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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 693 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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4 questions · 11 marks

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1Multiple choice1 markSecondary Memory Swap Remove

A company stores films on optical media.

Identify the optical storage medium that can store the most data.

[1 mark]
  • ABlu-ray Disc
  • BCD
  • CDVD
  • DMagnetic tape
Mark scheme
  • A Blu-ray Disc (1)
  • The only correct answer is A. The correct answer is Blu-ray Disc.
  • B is not correct because a CD stores less data than a Blu-ray Disc, up to about 700 MB
  • C is not correct because a DVD stores less data than a Blu-ray Disc, up to about 4.7 GB (single-layer) or 8.4 GB (dual-layer)
  • D is not correct because magnetic tape is not an optical storage medium
Example answers and how they were marked
Full marks1/1

A Blu-ray Disc

Why: Correct option (1): a Blu-ray Disc has the greatest capacity of the optical media.

No marks0/1

C DVD

Why: Near miss scoring 0: a DVD is optical but stores less than a Blu-ray Disc (mark scheme line C). Only A is credited.

No marks0/1

D Magnetic tape

Why: Misconception scoring 0: candidates pick tape for its large capacity but magnetic tape is not an optical storage medium (mark scheme line D).

2Describe2 marksSecondary Memory Swap Remove

Computers use secondary storage.

Describe the role of secondary storage.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • Stores programs (including the operating system) and data that are not currently in use (1) so that they can be loaded into RAM/main memory when needed (1)
  • Keeps files/programs/data when the power is turned off (1) which happens because it is non-volatile (1)
  • Stores files/data for backup or archiving (1) so that they can be recovered if the originals are lost/corrupted (1)

A correct role on its own earns one mark; the second mark requires a linked development.

Accept either order if both the role and the link are given.

Do not accept 'it is non-volatile' on its own, unless it is linked to keeping data when the power is turned off.

Do not accept answers that only name a storage type (magnetic, optical, solid state) without describing a role.

Do not accept responses that describe primary storage/RAM, e.g. storing the data/instructions the CPU is currently working on, or that secondary storage makes the computer run faster.

Example answers and how they were marked
Full marks2/2

Secondary storage stores programs and data that are not currently in use so that they can be loaded into RAM when they are needed.

Why: Role point (1) linked to loading into RAM when needed (1).

Some marks1/2

It stores files and programs that are not currently in use.

Why: Correct role on its own earns one mark (1); no linked development, so the second mark is not awarded.

No marks0/2

It holds the data and instructions the CPU is working on so the computer runs faster.

Why: Describes primary storage/RAM and a speed benefit, which the mark scheme does not accept; no role of secondary storage is given.

3Explain2 marksSecondary Memory Swap Remove

A hard disk drive stores data on a spinning magnetic platter.

Explain how data is read from a magnetic hard disk.

[2 marks]
Mark scheme

Award up to two marks for a linked explanation such as:

  • The read/write head moves over the surface of the platter (1) and detects whether each area of the disk is magnetised (1)
  • The platter spins/rotates (1) so the read/write head can pass over the whole surface/tracks of the disk (1)
  • The pattern of magnetised and non-magnetised areas detected by the read/write head (1) is read as binary 1s and 0s (1)
  • The drive head detects the direction of magnetisation of each area (1) so the data can be read as binary (1)

For both marks, the expansion must follow/associate with the statement.

Allow one mark for stating that data is read magnetically / that the read/write head detects the magnetisation of the disk without a linked reason.

Do not accept answers that describe how data is written to the disk, such as the head magnetising the platter, rather than how it is read.

Do not accept 'a laser reads the pits and lands' - this describes optical storage, not magnetic storage.

Example answers and how they were marked
Full marks2/2

The platter rotates so the read/write head passes over the whole surface of the disk and it detects whether each area is magnetised or not. The pattern of magnetised areas is then read as 1s and 0s.

Why: Linked point (1) rotation of the platter with reason (1) the head reaches the whole surface, and the second line about magnetised areas is also present.

Some marks1/2

The read/write head detects the magnetic charges on the disk.

Why: Allow line (1): states the head detects the magnetisation of the disk, but gives no linked reason (e.g. the platter rotating so the head covers the whole surface), so only one mark.

No marks0/2

A laser shines onto the disk and reads the pits and lands, then the data is sent to the CPU.

Why: Describes optical storage. Do not accept 'a laser reads the pits and lands' - a magnetic disk is read by a head detecting magnetisation.

