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Edexcel GCSE Computer Science (1CP2) Exam Questions

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4 questions · 16 marks

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1Describe2 marksStored Program Computers Swap Remove

The control unit (CU) is a component inside the CPU.

Describe the role of the control unit in the fetch-decode-execute cycle.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • Decodes each (fetched) instruction (1) to work out which operation is needed / which components should carry it out (1)
  • Coordinates/directs the other components (1) by sending control signals along the control bus (1)
  • Fetches the next instruction (1) by sending its address to main memory along the address bus (1)
  • Sends a read/write control signal to main memory (1) so that the instruction or data is transferred during the fetch/execute stage (1)

Do not accept answers about synchronising the CPU or timing the cycles (that is the role of the clock).

Do not accept answers about carrying out arithmetic or logical operations (that is the ALU).

Do not accept answers about holding data or the results of instructions (that is registers/main memory).

Do not accept generic answers that only say the CU controls the CPU or processes instructions, with no linked development.

Only award one mark for a response that only repeats that the CU sends control signals; the second mark needs a linked outcome such as coordination, a memory read/write, or fetching an instruction.

Do not accept 'during the decode stage' as the development for the decoding point, as it restates the question.

Example answers and how they were marked
Full marks2/2

It decodes the instruction that has been fetched so that it knows which operation the CPU must carry out and which components should do it.

Why: Decoding named with the acceptable wording 'each (fetched) instruction' (1), plus the linked development that this identifies the operation and components (1).

Some marks1/2

It decodes each instruction during the decode stage of the cycle.

Why: Earns (1) for decoding the instruction. 'During the decode stage' restates the question and is not accepted as a development, so the second mark is not earned.

No marks0/2

It carries out the calculations and comparisons when the instruction is executed.

Why: Calculations and comparisons are the ALU's role, which the 'Do not accept' line rules out, so no mark is earned.

2Describe2 marksStored Program Computers Swap Remove

The CPU contains an arithmetic logic unit (ALU).

Describe the purpose of the arithmetic logic unit (ALU).

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • Carries out arithmetic operations/calculations, such as addition or subtraction (1) so that the result can be stored in a register (1)
  • Carries out logical operations, such as comparing two data items (1) to see which one is greater/larger (1)
  • Compares two data items (1) to decide whether a condition is true / which path a program takes next (1)

Allow the result of an arithmetic or logical operation being held/stored in a register, but only where the operation is named.

Do not accept answers that say the ALU stores data or results without naming an operation (registers/main memory store data).

Do not accept answers about controlling components, decoding instructions or timing (that is the control unit or the clock).

Do not award credit for 'it processes data' on its own; an arithmetic or a logical operation must be named.

An example on its own, e.g. 'it adds two numbers', does not earn a second mark; the second mark needs a linked development.

Example answers and how they were marked
Full marks2/2

The ALU carries out arithmetic operations such as addition and subtraction, and the result of the calculation is stored in a register.

Why: Linked point (1) for arithmetic operations with an example, and development (1) for the result being stored in a register.

Some marks1/2

It does all the calculations in the CPU, for example adding two numbers together.

Why: Point (1) for arithmetic operations/calculations named with an example; no linked development, so the second mark is not earned.

No marks0/2

It stores the results of calculations so that they can be used by the CPU later.

Why: Storing results with no arithmetic or logical operation named, which the 'Do not accept' line rules out, so no mark is earned.

3Discuss6 marksPrimary Memory Swap Remove

An employee is writing a report on a laptop. There is a power cut and the laptop turns off. When power is restored, the employee cannot find the report file.

Discuss the role of RAM in this situation.

Your answer should include:

  • why the report was lost
  • the difference between RAM and secondary storage
  • how the employee could prevent this in future.
[6 marks]
Mark scheme

Indicative content

Why the report was lost

  • The report was being created and edited in RAM, which is volatile.
  • Volatile memory loses its contents when the power supply is removed.
  • The power cut removed the power, so the data in RAM was lost.
  • The report had not been saved to secondary storage before the power cut.
  • Only data that had been saved to secondary storage would remain after the power cut.

The difference between RAM and secondary storage

  • RAM is volatile and holds data temporarily while the computer is on.
  • Secondary storage is non-volatile and keeps data permanently when the power is off.
  • RAM is directly accessible by the CPU and is much faster than secondary storage.
  • Secondary storage has a larger capacity and is cheaper per gigabyte than RAM.
  • RAM holds the programs and data currently in use; secondary storage holds files for long-term storage.

How the employee could prevent this in future

  • The employee should save the report regularly to secondary storage, such as the hard drive or a USB flash drive.
  • The employee could enable autosave or autosave/recovery features in the word processor.
  • The employee could use cloud storage that saves changes automatically.
  • The employee could use an uninterruptible power supply (UPS) or battery to keep the laptop on during a power cut.
  • The employee should not rely on RAM to keep work permanently.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Additional guidance

  • Level 3 responses must explain that RAM is volatile and contrast this with non-volatile secondary storage.
  • Do not award marks for stating that the report was lost from secondary storage unless it had been saved there.
Example answers and how they were marked
Full marks6/6

The report was lost because it was being held in RAM, which is volatile memory. RAM only keeps its contents while the computer has power. When the power cut happened, the laptop turned off and everything in RAM was lost, including the unsaved report. RAM is different from secondary storage because secondary storage is non-volatile and keeps data permanently even when the power is off. For example, the hard drive would still contain the report if it had been saved. RAM is also much faster than secondary storage and is used for programs and data currently in use. To prevent this in future, the employee should save the report regularly to the hard drive or use autosave. They could also save to cloud storage, which saves automatically, or use a UPS to keep the laptop running during a power cut.

