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Edexcel GCSE Computer Science (1CP2) Exam Questions

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9 questions · 29 marks

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1Multiple choice1 markCharacter Sets Swap Remove

A new character set must be able to represent 70 different characters.

Identify the minimum number of bits needed to represent each character.

[1 mark]
  • A6
  • B7
  • C8
  • D70
Mark scheme
  • B 7 (1)
  • The only correct answer is B. The correct answer is 7.
  • A is not correct because 6 bits give only 64 combinations, which is not enough for 70 characters
  • C is not correct because 7 bits already give 128 combinations, so 8 bits is not the minimum needed
  • D is not correct because 70 is the number of characters needed, not a number of bits
Example answers and how they were marked
Full marks1/1

B 7

Why: The only correct answer: 7 bits give 128 combinations, enough for 70 characters, and it is the smallest number of bits that does (1).

No marks0/1

C 8

Why: Distractor, no credit: a single-tick item has no partial credit, and 8 bits is not the minimum because 7 bits already give 128 combinations, so the scheme's C line gives no mark.

No marks0/1

A 6

Why: Misconception, no credit: 6 bits give only 64 combinations, which cannot represent 70 different characters, so the scheme's A line gives no mark.

2Multiple choice1 markUnits & Conversion Swap Remove

Units of data storage can be binary or decimal.

Identify the unit of storage that is equivalent to 1024 gibibytes.

[1 mark]
  • AGibibyte
  • BMebibyte
  • CTebibyte
  • DTerabyte
Mark scheme
  • C Tebibyte (1)
  • The only correct answer is C. The correct answer is tebibyte.
  • A is not correct because a gibibyte is 1024 mebibytes
  • B is not correct because a mebibyte is 1024 kibibytes
  • D is not correct because a terabyte is 1000 gigabytes
Example answers and how they were marked
Full marks1/1

C Tebibyte

Why: Correct: 1024 gibibytes make one tebibyte (1).

No marks0/1

A Gibibyte

Why: Near miss: a gibibyte is 1024 mebibytes, not 1024 gibibytes (0).

No marks0/1

D Terabyte

Why: Typical misconception: uses the decimal terabyte (1000 gigabytes) instead of the binary tebibyte (0).

3Short recall2 marksLANs & WANs Swap Remove

A school has computers in every classroom.

Define the term 'local area network (LAN)'.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • A network that covers a small geographical area / is on a single site / is within one building (1)
  • (Two or more) computers/devices connected together (1)
  • So that the connected devices can share data/files/resources such as printers or an internet connection (1)
  • Uses cabling/infrastructure owned by the organisation (1)

Do not accept a network that covers a large geographical area / connects networks in different countries, as this describes a WAN.

Do not accept 'a network in a school' on its own, as this repeats the stem without a LAN feature such as a single site or connected devices.

Do not accept 'a network that connects to the internet' without a LAN feature such as a single site or connected devices.

Do not accept 'owned by one organisation' on its own, as a WAN can also be owned by one organisation.

Do not accept 'local' on its own without saying what it means.

The share mark needs the sharing to be linked to the connected devices/network, e.g. 'share files' or 'share printers'.

Example answers and how they were marked
Full marks2/2

A LAN is a group of computers connected together on one site, such as a school, so that they can share files and printers.

Why: Connected together (1) and single site (1); the sharing point is also made but the maximum is two marks.

Some marks1/2

A network that is in one building.

Why: Covers a single site/one building (1) but does not say that devices are connected together or what they share.

No marks0/2

A network that covers a large area and connects different countries.

Why: Describes a WAN, not a LAN, so no creditworthy LAN point is made.

4Explain2 marksFile Management Swap Remove

An operating system stops a new file from replacing an existing file with the same name in the same folder.

Explain one reason why the operating system does this.

[2 marks]
Mark scheme

Award up to two marks for a linked explanation such as:

  • Existing data would be lost (1) because the new file would overwrite/replace its contents (1)
  • The original file could not be recovered (1) because its contents would be destroyed/replaced (1)
  • A program that uses the existing file would fail (1) because the file's data would have been changed/removed (1)
  • The user could lose important work (1) because the old file is replaced by the new one (1)

For both marks, the expansion must follow/associate with the statement.

