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Edexcel GCSE Computer Science (1CP2) Exam Questions

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10 questions · 24 marks

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1Multiple choice1 markUnits & Conversion Swap Remove

A computer stores data in binary.

Identify the number of bits in one kibibyte.

[1 mark]
  • A1024
  • B8000
  • C8192
  • D8 388 608
Mark scheme
  • C 8192 (1)
  • The only correct answer is C. The correct answer is 8192.
  • A is not correct because 1024 is the number of bytes in a kibibyte
  • B is not correct because 8000 is the number of bits in 1000 bytes
  • D is not correct because 8 388 608 is the number of bits in a mebibyte
Example answers and how they were marked
Full marks1/1

C 8192

Why: Correct: one kibibyte is 1024 bytes and 1024 × 8 = 8192 bits (1).

No marks0/1

A 1024

Why: Near miss: 1024 is the number of bytes in a kibibyte, not the number of bits (0).

No marks0/1

B 8000

Why: Typical misconception: uses 1000 bytes for a kibibyte, giving 1000 × 8 = 8000 bits (0).

2Multiple choice1 markImpact of AI Swap Remove

A manufacturer sells a robot that is used in factories.

Identify what is meant by legal liability in this situation.

[1 mark]
  • AThe manufacturer is legally responsible for harm caused by the robot
  • BThe manufacturer checks that the robot cannot cause harm
  • CThe robot produces results that are fair for all workers
  • DThe manufacturer takes responsibility for the robot's decisions
Mark scheme
  • A The manufacturer is legally responsible for harm caused by the robot (1)
  • The only correct answer is A. The correct answer is the manufacturer is legally responsible for harm caused by the robot.
  • B is not correct because checking the robot cannot cause harm is safety
  • C is not correct because fair results for all workers is algorithmic bias
  • D is not correct because taking responsibility for the robot's decisions is accountability
Example answers and how they were marked
Full marks1/1

A The manufacturer is legally responsible for harm caused by the robot

Why: Correct definition of legal liability (1).

No marks0/1

D The manufacturer takes responsibility for the robot's decisions

Why: Near-miss: this is accountability, not legal liability.

No marks0/1

B The manufacturer checks that the robot cannot cause harm

Why: Describes safety, not legal liability.

3Short recall1 markImages Swap Remove

Each pixel in a bitmap image is stored using a number of bits.

Define the term colour depth.

[1 mark]
Mark scheme

Award one mark for any of the following:

  • The number of bits per pixel (1)
  • The number of bits used to represent/store the colour of each pixel (1)

Allow bit depth

Do not accept the number of colours a pixel can have on its own

Do not accept the number of pixels in the image (this is the resolution/image size)

Example answers and how they were marked
Full marks1/1

The number of bits used to store the colour of one pixel.

Why: Gives the number of bits per pixel (1)

No marks0/1

The number of colours that each pixel can use.

Why: Gives the number of colours, not the number of bits; the mark scheme does not accept this on its own

No marks0/1

The number of pixels in the image.

Why: Confuses colour depth with resolution/image size, which the mark scheme does not accept

4Short recall1 markMalware Swap Remove

Anti-malware software helps to protect a computer system.

State what anti-malware software does with a file when it finds that the file is infected.

[1 mark]
Mark scheme

Award one mark for any of the following:

  • Quarantine the file (1)
  • Isolate the file (1)
  • Delete/remove the file (1)
  • Repair/clean the file (1)

Do not accept scan/check the file

Do not accept block/prevent/stop the file from running

Do not accept remove the virus from the system

Example answers and how they were marked
Full marks1/1

Quarantine the file.

Why: Quarantine the file (1).

No marks0/1

Scan the file to see if it is infected.

Why: Scanning is not the action taken after infection is found; the scheme says do not accept scan/check the file.

No marks0/1

Stop the file from running.

Why: Stopping/blocking the file from running is not creditworthy; the scheme says do not accept block/prevent/stop the file from running.

5Short recall2 marksNetwork Security Risks Swap Remove

Penetration testing can be used to identify vulnerabilities in a network.