Why: Comprehensive understanding of RAM volatility, clear contrast with non-volatile secondary storage, and well-linked prevention methods applied to the employee's situation.

Some marks4/6

The report was lost because it was in RAM. RAM is temporary memory and it loses data when the power goes off. Secondary storage is permanent, so if the employee had saved the report it would still be there. RAM is faster than secondary storage. To prevent it, they should save their work.

Why: Adequate understanding shown through the volatility of RAM and the difference from permanent secondary storage, but the answer lacks detail about why the report was specifically lost and gives only a brief prevention method.

No marks0/6

The report was lost from the hard drive because the power cut erased it. RAM is permanent storage, so the report should have been saved there. The employee should buy more RAM to stop this happening again.

Why: No creditworthy points. The answer wrongly says the report was lost from the hard drive and that RAM is permanent storage, and it suggests more RAM will prevent power-loss data loss. These are misconceptions.

4Discuss6 marksStored Program Computers Swap Remove

A college is replacing the computers in its IT suite. The technician tells the students that the new computers use the von Neumann stored program concept.

Discuss the von Neumann stored program concept and the role of the CPU and main memory (RAM) in the fetch-decode-execute cycle.

Your answer should consider:

  • the role of main memory (RAM)
  • the role of the CPU components (control unit, arithmetic logic unit, registers and clock)
  • the role of the address, data and control buses.

You do not need to consider how clock speed affects performance.

[6 marks]
Mark scheme

Indicative content

Stored program concept

  • The stored program concept means that the program instructions and the data the program is using are both held in the same main memory (RAM).
  • The CPU fetches an instruction from main memory, the control unit decodes it and the instruction is executed, and this is repeated in the fetch-decode-execute cycle.
  • The program is stored as a set of binary instructions, so a different program can be run on the college's new computers by loading different instructions into RAM rather than by changing any hardware.
  • Instructions are usually carried out one at a time, in the order in which they are stored, which is suitable for the computers in the IT suite that each run one piece of software at a time.

Main memory (RAM)

  • Main memory (RAM) holds the instructions and the data that the CPU is currently using.
  • RAM is directly accessible by the CPU, so the required instruction or item of data can be fetched quickly during the fetch stage of the cycle.
  • RAM can be read from and written to while a program is running, so the results produced by the students' work can be stored back into memory.
  • RAM is volatile, so its contents are lost when the power is turned off, and the college's computers will have empty RAM each time they are started.

CPU components

  • The control unit decodes each instruction and coordinates the timing and control of the other parts of the CPU, so it directs the fetch-decode-execute cycle.
  • The arithmetic logic unit (ALU) carries out arithmetic operations and logical comparisons on the data, for example working out a student's total mark in a spreadsheet.
  • Registers are small, fast storage locations inside the CPU that hold the address of the next instruction, the instruction being decoded and the data being worked on.
  • The clock sends a regular signal that synchronises the actions of the CPU, so each step of the cycle is carried out in time with the clock.

Buses

  • The address bus is one way, from the CPU to main memory, and carries the address of the memory location that the CPU wants to read from or write to.
  • The data bus carries the instruction or the data between the CPU and main memory, so it is used to bring an instruction to the CPU in the fetch stage.
  • The control bus carries control signals such as read and write, so the CPU can tell main memory whether it is reading an instruction or writing data.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Additional guidance

  • Level 3 responses must cover the role of main memory (RAM) and the role of the CPU components or the buses during the fetch-decode-execute cycle, as well as the stored program concept.
  • Do not accept RAM described as being inside the CPU, or as non-volatile, or any point about how clock speed affects performance, because the question excludes it.
Example answers and how they were marked
Full marks6/6

The von Neumann stored program concept means that the program instructions and the data the program is using are both held in the same main memory (RAM). This means each of the college's new computers can run any piece of software simply by loading a different set of instructions into its RAM, with no change to the hardware. The CPU fetches an instruction from RAM, the control unit decodes it and the instruction is executed, and this repeats in the fetch-decode-execute cycle. RAM holds the instructions and data that the CPU is currently using and is directly accessible by the CPU, so they can be fetched quickly, but it is volatile, so the contents are lost when a computer is switched off at the end of the day. During the fetch stage, the address bus carries the address of the instruction in RAM, the data bus carries the instruction back to the CPU, and the control bus carries the control signals, such as read, that tell main memory what to do. Registers inside the CPU hold the address of the next instruction and the data being worked on, the clock sends a regular signal so that every step of the cycle happens in time, and the ALU carries out the arithmetic and logical operations needed by the students' work in the IT suite.

Why: Level 3: accurate stored program concept linked to loading software on the college's computers, the role of RAM including volatility, and the roles of the address, data and control buses, registers, clock and ALU, all applied to the situation.

Some marks3/6

The stored program concept means that the program instructions and the data the program is using are stored together in the same memory. The CPU fetches an instruction from main memory, decodes it and then executes it. Main memory (RAM) holds the instructions and data that the CPU is using and it can be read from and written to, so the CPU can get at them quickly. RAM is volatile, so its contents are lost when the computer is switched off.

Why: Level 2: an adequate account of the stored program concept and the role of RAM, with one line of reasoning (fetch, decode, execute) and the volatility point, but no coverage of the CPU components or the buses and no application to the college's computers, so it stays at the lower end of Level 2.

Some marks1/6

In von Neumann architecture the CPU fetches and decodes instructions one at a time. RAM is the memory inside the CPU that stores the program so that it is not lost when the computer is switched off. The clock speed makes the CPU faster so the fetch-decode-execute cycle runs more quickly.

Why: Level 1: one basic point about the CPU fetching and decoding instructions from memory; RAM is wrongly placed inside the CPU and described as non-volatile and the clock speed point is excluded by the question, so neither is credited.

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