage

  • Secondary storage, such as a hard disk drive, is much slower to access than RAM.
  • The CPU can process instructions much faster than secondary storage can supply them, so the CPU would have to wait and would not be working at full speed.
  • RAM is fast electronic memory with no moving parts, so data can be read from it in a fraction of the time taken by a magnetic hard disk drive.
  • Running the school's programs directly from secondary storage would make the computers in the IT room very slow to use.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Additional guidance

  • Level 3 responses must cover both the role of RAM in the stored program concept and the speed difference between RAM and secondary storage, with a reason such as the CPU having to wait for instructions.
  • Answers that make only basic, independent points, such as what RAM is, that a program is copied into RAM when it is opened, or that RAM is faster than a hard drive, without linking them to explain why the CPU would have to wait for instructions, are limited to Level 1.
  • Do not accept statements that RAM is permanent storage, that RAM replaces secondary storage, or that secondary storage is read-only.
Example answers and how they were marked
Full marks6/6

The computers need RAM because of the von Neumann stored program concept, in which the instructions of a program and the data it uses are both held in main memory. When a student opens a program on one of the new computers, the operating system copies it from the hard drive into RAM. The CPU then fetches each instruction from RAM in the fetch-decode-execute cycle, so the program must be in RAM before it can be run. The CPU cannot execute a program directly from secondary storage because a hard disk drive is much slower than RAM. It has moving parts and a much lower transfer rate, so the CPU would often have nothing to do while it waited for the next instruction. RAM is fast electronic memory that the CPU can read directly, which is why 16 GB of RAM lets the school run several programs at once and still keep the CPU working at full speed.

Why: Comprehensive understanding: the stored program concept is explained (instructions and data held in main memory), the program being opened is linked to it, and the speed difference is developed with the reason that the CPU would wait for instructions, all applied to the school's computers. Level 3.

Some marks2/6

RAM is the main memory of the computer. It stores the programs and data that are being used at the moment. When you open a program it is copied into RAM, and the CPU fetches instructions from RAM. RAM is faster than the hard drive, so a program runs better from RAM. Having 16 GB means the school can have more programs open at once.

Why: Basic, independent points only: what RAM is, that a program is copied into RAM when it is opened, that the CPU fetches instructions from RAM, and that RAM is faster than a hard drive. None is linked to the stored program concept or developed to explain why the CPU would have to wait for instructions, so Level 1, 2 marks.

No marks0/6

RAM is the permanent storage inside the computer, like a hard drive. The school needs 16 GB of RAM so that all the students' files can be saved permanently. When a program is opened, it is copied from RAM to the CPU. The CPU cannot execute from secondary storage because secondary storage is read-only.

Why: No creditworthy points. RAM is described as permanent storage, files are said to be saved permanently in RAM, a program is said to be copied from RAM to the CPU, and secondary storage is said to be read-only. All are the misconceptions listed in the Do not accept guidance, so Level 0.

9Discuss6 marksSecondary Memory Swap Remove

A school is buying new computers. Each computer needs storage for the operating system, applications and students' work. The computers have RAM and will be used in classrooms.

Discuss the role of secondary storage in these computers.

Your answer should include:

  • why secondary storage is needed
  • the difference between primary and secondary storage
  • a suitable type of secondary storage for the school's computers and a reason why it is suitable.
[6 marks]
Mark scheme

Indicative content

Why secondary storage is needed

  • Secondary storage is non-volatile, so it keeps the operating system, applications and students' work when the power is turned off.
  • It stores programs and files that are not currently in use, so they are not lost when the computer is switched off.
  • It provides a larger capacity than primary storage for files such as students' work, videos and photographs.
  • It allows each computer to keep many students' files and the software the school has installed.

The difference between primary and secondary storage

  • Primary storage (RAM) is volatile and directly accessible by the CPU; secondary storage is non-volatile and not directly accessible by the CPU.
  • RAM holds the data and instructions currently in use; secondary storage holds data and programs long term.
  • Primary storage is faster but smaller and more expensive per gigabyte; secondary storage is slower but larger and cheaper.
  • The school's computers need both: RAM to run the operating system and applications, and secondary storage to keep them when the computer is switched off.

A suitable type of secondary storage for the school's computers and a reason why it is suitable

  • A solid state drive (SSD) is suitable because it has no moving parts, so it is durable and quiet, and has fast read/write speeds, which helps the computers start up quickly.
  • A magnetic hard disk drive (HDD) is suitable because it is cheap and offers a very large capacity, which is useful for storing many students' files.
  • Either type could be used; a small SSD for the operating system and applications plus a large HDD for files would balance speed and cost.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Additional guidance

  • Award credit for a type of secondary storage only when a reason is given that is linked to the school's computers; a named type alone (e.g. 'SSD') is not creditworthy. Do not accept RAM as secondary storage or the claim that secondary storage is the same as RAM. Do not accept CD/DVD/Blu-ray as the main storage for the school's computers because their capacity is too low and write speeds are slow.
  • For Level 3, the answer must cover all three bullets and apply at least one point to the school's computers. A 6-mark answer is well developed with sustained reasoning and a justified choice; a 5-mark answer covers all three but with limited development or application. Comparisons of speed and cost between primary and secondary storage are creditworthy as part of the difference.
Example answers and how they were marked
Full marks6/6

The school needs secondary storage because it is non-volatile, so the operating system, applications and students' work stay on the computer when the power is turned off. RAM is volatile and only holds data currently in use, while secondary storage keeps files long term. Secondary storage is also larger and cheaper per gigabyte than RAM, so it can hold many students' files. An SSD would be suitable because it has no moving parts, so it is durable in a classroom, and it has fast read/write speeds, so the computers start up quickly. A magnetic HDD would give a larger capacity for the same cost, which is useful for storing videos.

