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Edexcel GCSE Computer Science (1CP2) Exam Questions

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4 questions · 10 marks

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1Multiple choice1 markSecondary Memory Swap Remove

A company stores films on optical media.

Identify the optical storage medium that can store the most data.

[1 mark]
  • ABlu-ray Disc
  • BCD
  • CDVD
  • DMagnetic tape
Mark scheme
  • A Blu-ray Disc (1)
  • The only correct answer is A. The correct answer is Blu-ray Disc.
  • B is not correct because a CD stores less data than a Blu-ray Disc, up to about 700 MB
  • C is not correct because a DVD stores less data than a Blu-ray Disc, up to about 4.7 GB (single-layer) or 8.4 GB (dual-layer)
  • D is not correct because magnetic tape is not an optical storage medium
Example answers and how they were marked
Full marks1/1

A Blu-ray Disc

Why: Correct option (1): a Blu-ray Disc has the greatest capacity of the optical media.

No marks0/1

C DVD

Why: Near miss scoring 0: a DVD is optical but stores less than a Blu-ray Disc (mark scheme line C). Only A is credited.

No marks0/1

D Magnetic tape

Why: Misconception scoring 0: candidates pick tape for its large capacity but magnetic tape is not an optical storage medium (mark scheme line D).

2Short recall1 markSecondary Memory Swap Remove

Data is stored on optical discs as pits and lands.

Name the component in an optical disc drive that reads this data.

[1 mark]
Mark scheme

Award one mark for:

  • Laser (1)

Allow laser beam

Do not accept read/write head

Do not accept pits

Do not accept lands

Do not accept reflective surface

Do not accept magnet/magnetic

Example answers and how they were marked
Full marks1/1

Laser

Why: Laser is the creditworthy answer (1).

No marks0/1

A read/write head

Why: Read/write head is not accepted by the mark scheme; it reads magnetic media, not optical discs, so no marks are awarded.

No marks0/1

Pits and lands

Why: Pits and lands are what the laser reads, not the component that reads the data, so the mark scheme does not accept them.

3Explain2 marksEmbedded Systems Swap Remove

A greenhouse uses an embedded system to keep the plants healthy.

Explain how the embedded system controls the temperature in the greenhouse.

[2 marks]
Mark scheme

Award up to two marks for a linked explanation such as:

  • A temperature sensor measures/reads the temperature in the greenhouse (1) which the processor compares with the value stored in the system (1)
  • The heater is switched on (1) when the temperature reading goes below the value stored in the system (1)
  • A fan/vent/window is opened/a cooler is switched on (1) when the temperature reading goes above the value stored in the system (1)
  • The temperature is checked/measured continuously (1) so the heater/fan is switched on or off as soon as the temperature changes (1)

For both marks, the expansion must follow/associate with the statement.

Allow one mark for a correct point on its own without a linked reason, e.g. 'a temperature sensor measures the temperature'.

Do not award 'the embedded system controls/keeps the temperature correct' as this repeats the question.

Do not accept naming a device without saying what it does, e.g. 'the greenhouse has a thermostat'.

Example answers and how they were marked
Full marks2/2

A temperature sensor measures the temperature in the greenhouse, which the processor compares with the value stored in the system.

Why: Point (1): the input and what it measures. Reason (1): the linked statement about what the processor does with the reading.

Some marks1/2

The embedded system uses a temperature sensor that measures the temperature in the greenhouse.

Why: A correct point on its own (1); no linked statement about what the system does with the reading, so the second mark is not awarded.

No marks0/2

The embedded system controls the temperature so the plants do not get too cold.

Why: Rewords the question without saying how the temperature is measured or changed, so no mark is awarded.

4Discuss6 marksPrimary Memory Swap Remove

A school is buying new computers for its IT room. The computers the technician has ordered have 16 GB of RAM and a large hard drive.

Discuss why main memory (RAM) is needed for programs to run on these computers.

Your answer should include:

  • the role of RAM in the stored program concept
  • what happens to a program when it is opened
  • why the CPU cannot execute a program directly from secondary storage.
[6 marks]
Mark scheme

Indicative content

the role of RAM in the stored program concept

  • In the von Neumann stored program concept, a program's instructions and the data it uses are held together in main memory.
  • RAM holds the instructions and data of the program that the CPU is currently processing.
  • The CPU fetches each instruction from RAM during the fetch-decode-execute cycle, so a program must be in RAM before it can be run.
  • RAM is directly accessible by the CPU, so instructions can be fetched quickly enough for the CPU to keep working.

what happens to a program when it is opened

  • When a program is opened, a copy of its instructions and data is transferred from secondary storage, such as the hard drive, into RAM.
  • The operating system loads the program into RAM so that the CPU can start fetching and executing its instructions.
  • When the program is closed, it is removed from RAM, and the space it used is free for another program.
  • If a computer does not have enough RAM, the program may not open, or another open program has to be closed first.

