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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 604 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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3 questions · 6 marks

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1Short recall3 marksStored Program Computers Swap Remove

The CPU contains several components.

Name three components of the CPU.

[3 marks]
Mark scheme

Award one mark for any of the following up to a maximum of three marks:

  • Control unit / CU (1)
  • Arithmetic logic unit / ALU (1)
  • Register(s) (1)
  • Clock (1)

Do not accept main memory / RAM.

Do not accept cache.

Marks can be awarded in any order.

Example answers and how they were marked
Full marks3/3

Control unit, arithmetic logic unit and registers.

Why: Names three creditworthy CPU components (control unit, ALU, registers), one mark each.

Some marks2/3

Control unit, clock and main memory.

Why: Control unit (1) and clock (1) are creditworthy; main memory is not a component of the CPU, a common misconception seen in the June 2023 question.

No marks0/3

Main memory, RAM and cache.

Why: None are CPU components named in the specification; candidates often confuse main memory with CPU components.

2Short recall1 markUnits & Conversion Swap Remove

A file has a size of 2 kibibytes.

State the number of bytes in the file.

[1 mark]
Mark scheme

Award one mark for:

  • 2048 (1)
  • 2 × 1024 (1)
  • 2^11 (1)

Allow 2048 bytes.

Do not accept 2000, which is the number of bytes in two decimal kilobytes.

Do not accept 1024, which is the number of bytes in one kibibyte.

Do not accept 16, which is the number of bits in two bytes.

Example answers and how they were marked
Full marks1/1

2048

Why: 2048 is 2 × 1024, the number of bytes in 2 kibibytes (1).

No marks0/1

2000

Why: 2000 uses the decimal kilobyte, not the binary kibibyte; the mark scheme does not accept it.

No marks0/1

16

Why: 16 is the number of bits in two bytes, confusing bits with bytes; the mark scheme does not accept it.

3Describe2 marksMemory Management Swap Remove

A user closes a program that is running on a computer.

Describe how the operating system manages the main memory that the program was using.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • The memory (that was) used by the program is freed/released/marked as free (1) so it can be allocated/reused by another program/process (1)
  • The operating system's memory allocation table/record (of memory in use) is updated (1) to show that the program's memory locations/blocks are now free/available (1)
  • The program's instructions/data are removed/overwritten in main memory (1) so the space they used is no longer reserved for that program (1)
  • The memory pages/blocks allocated to the program are returned to the list of free pages/blocks (1) that can be used when the next program is loaded (1)

For both marks, the expansion must follow/associate with the statement.

Do not award two marks for the same idea described twice (e.g. the memory is freed and added to a list of free blocks); the two marks must come from two different linked descriptions.

Do not accept responses about closing the program window, stopping/terminating the program/process, saving the file or deleting the program from secondary storage/the hard disk.

Ignore statements that main memory is 'managed'/'cleaned up' with no development.

Example answers and how they were marked
Full marks2/2

The operating system updates its memory allocation table to show that the memory locations the program was using are now free, so another program can be loaded into them.

Why: The memory allocation table/record is updated (1) linked to showing the program's memory locations are now free/available (1).

Some marks1/2

The operating system frees up the memory the program was using.

Why: The memory used by the program is freed/released (1), but there is no linked development of what this allows.

No marks0/2

The operating system deletes the program from the hard disk to free up memory.

Why: This confuses main memory with secondary storage; deleting the program from secondary storage is named in the 'Do not accept' line, so no creditworthy point is made.

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