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Edexcel GCSE Computer Science (1CP2) Exam Questions

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3 questions · 14 marks

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1Describe2 marksStored Program Computers Swap Remove

A computer is based on the von Neumann stored program concept.

Describe how the CPU uses main memory (RAM) during the fetch-decode-execute cycle.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • The program's instructions (and the data it uses) are held in main memory/RAM (1) so the CPU fetches both the instructions and the data from that one memory (1)
  • The CPU fetches the next instruction from main memory/RAM (1) using the address of the memory location that holds it (1)
  • The CPU reads/fetches data from main memory/RAM (1) when an instruction needs it and writes the result back to main memory/RAM (1)
  • The program's instructions are held in main memory/RAM while the program runs (1) and the CPU fetches them one at a time/one after another to be decoded and executed (1)

Allow 'memory' for main memory/RAM.

Allow 'gets' for fetches/reads.

For both marks, the development must say what the CPU does with the contents of main memory (fetches/reads/writes), not just that main memory is used.

Do not accept answers about the program being stored in secondary storage, such as on a hard drive, or about it being loaded from there.

Do not accept benefits such as the computer running faster or being easier for the user.

Do not accept naming CPU components (control unit, arithmetic logic unit, registers) or buses on their own, without saying what is stored or fetched.

Do not accept 'the computer stores data' on its own, without a link to the instructions of a program.

Example answers and how they were marked
Full marks2/2

The program's instructions and the data it uses are both held in the same main memory (RAM), so the CPU can fetch the instructions and the data it needs from that one memory.

Why: Linked point (1) that instructions and data are stored together in main memory, with the development (1) that the CPU fetches both from the same memory.

Some marks1/2

The CPU fetches the instructions from main memory so that they are processed more quickly.

Why: The first point earns (1) for the CPU fetching instructions from main memory. The second statement is a benefit (speed), which the 'Do not accept benefits' line rules out, so it earns nothing.

No marks0/2

The control unit decodes each instruction and the ALU carries out the calculations.

Why: Both statements name CPU components without saying what is stored, fetched or written, which the mark scheme tells examiners not to accept, so neither earns a mark.

2Discuss6 marksPrimary Memory Swap Remove

An employee is writing a report on a laptop. There is a power cut and the laptop turns off. When power is restored, the employee cannot find the report file.

Discuss the role of RAM in this situation.

Your answer should include:

  • why the report was lost
  • the difference between RAM and secondary storage
  • how the employee could prevent this in future.
[6 marks]
Mark scheme

Indicative content

Why the report was lost

  • The report was being created and edited in RAM, which is volatile.
  • Volatile memory loses its contents when the power supply is removed.
  • The power cut removed the power, so the data in RAM was lost.
  • The report had not been saved to secondary storage before the power cut.
  • Only data that had been saved to secondary storage would remain after the power cut.

The difference between RAM and secondary storage

  • RAM is volatile and holds data temporarily while the computer is on.
  • Secondary storage is non-volatile and keeps data permanently when the power is off.
  • RAM is directly accessible by the CPU and is much faster than secondary storage.
  • Secondary storage has a larger capacity and is cheaper per gigabyte than RAM.
  • RAM holds the programs and data currently in use; secondary storage holds files for long-term storage.

How the employee could prevent this in future

  • The employee should save the report regularly to secondary storage, such as the hard drive or a USB flash drive.
  • The employee could enable autosave or autosave/recovery features in the word processor.
  • The employee could use cloud storage that saves changes automatically.
  • The employee could use an uninterruptible power supply (UPS) or battery to keep the laptop on during a power cut.
  • The employee should not rely on RAM to keep work permanently.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Additional guidance

  • Level 3 responses must explain that RAM is volatile and contrast this with non-volatile secondary storage.
  • Do not award marks for stating that the report was lost from secondary storage unless it had been saved there.
Example answers and how they were marked
Full marks6/6

The report was lost because it was being held in RAM, which is volatile memory. RAM only keeps its contents while the computer has power. When the power cut happened, the laptop turned off and everything in RAM was lost, including the unsaved report. RAM is different from secondary storage because secondary storage is non-volatile and keeps data permanently even when the power is off. For example, the hard drive would still contain the report if it had been saved. RAM is also much faster than secondary storage and is used for programs and data currently in use. To prevent this in future, the employee should save the report regularly to the hard drive or use autosave. They could also save to cloud storage, which saves automatically, or use a UPS to keep the laptop running during a power cut.

Why: Comprehensive understanding of RAM volatility, clear contrast with non-volatile secondary storage, and well-linked prevention methods applied to the employee's situation.