State two aims of penetration testing.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • To identify possible entry points into the system/network (1)
  • To identify the targets of potential attacks (1)
  • To test whether existing security controls/protections work (1)
  • To report the findings so that weaknesses can be fixed (1)

Accept 'to simulate an attack on the organisation's own network' only when it also states that this is done to find weaknesses, e.g. 'simulate an attack to find weaknesses' (1)

Do not accept 'to simulate an attack' on its own, as it does not say what the testing is for

Do not accept 'to hack the network', as this repeats the method rather than giving an aim

Do not accept 'to steal data' or 'to gain unauthorised access', as these are the aims of an attacker

Example answers and how they were marked
Full marks2/2

To identify possible entry points into the network and to report the findings so that any weaknesses can be fixed.

Why: Two creditworthy aims: identifying possible entry points (1) and reporting findings so weaknesses can be fixed (1).

Some marks1/2

To test whether the existing security controls work.

Why: One listed aim, testing existing security controls (1); no second aim is given.

No marks0/2

To steal data from the company's customers.

Why: Stealing data is an attacker's aim, not an aim of penetration testing; the mark scheme says not to accept it.

6Describe2 marksPeripheral Management Swap Remove

A student uses a graphics tablet connected to a computer to draw in a program.

Describe how the operating system passes input from the graphics tablet to the program.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • The operating system receives signals/data from the graphics tablet (1) and converts them into data the program can use/process (1)
  • The operating system receives data from the graphics tablet (1) and passes/forwards it to the program being used/the active program (1)
  • The tablet's device driver receives/interprets the signals/data from the tablet (1) so the operating system can pass the input to the program (1)
  • The operating system identifies the graphics tablet as the source of the input (1) so the data is sent to the correct program (1)

Accept 'signals' for 'data' throughout.

Accept reference to the device driver only where it is linked to receiving/interpreting the input (e.g. the driver receives the tablet's signals (1) so the OS can pass data to the program (1)).

Do not accept 'the operating system uses a driver' on its own, without saying what the driver does with the input.

Do not accept generic statements such as 'the operating system runs the tablet' as a description of how input is managed.

Do not accept responses that say the operating system creates/finishes the drawing, or that the tablet stores the input permanently.

Example answers and how they were marked
Full marks2/2

The operating system receives signals from the graphics tablet and passes the data to the program.

Why: Receives signals/data from the tablet (1) and passes the data to the active program (1).

Some marks1/2

The operating system receives signals from the graphics tablet.

Why: Gives the first half of a linked description (1): it receives signals, but does not say what happens to the input.

No marks0/2

The operating system uses a device driver to control the graphics tablet and stores the input.

Why: Only says the OS uses a driver to control the tablet and that input is stored; it does not describe the driver receiving/interpreting the input or the input being passed to the program, so no linked point is credited. The mark scheme rejects 'uses a driver' on its own.

7Describe2 marksWireless Connections Swap Remove

A family uses a wireless network at home.

Describe how interference can affect the performance of a wireless network.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • Other electrical/radio devices nearby (1) interfere with the wireless signal so data is corrupted (1)
  • Interference corrupts data (1) so the data has to be resent, which increases latency/slows the transfer (1)
  • Interference reduces the strength of the signal received (1) which lowers the data transfer rate the connection can support (1)
  • Interference makes the connection drop (1) so data transfer stops/devices have to reconnect (1)

Do not accept responses that only name a device (microwave, phone) without saying how it affects the network.

Do not accept responses that only state the network becomes slower without saying what causes the interference or how it affects the data.

Do not accept responses about wired connections or cables.

Example answers and how they were marked
Full marks2/2

Other electrical devices nearby can interfere with the wireless signal and corrupt data, so the data has to be resent and transfers are slower.

Why: Linked point: other electrical devices interfere and corrupt data (1), developed by the data being resent, which slows the transfer (1).

Some marks1/2

Other electrical devices nearby can interfere with the wireless signal.

Why: Cause given: other electrical devices interfere with the signal (1), but no development of how this affects the data or performance.

No marks0/2

Interference happens when the wireless cable is damaged by other cables.

Why: Misconception about cables; the mark scheme does not accept responses about wired connections or cables.

8Convert2 marksHexadecimal to Binary Conversion Swap Remove

Binary, denary and hexadecimal patterns represent numbers.

Convert the hexadecimal number DB to 8-bit binary.

