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Edexcel GCSE Computer Science (1CP2) Exam Questions

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4 questions · 17 marks

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1Short recall3 marksStored Program Computers Swap Remove

The CPU contains several components.

Name three components of the CPU.

[3 marks]
Mark scheme

Award one mark for any of the following up to a maximum of three marks:

  • Control unit / CU (1)
  • Arithmetic logic unit / ALU (1)
  • Register(s) (1)
  • Clock (1)

Do not accept main memory / RAM.

Do not accept cache.

Marks can be awarded in any order.

Example answers and how they were marked
Full marks3/3

Control unit, arithmetic logic unit and registers.

Why: Names three creditworthy CPU components (control unit, ALU, registers), one mark each.

Some marks2/3

Control unit, clock and main memory.

Why: Control unit (1) and clock (1) are creditworthy; main memory is not a component of the CPU, a common misconception seen in the June 2023 question.

No marks0/3

Main memory, RAM and cache.

Why: None are CPU components named in the specification; candidates often confuse main memory with CPU components.

2Calculate2 marksAdding Binary Numbers Swap Remove

Computers manipulate binary patterns.

Complete the table to show the result of the 8-bit binary addition.

[2 marks]
1286432168421
10010101
01001111
Mark scheme

Award one mark for each correct nibble in the correct order:

  • 1110 (1)
  • 0100 (1)

0 marks if the response is not 8-bit binary.

Example answers and how they were marked
Full marks2/2

1110 0100

Why: 149 + 79 = 228, carrying where a column adds to 2: both nibbles are correct (2).

Some marks1/2

1110 0101

Why: A slip in the last bit. The first nibble is correct (1); the second is not.

No marks0/2

1101 1111

Why: Writes 1 in every column with a 1 and never carries. Neither nibble is correct.

3Discuss6 marksFile Management Swap Remove

A small business has one computer with a single hard disk. Two employees save documents and photographs to it every day. The operating system manages the disk.

Discuss why the operating system needs to manage where files are stored on the disk.

Your answer should include:

  • how the operating system allocates disk space when a file is saved
  • how the operating system keeps track of each file
  • what could happen if the operating system did not manage files
[6 marks]
Mark scheme

Indicative content

Allocating space

  • The operating system checks that there is enough free space before a file is saved, so a large photograph does not make the save fail.
  • The operating system finds free space on the disk and allocates it to the new file, so the file's data has somewhere to be written.
  • Disk space is allocated so that a file is not written on top of data that already belongs to another file.
  • When a file is deleted, the operating system marks its space as free so it can be used again by the next document that is saved.

Keeping track

  • The operating system keeps a record of the name, size and location of every file, so it knows where each file is stored.
  • The record is updated whenever a file is saved, renamed or deleted, so it still matches what is on the disk.
  • The operating system uses this record to find a file again, so an employee can open a document or photograph that was saved earlier.
  • The record lets the operating system tell the two employees' documents and photographs apart, even though they are all on the same disk.

Without this management

  • Two files could be given the same space, so one document would overwrite another and the work would be lost.
  • The operating system would not know where a file is stored, so a saved document could not be found and opened again.
  • Space used by deleted files might never be freed, so the disk would fill up and new files could not be saved.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Level 3 responses must cover both the allocation of space and the tracking of files, with at least one consequence of no management linked to its cause. Reference to a file being split across blocks that are not next to each other, or to the record holding the location of each block, is Level 3 detail and is not required.

Basic, unlinked points with no application to the business's documents or photographs, and a consequence such as 'files would be lost' with no cause given, are limited to Level 1; to reach Level 2 a point must be linked to a reason (for example, the record is kept so a document can be found again) and be applied to the context. Do not accept defragmentation, process scheduling, user management, peripheral management, or backup and antivirus scanning, as file management.

Example answers and how they were marked
Full marks6/6

Before a document is saved, the operating system checks that there is enough free space on the single disk, so a large photograph cannot make the save fail. It then finds free space and allocates it to the new file, making sure it does not write over data that already belongs to another file. The operating system keeps a record of the name, size and location of every file and updates it whenever a file is saved or deleted. It uses this record to find a file again, so an employee can open a document that was saved earlier. Without this, the two employees could be given the same space, so one document would overwrite the other, or the operating system would not know where a file is stored and the business could not find its work again.

Why: Covers both allocation (free space check, free space given to the file, no overwriting) and tracking (record of name, size and location, updated on save, used to find the file), applies it to the business's single disk and its two employees' documents and photographs, and links the consequences of no management to their causes: Level 3.

Some marks2/6

The operating system decides where on the disk a file is saved. It also keeps a record of where each file is stored. Without this, files would be lost.