Do not accept 'so files do not have the same name' without a reason linked to loss of data.

Do not accept 'to keep files tidy' or 'so the computer does not crash' without a reason linked to the existing file's contents being lost.

Example answers and how they were marked
Full marks2/2

The user would lose the existing file (1) because the new file would overwrite its contents (1).

Why: Linked point (1) and reason (1).

Some marks1/2

The old file would be lost (1).

Why: Point only; no linked reason stating that the new file would overwrite its contents.

No marks0/2

So two files do not have the same name (0) because each file needs a different name.

Why: Repeats the rule about names and does not explain the loss of existing data.

5Convert2 marksDenary to Hexadecimal Conversion Swap Remove

Computers manipulate binary patterns.

Convert the denary number 90 to hexadecimal.

[2 marks]
Mark scheme

Award one mark for each correct digit in the correct position:

  • 5 (1)
  • A (1)

Answer: 5A

Example answers and how they were marked
Full marks2/2

5A

Why: 90 ÷ 16 = 5 remainder 10, so the digits are 5 and A: both digits are correct (2).

Some marks1/2

510

Why: One digit is correct (1), but a digit over 9 is written in denary instead of as a letter.

No marks0/2

A5

Why: The digits are the wrong way round, so neither is in the correct position.

6Calculate3 marksAdding Binary Numbers Swap Remove

Computers manipulate binary patterns.

(a)

Complete the table to show the 8-bit result of the binary addition.

[2 marks]
1286432168421
11000001
01100011
Mark scheme

Award one mark for each correct nibble in the correct order:

  • 0010 (1)
  • 0100 (1)

0 marks if the response is not 8-bit binary.

Ignore a carry shown beyond the eighth bit.

Example answers and how they were marked
Full marks2/2

0010 0100

Why: 193 + 99 = 292, which needs 9 bits; the 8 bits that are kept are both correct (2).

Some marks1/2

0010 0101

Why: A slip in the last bit. The first nibble is correct (1); the second is not.

No marks0/2

1110 0011

Why: Never carries. Neither nibble is correct.

(b)

State the name of the error that occurs when this addition is carried out.

[1 mark]
Mark scheme

Award one mark for:

  • overflow (error) (1)
Example answers and how they were marked
Full marks1/1

Overflow

Why: The result needs more bits than are available (1).

No marks0/1

Underflow

Why: A near miss: the result is too big for 8 bits, not too small.

No marks0/1

A syntax error

Why: A syntax error is a mistake in a program's code, not in arithmetic.

7Discuss6 marksEmbedded Systems Swap Remove

A delivery company is developing a drone to deliver small parcels to customers' homes. The drone has sensors, a camera, a GPS receiver and rotors, and it must fly autonomously and avoid obstacles.

Discuss the use of embedded systems in the delivery drone.

Your answer should include:

  • what embedded systems are used for in the drone
  • the benefits of using embedded systems in the drone
  • any drawbacks or limitations of using embedded systems in the drone
[6 marks]
Mark scheme

Indicative content

What embedded systems are used for in the drone

  • An embedded system is a computer built into a larger device that performs a single, dedicated function as part of that device.
  • The drone contains several embedded systems, and each one is dedicated to a task such as flight control, navigation, obstacle detection or battery monitoring rather than being a general-purpose computer.
  • The flight controller embedded system processes data from the drone's sensors and changes the signals sent to the rotors, so the drone stays stable and can be steered while carrying a parcel.
  • The GPS receiver embedded system works out the drone's position and uses it to navigate along the route to the customer's address.
  • The camera embedded system captures images or video that are processed to detect obstacles, such as trees, buildings or overhead cables, in the drone's path.
  • Sensor embedded systems, for example ultrasonic or infrared sensors, measure the distance to the ground and to obstacles so the drone can land and avoid collisions.
  • The battery management and communication embedded systems monitor the charge and send the drone's status and location to the control centre, and the rotor-control embedded systems drive the rotors so the drone can take off, hover and land.