[2 marks]
Mark scheme

Award one mark for each correct nibble in the correct order:

  • 1101 (1)
  • 1011 (1)

0 marks if the response is not 8-bit binary.

Example answers and how they were marked
Full marks2/2

1101 1011

Why: Each digit is 4 bits: D = 1101, B = 1011 (2).

Some marks1/2

1101 1100

Why: Converts B as if it were the next digit up. The first nibble is correct (1); the second is not.

No marks0/2

1011 1101

Why: The nibbles are in the wrong order. Neither nibble is correct.

9Discuss6 marksFetch Decode Execute Cycle Swap Remove

A school is upgrading the desktop computers in its computer science classroom. Each computer has a CPU, main memory and buses. The technician is explaining how the CPU uses these components during the fetch-decode-execute cycle.

Discuss how the CPU uses its components and the buses during the fetch-decode-execute cycle.

Your answer should consider:

  • the role of the CPU and registers
  • the role of the address bus, data bus and control bus
  • the role of the clock.
[6 marks]
Mark scheme

Indicative content

The role of the CPU and registers

  • The control unit decodes the instruction fetched from main memory and controls the other components during the cycle.
  • The ALU carries out arithmetic and logical operations during the execute stage, such as adding two values held in registers.
  • Registers hold the data, addresses and results that the CPU is working on during the cycle.
  • The program counter holds the address of the next instruction to be fetched, so it is incremented after each fetch.
  • The memory address register holds the address of the memory location that is about to be read or written.
  • The memory data register holds the instruction or data that has been fetched from or is being written to main memory.

The role of the address bus, data bus and control bus

  • The address bus carries the address of the memory location that the CPU needs to access from the CPU to main memory.
  • The address bus is one-way, so addresses are only sent from the CPU to main memory.
  • The data bus carries instructions and data between the CPU and main memory, so it is bi-directional.
  • The width of the data bus affects how many bits can be transferred at one time.
  • The control bus carries control signals such as read and write signals, so main memory knows whether the CPU wants to read an instruction or write data.
  • The control bus carries signals from the control unit to coordinate the components during the fetch-decode-execute cycle.

The role of the clock

  • The clock sends regular pulses that synchronise the actions of the CPU and main memory.
  • Each clock pulse triggers the next step of the fetch-decode-execute cycle, so the stages happen in the correct order.
  • The clock provides a regular timing signal so that the fetch-decode-execute cycle repeats at a steady rate.
  • The clock is separate from the control bus; the control bus carries control signals, while the clock provides timing pulses.
  • Do not credit the address bus storing addresses, the data bus storing data, or the control bus controlling the computer without naming a control signal; do not credit clock speed affecting performance as a role in the cycle.
  • Level 3 responses must cover all three bullets and link them to the fetch-decode-execute cycle; Level 2 answers may identify roles but link them only partly to the cycle.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)
Example answers and how they were marked
Full marks6/6

The control unit decodes each instruction that is fetched from main memory and then controls the other components to execute it. The program counter holds the address of the next instruction, and this address is copied to the memory address register before it is sent along the address bus. The address bus carries this address from the CPU to main memory, and it is one-way. The data bus then carries the instruction back from main memory to the CPU; it is bi-directional, so it can also carry data to be written. The memory data register holds the instruction that has been fetched. The control bus carries read and write signals from the control unit, so memory knows whether the CPU wants to read an instruction or write data. During the execute stage, the ALU performs arithmetic or logical operations on data held in registers. The clock sends regular pulses that synchronise each stage, so one fetch, decode or execute step happens on each tick and the cycle repeats in the correct order.

Why: Comprehensive understanding of the CPU, registers, all three buses and the clock, with sustained application to the fetch-decode-execute cycle. Level 3.

Some marks4/6

The address bus carries the address of the next instruction from the program counter to main memory so it can be fetched. The data bus carries the instruction back to the CPU, and it is bi-directional. The control unit decodes the instruction. The clock sends pulses to keep the stages in order.

Why: Adequate understanding of some roles with some linkage to the fetch-decode-execute cycle, but the control bus, ALU and most registers are not covered. Level 2.

Some marks1/6

The data bus carries data between the CPU and RAM. The address bus stores the addresses that the CPU needs. The control bus controls the computer. The clock is the speed of the CPU.