Why: Two basic points are made: space is allocated when a file is saved, and a record of where each file is stored is kept. Neither is linked to a reason, there is no application to the business's documents and photographs, and 'files would be lost' is given with no cause: Level 1, top of the level.

Some marks1/6

The operating system puts files in the right place so the disk does not get full. It also defragments the disk to make the files smaller.

Why: One basic point about the operating system placing files on the disk so it does not fill up (Level 1). Defragmentation is not file management and does not make files smaller, so it is not credited: Level 1.

4Discuss6 marksLow and High Level Languages Swap Remove

A company is developing the firmware for a robotic vacuum cleaner. The firmware must read the distance sensors and control the motors. The vacuum cleaner has a small amount of memory.

Discuss the characteristics of a low-level programming language that make it suitable for writing the firmware.

Your answer should include:

  • control of the hardware
  • the efficiency of the code
  • the link between the language and the processor.
[6 marks]
Mark scheme

Indicative content

Control of the hardware

  • Low-level languages can read and write the contents of registers and memory addresses directly, so the firmware can take the values from the distance sensors without calling a library routine.
  • Assembly language instructions can read from and write to specific input/output ports on the vacuum cleaner's processor, so the motors can be switched on and off directly.
  • The programmer decides exactly which processor operations are carried out and in which order, which matters when the vacuum must reverse away from a step or an obstacle.
  • A low-level language puts nothing between the program and the hardware, so the programmer can control the hardware of the vacuum cleaner precisely.

Efficiency of the code

  • Assembly language code can be hand-optimised instruction by instruction, so the code that checks a sensor is as short as possible.
  • The programmer can choose which registers hold values that are used again and again, which cuts down the number of memory accesses the firmware needs.
  • A hand-written low-level program can be made compact, so it is more likely to fit in the small amount of memory the vacuum cleaner has.
  • Because each instruction does one defined job, the time taken to react to a sensor reading is predictable, which suits firmware that must not overrun.

Link between the language and the processor

  • Low-level languages are processor-specific, so the instructions used are those of the exact processor in the vacuum cleaner rather than general statements that need translating.
  • Each assembly language instruction maps to one machine code instruction, so the programmer knows precisely which processor operation will be carried out by each line of code.
  • An assembler turns each mnemonic into its machine code equivalent, so the machine code running on the vacuum cleaner's processor is exactly what the programmer wrote.
  • Code written for a different processor would have to be rewritten, which is acceptable here because the vacuum cleaner always uses the same processor.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Within Level 1, award 1 mark for a single basic point and 2 marks for two or more independent basic points; Level 2 requires the points to be linked to the vacuum cleaner; Level 3 requires both control of the hardware and efficiency of the code, and a few concise, linked sentences can reach Level 3, so extra length is not required.

Accept registers, memory addresses, input/output ports, machine code and mnemonics as ways of describing access to the hardware, and accept 'a low-level language is faster' as a basic point on its own. Do not award 'binary is a low-level language' (machine code is written in binary, but binary is not a language), or characteristics of high-level languages such as being easy to read or portable, as characteristics of a low-level language.

Example answers and how they were marked
Full marks6/6

A low-level language can read and write to registers and to input/output ports directly, so the firmware can take the distance sensor readings and switch the motors without needing library routines. It can be hand-optimised instruction by instruction, so the code that checks a sensor is short and the time it takes is predictable, and a compact program is more likely to fit in the vacuum cleaner's small memory. The language is processor-specific and each assembly instruction maps to one machine code instruction, so the programmer knows exactly which operation the vacuum's processor will carry out, and the assembled machine code is exactly what they wrote.

Why: Covers all three bullets: direct control of registers and ports applied to the sensors and motors, hand-optimised compact code with predictable timing applied to the small memory, and the one-to-one link to the processor's own instruction set. Linked and applied throughout, so Level 3.

Some marks2/6

A low-level language can control the hardware directly. It can read the sensors and control the motors. It is also faster than a high-level language, so the vacuum responds quickly. This is useful because it has little memory.

Why: Three basic, independent points: direct control of the hardware applied to the sensors and motors, faster execution, and suitability for limited memory. They are asserted without development (no registers, ports or predictable timing) and the link between the language and the processor is missing, so Level 1, two or more basic points (2).

Some marks1/6

A low-level language is written in binary, so the computer can understand it directly. It is faster than a high-level language.

Why: 'Faster than a high-level language' is a creditworthy basic point (1). 'Written in binary' is not awarded, as binary itself is not a language and the do-not-award rule applies. Only one undeveloped point with no application to the vacuum cleaner, so Level 1, single basic point (1).

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