Why: Covers all three bullets: why secondary storage is needed (non-volatile, stores OS/apps/work, larger capacity), the difference from RAM (volatile, directly accessible, faster, smaller), and suitable types (SSD durable and fast; HDD cheap and high capacity) applied to the school's computers. Sustained and well structured. Level 3.

Some marks3/6

Secondary storage is needed to store data when the power is off. It is non-volatile, unlike RAM which is volatile. RAM is directly accessed by the CPU and is faster, but secondary storage is bigger. The school could use a hard disk because it has a lot of space.

Why: All three bullets covered with basic points: non-volatile storage when power off (1), difference volatile vs non-volatile (1), HDD with reason of capacity (1). Limited development and application to the school, so low Level 2, 3 marks.

Some marks1/6

Secondary storage is non-volatile so it keeps data when the power is off. It is the same as RAM, which is why it is fast. The school should use a CD because it is cheap and portable.

Why: One creditworthy basic point: non-volatile keeps data (1). Misconception that secondary storage is the same as RAM, and CD is not accepted as suitable main storage, so Level 1.

10Discuss6 marksStored Program Computers Swap Remove

A school is buying new desktop computers for its computer science classroom. The teacher explains that each computer uses the von Neumann stored program concept: the program instructions and the data are stored together in main memory, and the CPU runs each instruction by carrying out the fetch-decode-execute cycle.

Discuss the role of the control unit, the arithmetic logic unit (ALU) and registers in the fetch-decode-execute cycle.

Your answer should include:

  • how an instruction is fetched from main memory and decoded
  • how the ALU executes an instruction
  • how registers are used during the cycle.
[6 marks]
Mark scheme

Indicative content

Fetching and decoding an instruction

  • The register that holds the address of the next instruction (the program counter) contains the address of the instruction to be fetched.
  • This address is sent to main memory (RAM) and the instruction is copied from main memory into a register inside the CPU.
  • The program counter is updated so that it holds the address of the next instruction in the program.
  • The control unit decodes the instruction that has been fetched, working out which operation is required and which data or registers are needed.
  • The control unit sends control signals to coordinate the other components as the instruction is carried out.
  • The control unit decides what happens next, for example after a comparison it decides whether the next instruction is the following one or a jump.

The arithmetic logic unit (ALU) executes an instruction

  • The control unit directs the arithmetic logic unit (ALU) to carry out the operation.
  • The ALU performs arithmetic operations such as addition, subtraction, multiplication and division, for example adding two values in a program written by the class.
  • The ALU performs logical operations such as comparing two values to see if they are equal or whether one is greater than the other.
  • The result of the operation carried out by the ALU is passed back and stored in a register.
  • The ALU operates on data that has been fetched from main memory; it does not fetch the instruction and it does not decide which instruction is next.

Registers

  • Registers are small, very fast memory locations inside the CPU.
  • They hold the data, addresses and results that the CPU is working on during the cycle.
  • Registers are used in every stage of the cycle, not only when the ALU produces a result.
  • Because registers are inside the CPU they can be read and written much faster than main memory during the cycle.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)
  • A Level 3 answer must link the roles of all three components to the fetch, decode and execute stages. An answer that links only one component to a stage, with the other points listed separately, is Level 1 (1–2 marks); an answer that links two of the components to stages is Level 2 (3–4 marks). A point repeated under more than one heading is credited once only.
  • Accept 'the program counter', 'the address register' or 'a register holding the address of the next instruction' as the register that holds the address of the next instruction. Do not accept 'the control unit performs the calculations', 'the ALU controls the timing of the CPU' / 'the ALU sends the clock signal' or 'registers are in main memory (RAM)'.
Example answers and how they were marked
Full marks6/6

In the fetch stage, a register called the program counter holds the address of the next instruction and this address is sent to main memory. The instruction is copied from main memory into a register in the CPU and the program counter is updated so that it points to the next instruction. The control unit then decodes the instruction in the decode stage, working out which operation is required and which data or registers are needed, and it sends control signals to coordinate the other components. In the execute stage the control unit directs the ALU to carry out the operation the class's program needs: the ALU does arithmetic, such as adding two values, or a logical comparison, such as checking whether one value is greater than another, and it does not decide what happens next, the control unit does. The result from the ALU is stored in a register, and because registers hold the data, addresses and results at every stage, the cycle can repeat with the next instruction.

Why: Level 3: the role of each component is linked to the stage it works in (program counter and registers in fetch, control unit decoding and deciding next, ALU executing and its result stored in a register) across all three stages, with the classroom context.

Some marks2/6

The control unit decodes the instruction in the decode stage. The ALU does maths and logic, such as addition and comparing numbers. Registers store data inside the CPU. In the fetch stage the instruction is fetched from the RAM and put into the CPU.

Why: Level 1: several correct basic points that the mark scheme credits (the instruction is fetched from main memory into the CPU, the control unit decodes the instruction, the ALU does arithmetic and logical operations, registers store data) but only the control unit is linked to a stage of the cycle, so the answer is top of Level 1.

Some marks1/6

The control unit decodes instructions. The ALU controls the timing of the CPU and sends the clock signal. Registers are in the RAM and they store the program.

Why: Level 1: one basic point, that the control unit decodes instructions (1). The other statements are on the do-not-accept list (the ALU does not control the timing of the CPU or send the clock signal, and registers are in the CPU, not main memory), so they earn no credit.

Questions by topic

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