Benefits of using embedded systems in the drone

  • Embedded systems use little power, so the drone can fly for longer and deliver more parcels on one charge.
  • They are small and light, which is important because a heavier drone needs more power to stay in the air.
  • Because each embedded system is dedicated to one task, it can respond quickly and reliably, so the drone can change direction in time to avoid an obstacle.
  • Combining the processor, memory and input/output in one unit reduces the number of separate components and the cost per drone, so a fleet of delivery drones is cheaper to build.
  • Embedded systems allow the drone to fly autonomously, so the company does not need a human pilot for every delivery.
  • Programs are held in ROM, so the drone's behaviour is consistent and predictable each time it flies.

Any drawbacks or limitations of using embedded systems in the drone

  • Each embedded system has limited processing power, so the drone may not be able to run complex obstacle-recognition software and could fail to identify an unusual obstacle.
  • They have limited storage and RAM, so the drone cannot store much flight data or video on board and must send it to the control centre.
  • The software is held in ROM and is difficult to update, so fixing a bug or adding a new feature may mean returning the drone or connecting it to a computer.
  • The embedded systems are dedicated to the drone, so they cannot easily be reused for a different task if the drone is retired.
  • If an embedded system fails, the drone may crash, which could injure people or damage property, so robustness is essential.
  • A general-purpose computer would be too large and heavy for the drone, so the drone has to use these limited dedicated systems and cannot run general-purpose software.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Additional guidance

  • Level 3 responses must cover what embedded systems are used for in the drone and both benefits and drawbacks/limitations, with reasoning applied to the delivery drone. Do not accept general-purpose computer uses such as connecting to Wi-Fi to play videos, installing new software, apps or games, or using a server; do not accept the drone itself as a single embedded system unless a specific dedicated function is explained.
  • A definition of an embedded system on its own, with no application to the drone, cannot lift an answer above Level 1; limited storage and inability to be repurposed must be linked to the drone, for example little flight data can be stored or the system cannot be reused for another task, to gain credit.
Example answers and how they were marked
Full marks6/6

An embedded system is a computer built into a larger device that performs a dedicated function. The delivery drone contains several embedded systems. The flight controller is an embedded system that takes data from the drone's sensors and adjusts the speed of each rotor, so the drone stays level and stable while carrying a parcel. The GPS embedded system calculates the drone's position and works out the route to the customer's address. The camera embedded system takes images that are processed to spot obstacles such as trees or overhead cables, and the sensor embedded systems measure the distance to the ground so the drone can land safely. These systems are dedicated to one task each, so they respond quickly, which allows the drone to change direction in time to avoid an obstacle. They are also small and light and use little power, so the drone can fly further on one charge and deliver more parcels. Because each embedded system is built into the drone, the drone can fly autonomously and the company does not need a pilot for every delivery. However, the embedded systems have limited processing power and storage, so the drone may not be able to run complex obstacle-recognition software and might not recognise an unusual obstacle. Their software is held in ROM, so fixing a bug is difficult and the drone may have to be returned or connected to a computer to be updated. If an embedded system fails, the drone could crash, which could injure someone or damage property. Overall, embedded systems make the delivery drone possible because they are small, light and dedicated, but their limitations mean the drone cannot do every task that a general-purpose computer could.

Why: Definition of an embedded system (1); uses with reasons applied to the drone, including the flight controller, GPS, camera and sensors (1); benefits linked to weight, power, responsiveness and autonomous flight (1); drawbacks linked to limited processing/storage, ROM updates and crash risk (1); sustained lines of reasoning connect the uses, benefits and drawbacks to the delivery drone throughout, so Level 3, 6 marks.

Some marks3/6

An embedded system is a small computer inside a device that does one job. The drone uses a flight controller embedded system to keep it balanced and change the rotor speeds, and a GPS embedded system to find the address. The camera embedded system helps it avoid obstacles. Embedded systems are small and light and use little power, which is good for a drone because it has to stay in the air. A drawback is that they have limited processing power, so the drone might not recognise an obstacle.

Why: Definition (1); some uses with a little linkage to the drone, flight controller and GPS (1); a benefit linked to the drone staying in the air (1); one drawback linked to obstacle recognition (1). However, the points are brief and mostly asserted, with only some linkages, so Level 2, 3 marks.

No marks0/6

The drone uses embedded systems to connect to Wi-Fi and play videos. They are good because you can install games on them.