4Discuss6 marksStored Program Computers Swap Remove

A school is buying new desktop computers for its computer science classroom. The teacher explains that each computer uses the von Neumann stored program concept: the program instructions and the data are stored together in main memory, and the CPU runs each instruction by carrying out the fetch-decode-execute cycle.

Discuss the role of the control unit, the arithmetic logic unit (ALU) and registers in the fetch-decode-execute cycle.

Your answer should include:

  • how an instruction is fetched from main memory and decoded
  • how the ALU executes an instruction
  • how registers are used during the cycle.
[6 marks]
Mark scheme

Indicative content

Fetching and decoding an instruction

  • The register that holds the address of the next instruction (the program counter) contains the address of the instruction to be fetched.
  • This address is sent to main memory (RAM) and the instruction is copied from main memory into a register inside the CPU.
  • The program counter is updated so that it holds the address of the next instruction in the program.
  • The control unit decodes the instruction that has been fetched, working out which operation is required and which data or registers are needed.
  • The control unit sends control signals to coordinate the other components as the instruction is carried out.
  • The control unit decides what happens next, for example after a comparison it decides whether the next instruction is the following one or a jump.

The arithmetic logic unit (ALU) executes an instruction

  • The control unit directs the arithmetic logic unit (ALU) to carry out the operation.
  • The ALU performs arithmetic operations such as addition, subtraction, multiplication and division, for example adding two values in a program written by the class.
  • The ALU performs logical operations such as comparing two values to see if they are equal or whether one is greater than the other.
  • The result of the operation carried out by the ALU is passed back and stored in a register.
  • The ALU operates on data that has been fetched from main memory; it does not fetch the instruction and it does not decide which instruction is next.

Registers

  • Registers are small, very fast memory locations inside the CPU.
  • They hold the data, addresses and results that the CPU is working on during the cycle.
  • Registers are used in every stage of the cycle, not only when the ALU produces a result.
  • Because registers are inside the CPU they can be read and written much faster than main memory during the cycle.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)
  • A Level 3 answer must link the roles of all three components to the fetch, decode and execute stages. An answer that links only one component to a stage, with the other points listed separately, is Level 1 (1–2 marks); an answer that links two of the components to stages is Level 2 (3–4 marks). A point repeated under more than one heading is credited once only.
  • Accept 'the program counter', 'the address register' or 'a register holding the address of the next instruction' as the register that holds the address of the next instruction. Do not accept 'the control unit performs the calculations', 'the ALU controls the timing of the CPU' / 'the ALU sends the clock signal' or 'registers are in main memory (RAM)'.
Example answers and how they were marked
Full marks6/6

In the fetch stage, a register called the program counter holds the address of the next instruction and this address is sent to main memory. The instruction is copied from main memory into a register in the CPU and the program counter is updated so that it points to the next instruction. The control unit then decodes the instruction in the decode stage, working out which operation is required and which data or registers are needed, and it sends control signals to coordinate the other components. In the execute stage the control unit directs the ALU to carry out the operation the class's program needs: the ALU does arithmetic, such as adding two values, or a logical comparison, such as checking whether one value is greater than another, and it does not decide what happens next, the control unit does. The result from the ALU is stored in a register, and because registers hold the data, addresses and results at every stage, the cycle can repeat with the next instruction.

Why: Level 3: the role of each component is linked to the stage it works in (program counter and registers in fetch, control unit decoding and deciding next, ALU executing and its result stored in a register) across all three stages, with the classroom context.

Some marks2/6

The control unit decodes the instruction in the decode stage. The ALU does maths and logic, such as addition and comparing numbers. Registers store data inside the CPU. In the fetch stage the instruction is fetched from the RAM and put into the CPU.

Why: Level 1: several correct basic points that the mark scheme credits (the instruction is fetched from main memory into the CPU, the control unit decodes the instruction, the ALU does arithmetic and logical operations, registers store data) but only the control unit is linked to a stage of the cycle, so the answer is top of Level 1.

Some marks1/6

The control unit decodes instructions. The ALU controls the timing of the CPU and sends the clock signal. Registers are in the RAM and they store the program.

Why: Level 1: one basic point, that the control unit decodes instructions (1). The other statements are on the do-not-accept list (the ALU does not control the timing of the CPU or send the clock signal, and registers are in the CPU, not main memory), so they earn no credit.

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