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Edexcel GCSE Computer Science (1CP2) Exam Questions

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5 questions · 12 marks

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1Multiple choice1 markStored Program Computers Swap Remove

Identify the function of the control unit in the fetch-decode-execute cycle.

[1 mark]
  • ADecodes instructions
  • BPerforms arithmetic operations
  • CStores data and instructions
  • DTemporarily stores data being processed
Mark scheme
  • A Decodes instructions (1)
  • The only correct answer is A. The correct answer is Decodes instructions.
  • B is not correct because the arithmetic logic unit performs arithmetic operations
  • C is not correct because main memory stores data and instructions
  • D is not correct because registers temporarily store data being processed
Example answers and how they were marked
Full marks1/1

A Decodes instructions

Why: Correct option: the control unit decodes instructions during the fetch-decode-execute cycle (1).

No marks0/1

C Stores data and instructions

Why: Main memory stores data and instructions, not the control unit; this is a common distractor, so no mark.

No marks0/1

B Performs arithmetic operations

Why: Arithmetic operations are performed by the ALU, not the control unit; a common confusion between CPU components, so no mark.

2Multiple choice1 markCharacter Sets Swap Remove

Characters are encoded using 7-bit ASCII.

Identify the number of different characters that can be represented using 7-bit ASCII.

[1 mark]
  • A64
  • B127
  • C128
  • D256
Mark scheme
  • C 128 (1)
  • The only correct answer is C. The correct answer is 128.
  • A is not correct because 6 bits give only 64 different combinations
  • B is not correct because 127 is the largest 7-bit value, not the number of characters that 7 bits can represent
  • D is not correct because 256 characters need 8 bits, as used by 8-bit extended ASCII
Example answers and how they were marked
Full marks1/1

C 128

Why: Selects the only correct option (1): 7 bits give 2 to the power of 7, which is 128 different characters.

No marks0/1

D 256

Why: Near miss scoring 0: 256 is the number of characters that 8 bits give in extended ASCII, not 7-bit ASCII.

No marks0/1

B 127

Why: Misconception scoring 0, the off-by-one error the examiners' report describes: 127 is the largest 7-bit value, but 7 bits give 128 different characters.

3Short recall1 markUnits & Conversion Swap Remove

A file has a size of 2 kibibytes.

State the number of bytes in the file.

[1 mark]
Mark scheme

Award one mark for:

  • 2048 (1)
  • 2 × 1024 (1)
  • 2^11 (1)

Allow 2048 bytes.

Do not accept 2000, which is the number of bytes in two decimal kilobytes.

Do not accept 1024, which is the number of bytes in one kibibyte.

Do not accept 16, which is the number of bits in two bytes.

Example answers and how they were marked
Full marks1/1

2048

Why: 2048 is 2 × 1024, the number of bytes in 2 kibibytes (1).

No marks0/1

2000

Why: 2000 uses the decimal kilobyte, not the binary kibibyte; the mark scheme does not accept it.

No marks0/1

16

Why: 16 is the number of bits in two bytes, confusing bits with bytes; the mark scheme does not accept it.

4Calculate3 marksAdding Binary Numbers Swap Remove

Binary patterns can represent numbers.

(a)

Complete the table to show the 8-bit result of the binary addition.

[2 marks]
1286432168421
11011011
11011100
Mark scheme

Award one mark for each correct nibble in the correct order:

  • 1011 (1)
  • 0111 (1)

0 marks if the response is not 8-bit binary.

Ignore a carry shown beyond the eighth bit.

Example answers and how they were marked
Full marks2/2

1011 0111

Why: 219 + 220 = 439, which needs 9 bits; the 8 bits that are kept are both correct (2).

Some marks1/2

0000 0111

Why: Forgets to carry the 1s. The second nibble is correct (1); the first is not.

No marks0/2

1101 1111

Why: Never carries. Neither nibble is correct.

(b)

State the name of the error that occurs when this addition is carried out.

[1 mark]
Mark scheme

Award one mark for:

  • overflow (error) (1)
Example answers and how they were marked
Full marks1/1

Overflow

Why: The result needs more bits than are available (1).

No marks0/1

Underflow

Why: A near miss: the result is too big for 8 bits, not too small.

No marks0/1

A syntax error

Why: A syntax error is a mistake in a program's code, not in arithmetic.

5Discuss6 marksUser Management Swap Remove

A school library has 24 computers that are shared by students and teachers throughout the day. Each computer runs an operating system. The school wants users' work to be kept private and the computers to be used only by authorised people.

Discuss how the operating system's user management features can be used to share the computers securely.

Your answer should include:

  • user accounts
  • authentication
  • the benefits for the school.
[6 marks]
Mark scheme

Indicative content

User accounts

  • Each student and teacher should have their own user account, so the operating system can identify the person who is logged on.
  • The operating system keeps a record of all valid users on the computer, so unknown users are not allowed to log in.
  • A separate home area or folder can be created for each account, so a student's saved work is kept apart from other users' work.
  • An account can be disabled when a student leaves the school, so they can no longer access the computers.

Authentication

  • A username and password can be required at login, so only users with the correct details can use the computer.
  • The operating system checks the entered password against the stored password for that account before allowing access.
  • Users should be encouraged to choose a strong password, which makes it harder for someone else to guess and log in.
  • The operating system can lock an account after several failed login attempts, which reduces the chance of someone trying passwords repeatedly.

Benefits for the school

  • Many students can share the same computers because each person's files are kept separate.
  • Work is less likely to be deleted or changed by another student, because users only see their own files.
  • The school can see which account was used on a computer, so misuse can be traced to a user.
  • Teachers can be confident that only authorised people can use the library computers.
  • The school does not need a separate computer for every student, so it saves money.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Level 3 responses must cover both user accounts and authentication, and apply them to the school library.

Do not accept general operating system functions such as file management or process management unless they are explicitly linked to managing users.

Example answers and how they were marked
Full marks6/6

Each student and teacher should have their own user account with a username and password. When someone logs in, the operating system checks the password against the one stored for that account, so only authorised people can use the computer. Each account can have its own home folder, so a student's work is kept private and another student cannot open or delete it. If a student leaves the school, their account can be disabled so they cannot log in again. This lets the school share a smaller number of computers safely, as each user's work stays separate and any misuse can be traced to the logged-in account.

Why: Level 3. It explains user accounts, authentication and benefits, with sustained links to sharing computers in the school library.

Some marks4/6

Every user should have a username and password. The operating system checks the password so that people who are not allowed cannot log in. Each user should also have their own area to save files so they do not delete other people's work.

Why: Level 2. Basic accounts and authentication points are made and linked, but the benefits to the school are only briefly applied and not developed.

No marks0/6

The operating system manages the users by looking after the files in folders and by making sure the printer works for everyone. It also keeps the computer running quickly when lots of students use it.

Why: Level 0. These are general operating system functions such as file management and peripheral management, not user management, so no creditworthy point is made.

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