Why: No creditworthy point. The answer gives general-purpose computer uses (Wi-Fi and playing videos) that are not linked to the drone's delivery function, and claims that new software or games can be installed, which the mark scheme says not to accept. No drone-relevant use, benefit or drawback is given, so Level 0.

8Discuss6 marksFetch Decode Execute Cycle Swap Remove

A school is upgrading the desktop computers in its computer science classroom. Each computer has a CPU, main memory and buses. The technician is explaining how the CPU uses these components during the fetch-decode-execute cycle.

Discuss how the CPU uses its components and the buses during the fetch-decode-execute cycle.

Your answer should consider:

  • the role of the CPU and registers
  • the role of the address bus, data bus and control bus
  • the role of the clock.
[6 marks]
Mark scheme

Indicative content

The role of the CPU and registers

  • The control unit decodes the instruction fetched from main memory and controls the other components during the cycle.
  • The ALU carries out arithmetic and logical operations during the execute stage, such as adding two values held in registers.
  • Registers hold the data, addresses and results that the CPU is working on during the cycle.
  • The program counter holds the address of the next instruction to be fetched, so it is incremented after each fetch.
  • The memory address register holds the address of the memory location that is about to be read or written.
  • The memory data register holds the instruction or data that has been fetched from or is being written to main memory.

The role of the address bus, data bus and control bus

  • The address bus carries the address of the memory location that the CPU needs to access from the CPU to main memory.
  • The address bus is one-way, so addresses are only sent from the CPU to main memory.
  • The data bus carries instructions and data between the CPU and main memory, so it is bi-directional.
  • The width of the data bus affects how many bits can be transferred at one time.
  • The control bus carries control signals such as read and write signals, so main memory knows whether the CPU wants to read an instruction or write data.
  • The control bus carries signals from the control unit to coordinate the components during the fetch-decode-execute cycle.

The role of the clock

  • The clock sends regular pulses that synchronise the actions of the CPU and main memory.
  • Each clock pulse triggers the next step of the fetch-decode-execute cycle, so the stages happen in the correct order.
  • The clock provides a regular timing signal so that the fetch-decode-execute cycle repeats at a steady rate.
  • The clock is separate from the control bus; the control bus carries control signals, while the clock provides timing pulses.
  • Do not credit the address bus storing addresses, the data bus storing data, or the control bus controlling the computer without naming a control signal; do not credit clock speed affecting performance as a role in the cycle.
  • Level 3 responses must cover all three bullets and link them to the fetch-decode-execute cycle; Level 2 answers may identify roles but link them only partly to the cycle.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)
Example answers and how they were marked
Full marks6/6

The control unit decodes each instruction that is fetched from main memory and then controls the other components to execute it. The program counter holds the address of the next instruction, and this address is copied to the memory address register before it is sent along the address bus. The address bus carries this address from the CPU to main memory, and it is one-way. The data bus then carries the instruction back from main memory to the CPU; it is bi-directional, so it can also carry data to be written. The memory data register holds the instruction that has been fetched. The control bus carries read and write signals from the control unit, so memory knows whether the CPU wants to read an instruction or write data. During the execute stage, the ALU performs arithmetic or logical operations on data held in registers. The clock sends regular pulses that synchronise each stage, so one fetch, decode or execute step happens on each tick and the cycle repeats in the correct order.

Why: Comprehensive understanding of the CPU, registers, all three buses and the clock, with sustained application to the fetch-decode-execute cycle. Level 3.

Some marks4/6

The address bus carries the address of the next instruction from the program counter to main memory so it can be fetched. The data bus carries the instruction back to the CPU, and it is bi-directional. The control unit decodes the instruction. The clock sends pulses to keep the stages in order.

Why: Adequate understanding of some roles with some linkage to the fetch-decode-execute cycle, but the control bus, ALU and most registers are not covered. Level 2.

Some marks1/6

The data bus carries data between the CPU and RAM. The address bus stores the addresses that the CPU needs. The control bus controls the computer. The clock is the speed of the CPU.

Why: One basic, independent point (the data bus carries data) (1). The address bus does not store addresses, the control bus point names no control signal and clock speed is not a role in the cycle, so no further credit. Level 1.