Why: One basic, independent point (the data bus carries data) (1). The address bus does not store addresses, the control bus point names no control signal and clock speed is not a role in the cycle, so no further credit. Level 1.

10Discuss6 marksLow and High Level Languages Swap Remove

A company is developing the firmware for a robotic vacuum cleaner. The firmware must read the distance sensors and control the motors. The vacuum cleaner has a small amount of memory.

Discuss the characteristics of a low-level programming language that make it suitable for writing the firmware.

Your answer should include:

  • control of the hardware
  • the efficiency of the code
  • the link between the language and the processor.
[6 marks]
Mark scheme

Indicative content

Control of the hardware

  • Low-level languages can read and write the contents of registers and memory addresses directly, so the firmware can take the values from the distance sensors without calling a library routine.
  • Assembly language instructions can read from and write to specific input/output ports on the vacuum cleaner's processor, so the motors can be switched on and off directly.
  • The programmer decides exactly which processor operations are carried out and in which order, which matters when the vacuum must reverse away from a step or an obstacle.
  • A low-level language puts nothing between the program and the hardware, so the programmer can control the hardware of the vacuum cleaner precisely.

Efficiency of the code

  • Assembly language code can be hand-optimised instruction by instruction, so the code that checks a sensor is as short as possible.
  • The programmer can choose which registers hold values that are used again and again, which cuts down the number of memory accesses the firmware needs.
  • A hand-written low-level program can be made compact, so it is more likely to fit in the small amount of memory the vacuum cleaner has.
  • Because each instruction does one defined job, the time taken to react to a sensor reading is predictable, which suits firmware that must not overrun.

Link between the language and the processor

  • Low-level languages are processor-specific, so the instructions used are those of the exact processor in the vacuum cleaner rather than general statements that need translating.
  • Each assembly language instruction maps to one machine code instruction, so the programmer knows precisely which processor operation will be carried out by each line of code.
  • An assembler turns each mnemonic into its machine code equivalent, so the machine code running on the vacuum cleaner's processor is exactly what the programmer wrote.
  • Code written for a different processor would have to be rewritten, which is acceptable here because the vacuum cleaner always uses the same processor.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Within Level 1, award 1 mark for a single basic point and 2 marks for two or more independent basic points; Level 2 requires the points to be linked to the vacuum cleaner; Level 3 requires both control of the hardware and efficiency of the code, and a few concise, linked sentences can reach Level 3, so extra length is not required.

Accept registers, memory addresses, input/output ports, machine code and mnemonics as ways of describing access to the hardware, and accept 'a low-level language is faster' as a basic point on its own. Do not award 'binary is a low-level language' (machine code is written in binary, but binary is not a language), or characteristics of high-level languages such as being easy to read or portable, as characteristics of a low-level language.

Example answers and how they were marked
Full marks6/6

A low-level language can read and write to registers and to input/output ports directly, so the firmware can take the distance sensor readings and switch the motors without needing library routines. It can be hand-optimised instruction by instruction, so the code that checks a sensor is short and the time it takes is predictable, and a compact program is more likely to fit in the vacuum cleaner's small memory. The language is processor-specific and each assembly instruction maps to one machine code instruction, so the programmer knows exactly which operation the vacuum's processor will carry out, and the assembled machine code is exactly what they wrote.

Why: Covers all three bullets: direct control of registers and ports applied to the sensors and motors, hand-optimised compact code with predictable timing applied to the small memory, and the one-to-one link to the processor's own instruction set. Linked and applied throughout, so Level 3.

Some marks2/6

A low-level language can control the hardware directly. It can read the sensors and control the motors. It is also faster than a high-level language, so the vacuum responds quickly. This is useful because it has little memory.

Why: Three basic, independent points: direct control of the hardware applied to the sensors and motors, faster execution, and suitability for limited memory. They are asserted without development (no registers, ports or predictable timing) and the link between the language and the processor is missing, so Level 1, two or more basic points (2).

Some marks1/6

A low-level language is written in binary, so the computer can understand it directly. It is faster than a high-level language.

Why: 'Faster than a high-level language' is a creditworthy basic point (1). 'Written in binary' is not awarded, as binary itself is not a language and the do-not-award rule applies. Only one undeveloped point with no application to the vacuum cleaner, so Level 1, single basic point (1).

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