Some marks4/6

The report was lost because it was in RAM. RAM is temporary memory and it loses data when the power goes off. Secondary storage is permanent, so if the employee had saved the report it would still be there. RAM is faster than secondary storage. To prevent it, they should save their work.

Why: Adequate understanding shown through the volatility of RAM and the difference from permanent secondary storage, but the answer lacks detail about why the report was specifically lost and gives only a brief prevention method.

No marks0/6

The report was lost from the hard drive because the power cut erased it. RAM is permanent storage, so the report should have been saved there. The employee should buy more RAM to stop this happening again.

Why: No creditworthy points. The answer wrongly says the report was lost from the hard drive and that RAM is permanent storage, and it suggests more RAM will prevent power-loss data loss. These are misconceptions.

3Discuss6 marksFetch Decode Execute Cycle Swap Remove

A school is upgrading the desktop computers in its computer science classroom. Each computer has a CPU, main memory and buses. The technician is explaining how the CPU uses these components during the fetch-decode-execute cycle.

Discuss how the CPU uses its components and the buses during the fetch-decode-execute cycle.

Your answer should consider:

  • the role of the CPU and registers
  • the role of the address bus, data bus and control bus
  • the role of the clock.
[6 marks]
Mark scheme

Indicative content

The role of the CPU and registers

  • The control unit decodes the instruction fetched from main memory and controls the other components during the cycle.
  • The ALU carries out arithmetic and logical operations during the execute stage, such as adding two values held in registers.
  • Registers hold the data, addresses and results that the CPU is working on during the cycle.
  • The program counter holds the address of the next instruction to be fetched, so it is incremented after each fetch.
  • The memory address register holds the address of the memory location that is about to be read or written.
  • The memory data register holds the instruction or data that has been fetched from or is being written to main memory.

The role of the address bus, data bus and control bus

  • The address bus carries the address of the memory location that the CPU needs to access from the CPU to main memory.
  • The address bus is one-way, so addresses are only sent from the CPU to main memory.
  • The data bus carries instructions and data between the CPU and main memory, so it is bi-directional.
  • The width of the data bus affects how many bits can be transferred at one time.
  • The control bus carries control signals such as read and write signals, so main memory knows whether the CPU wants to read an instruction or write data.
  • The control bus carries signals from the control unit to coordinate the components during the fetch-decode-execute cycle.

The role of the clock

  • The clock sends regular pulses that synchronise the actions of the CPU and main memory.
  • Each clock pulse triggers the next step of the fetch-decode-execute cycle, so the stages happen in the correct order.
  • The clock provides a regular timing signal so that the fetch-decode-execute cycle repeats at a steady rate.
  • The clock is separate from the control bus; the control bus carries control signals, while the clock provides timing pulses.
  • Do not credit the address bus storing addresses, the data bus storing data, or the control bus controlling the computer without naming a control signal; do not credit clock speed affecting performance as a role in the cycle.
  • Level 3 responses must cover all three bullets and link them to the fetch-decode-execute cycle; Level 2 answers may identify roles but link them only partly to the cycle.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)
Example answers and how they were marked
Full marks6/6

The control unit decodes each instruction that is fetched from main memory and then controls the other components to execute it. The program counter holds the address of the next instruction, and this address is copied to the memory address register before it is sent along the address bus. The address bus carries this address from the CPU to main memory, and it is one-way. The data bus then carries the instruction back from main memory to the CPU; it is bi-directional, so it can also carry data to be written. The memory data register holds the instruction that has been fetched. The control bus carries read and write signals from the control unit, so memory knows whether the CPU wants to read an instruction or write data. During the execute stage, the ALU performs arithmetic or logical operations on data held in registers. The clock sends regular pulses that synchronise each stage, so one fetch, decode or execute step happens on each tick and the cycle repeats in the correct order.

Why: Comprehensive understanding of the CPU, registers, all three buses and the clock, with sustained application to the fetch-decode-execute cycle. Level 3.

Some marks4/6

The address bus carries the address of the next instruction from the program counter to main memory so it can be fetched. The data bus carries the instruction back to the CPU, and it is bi-directional. The control unit decodes the instruction. The clock sends pulses to keep the stages in order.

Why: Adequate understanding of some roles with some linkage to the fetch-decode-execute cycle, but the control bus, ALU and most registers are not covered. Level 2.

Some marks1/6

The data bus carries data between the CPU and RAM. The address bus stores the addresses that the CPU needs. The control bus controls the computer. The clock is the speed of the CPU.

Why: One basic, independent point (the data bus carries data) (1). The address bus does not store addresses, the control bus point names no control signal and clock speed is not a role in the cycle, so no further credit. Level 1.

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