9Discuss6 marksLow and High Level Languages Swap Remove

A company is developing the firmware for a robotic vacuum cleaner. The firmware must read the distance sensors and control the motors. The vacuum cleaner has a small amount of memory.

Discuss the characteristics of a low-level programming language that make it suitable for writing the firmware.

Your answer should include:

  • control of the hardware
  • the efficiency of the code
  • the link between the language and the processor.
[6 marks]
Mark scheme

Indicative content

Control of the hardware

  • Low-level languages can read and write the contents of registers and memory addresses directly, so the firmware can take the values from the distance sensors without calling a library routine.
  • Assembly language instructions can read from and write to specific input/output ports on the vacuum cleaner's processor, so the motors can be switched on and off directly.
  • The programmer decides exactly which processor operations are carried out and in which order, which matters when the vacuum must reverse away from a step or an obstacle.
  • A low-level language puts nothing between the program and the hardware, so the programmer can control the hardware of the vacuum cleaner precisely.

Efficiency of the code

  • Assembly language code can be hand-optimised instruction by instruction, so the code that checks a sensor is as short as possible.
  • The programmer can choose which registers hold values that are used again and again, which cuts down the number of memory accesses the firmware needs.
  • A hand-written low-level program can be made compact, so it is more likely to fit in the small amount of memory the vacuum cleaner has.
  • Because each instruction does one defined job, the time taken to react to a sensor reading is predictable, which suits firmware that must not overrun.

Link between the language and the processor

  • Low-level languages are processor-specific, so the instructions used are those of the exact processor in the vacuum cleaner rather than general statements that need translating.
  • Each assembly language instruction maps to one machine code instruction, so the programmer knows precisely which processor operation will be carried out by each line of code.
  • An assembler turns each mnemonic into its machine code equivalent, so the machine code running on the vacuum cleaner's processor is exactly what the programmer wrote.
  • Code written for a different processor would have to be rewritten, which is acceptable here because the vacuum cleaner always uses the same processor.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Within Level 1, award 1 mark for a single basic point and 2 marks for two or more independent basic points; Level 2 requires the points to be linked to the vacuum cleaner; Level 3 requires both control of the hardware and efficiency of the code, and a few concise, linked sentences can reach Level 3, so extra length is not required.

Accept registers, memory addresses, input/output ports, machine code and mnemonics as ways of describing access to the hardware, and accept 'a low-level language is faster' as a basic point on its own. Do not award 'binary is a low-level language' (machine code is written in binary, but binary is not a language), or characteristics of high-level languages such as being easy to read or portable, as characteristics of a low-level language.

Example answers and how they were marked
Full marks6/6

A low-level language can read and write to registers and to input/output ports directly, so the firmware can take the distance sensor readings and switch the motors without needing library routines. It can be hand-optimised instruction by instruction, so the code that checks a sensor is short and the time it takes is predictable, and a compact program is more likely to fit in the vacuum cleaner's small memory. The language is processor-specific and each assembly instruction maps to one machine code instruction, so the programmer knows exactly which operation the vacuum's processor will carry out, and the assembled machine code is exactly what they wrote.

Why: Covers all three bullets: direct control of registers and ports applied to the sensors and motors, hand-optimised compact code with predictable timing applied to the small memory, and the one-to-one link to the processor's own instruction set. Linked and applied throughout, so Level 3.

Some marks2/6

A low-level language can control the hardware directly. It can read the sensors and control the motors. It is also faster than a high-level language, so the vacuum responds quickly. This is useful because it has little memory.

Why: Three basic, independent points: direct control of the hardware applied to the sensors and motors, faster execution, and suitability for limited memory. They are asserted without development (no registers, ports or predictable timing) and the link between the language and the processor is missing, so Level 1, two or more basic points (2).

Some marks1/6

A low-level language is written in binary, so the computer can understand it directly. It is faster than a high-level language.

Why: 'Faster than a high-level language' is a creditworthy basic point (1). 'Written in binary' is not awarded, as binary itself is not a language and the do-not-award rule applies. Only one undeveloped point with no application to the vacuum cleaner, so Level 1, single basic point (1).

Questions by topic

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