why the CPU cannot execute a program directly from secondary storage

  • Secondary storage, such as a hard disk drive, is much slower to access than RAM.
  • The CPU can process instructions much faster than secondary storage can supply them, so the CPU would have to wait and would not be working at full speed.
  • RAM is fast electronic memory with no moving parts, so data can be read from it in a fraction of the time taken by a magnetic hard disk drive.
  • Running the school's programs directly from secondary storage would make the computers in the IT room very slow to use.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Additional guidance

  • Level 3 responses must cover both the role of RAM in the stored program concept and the speed difference between RAM and secondary storage, with a reason such as the CPU having to wait for instructions.
  • Answers that make only basic, independent points, such as what RAM is, that a program is copied into RAM when it is opened, or that RAM is faster than a hard drive, without linking them to explain why the CPU would have to wait for instructions, are limited to Level 1.
  • Do not accept statements that RAM is permanent storage, that RAM replaces secondary storage, or that secondary storage is read-only.
Example answers and how they were marked
Full marks6/6

The computers need RAM because of the von Neumann stored program concept, in which the instructions of a program and the data it uses are both held in main memory. When a student opens a program on one of the new computers, the operating system copies it from the hard drive into RAM. The CPU then fetches each instruction from RAM in the fetch-decode-execute cycle, so the program must be in RAM before it can be run. The CPU cannot execute a program directly from secondary storage because a hard disk drive is much slower than RAM. It has moving parts and a much lower transfer rate, so the CPU would often have nothing to do while it waited for the next instruction. RAM is fast electronic memory that the CPU can read directly, which is why 16 GB of RAM lets the school run several programs at once and still keep the CPU working at full speed.

Why: Comprehensive understanding: the stored program concept is explained (instructions and data held in main memory), the program being opened is linked to it, and the speed difference is developed with the reason that the CPU would wait for instructions, all applied to the school's computers. Level 3.

Some marks2/6

RAM is the main memory of the computer. It stores the programs and data that are being used at the moment. When you open a program it is copied into RAM, and the CPU fetches instructions from RAM. RAM is faster than the hard drive, so a program runs better from RAM. Having 16 GB means the school can have more programs open at once.

Why: Basic, independent points only: what RAM is, that a program is copied into RAM when it is opened, that the CPU fetches instructions from RAM, and that RAM is faster than a hard drive. None is linked to the stored program concept or developed to explain why the CPU would have to wait for instructions, so Level 1, 2 marks.

No marks0/6

RAM is the permanent storage inside the computer, like a hard drive. The school needs 16 GB of RAM so that all the students' files can be saved permanently. When a program is opened, it is copied from RAM to the CPU. The CPU cannot execute from secondary storage because secondary storage is read-only.

Why: No creditworthy points. RAM is described as permanent storage, files are said to be saved permanently in RAM, a program is said to be copied from RAM to the CPU, and secondary storage is said to be read-only. All are the misconceptions listed in the Do not accept guidance, so Level 0.

Questions by topic

2.1 Binary

Build a paper on this topic 58
Adding Binary Numbers 6 questions Binary and Hexadecimal Basics 10 questions Binary Shifts 6 questions Binary to Denary Conversion 6 questions Binary to Hexadecimal Conversion 6 questions Denary to Binary Conversion 6 questions Denary to Hexadecimal Conversion 6 questions Denary to Negative Binary Conversion 6 questions Hexadecimal to Binary Conversion 6 questions

2.2 Data representation

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Character Sets 18 questions Images 19 questions Sound 19 questions

2.3 Data storage and compression

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Compression 18 questions Units & Conversion 6 questions

3.1 Hardware

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Embedded Systems 17 questions Fetch Decode Execute Cycle 15 questions Primary Memory 15 questions Secondary Memory 15 questions Stored Program Computers 15 questions

3.2 Software

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File Management 18 questions Memory Management 16 questions Peripheral Management 11 questions Process Management 12 questions Purpose & Function of Operating Systems 17 questions Software Basics 13 questions User Management 18 questions Utility Software 19 questions

3.3 Programming languages

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Low and High Level Languages 19 questions Translators 18 questions

4.1 Networks

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Addressing 16 questions LANs & WANs 16 questions Network Speed 5 questions Packet Switching 16 questions Protocols & Layers 17 questions The Internet 16 questions Topologies 17 questions Wired Connections 17 questions Wireless Connections 18 questions

4.2 Network security

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Network Security Risks 18 questions Preventing Network Security Risks 18 questions

5.1 Environmental

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E-waste 17 questions Manufacturing Technology 19 questions

5.2 Ethical and legal

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Data Protection Act 17 questions Impact of AI 18 questions Intellectual Property 18 questions Software Licences 18 questions

5.3 Cybersecurity

Build a paper on this topic 30
Malware 18 questions Social Engineering 12 questions

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