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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 604 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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3 questions · 4 marks

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1Multiple choice1 markSecondary Memory Swap Remove

A computer has both primary and secondary storage.

Identify the role of secondary storage.

[1 mark]
  • ATo store data and programs permanently
  • BTo store data and instructions currently in use
  • CTo carry out calculations on data
  • DTo allow the CPU to access programs directly
Mark scheme
  • A To store data and programs permanently (1)
  • The only correct answer is A. The correct answer is to store data and programs permanently.
  • B is not correct because storing the data and instructions currently in use is the role of primary storage/RAM, which is volatile, not the role of secondary storage
  • C is not correct because calculations on data are carried out by the CPU, not by secondary storage
  • D is not correct because secondary storage is not directly accessible by the CPU; data must first be copied into RAM
Example answers and how they were marked
Full marks1/1

A To store data and programs permanently

Why: Correct option (1): storing data and programs permanently is the role of secondary storage, which is non-volatile.

No marks0/1

B To store data and instructions currently in use

Why: Near miss scoring 0: this describes primary storage/RAM, which is volatile, and is not the role of secondary storage (line B of the mark scheme). Only A is credited.

No marks0/1

D To allow the CPU to access programs directly

Why: Misconception scoring 0: candidates think the CPU reads programs straight from secondary storage, but secondary storage is not directly accessible by the CPU (line D).

2Multiple choice1 markCharacter Sets Swap Remove

ASCII is a character set used for representing text.

Identify the number of bits used to encode each character in ASCII.

[1 mark]
  • A6
  • B7
  • C8
  • D16
Mark scheme
  • B 7 (1)
  • The only correct answer is B. The correct answer is 7 bits.
  • A is not correct because 6 bits give only 64 different characters
  • C is not correct because 8 bits are used by extended ASCII to give 256 characters
  • D is not correct because 16 bits give 65 536 different characters, which is far more than the 128 in ASCII
Example answers and how they were marked
Full marks1/1

B 7

Why: B is the only correct answer: each ASCII character is encoded using 7 bits (1).

No marks0/1

C 8

Why: Near miss scoring 0: 8 bits is extended ASCII, and the scheme's C line says extended ASCII, not ASCII, is not the answer.

No marks0/1

A 6

Why: Misconception scoring 0: 6 bits give only 64 different characters, so it cannot be ASCII.

3Short recall2 marksUnits & Conversion Swap Remove

Data storage is measured in binary multiples.

Define the term bit.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • A binary digit (1)
  • Has the value 0 or 1 (1)
  • The smallest unit of data storage (1)
  • A single 0 or 1 (1)

Allow binary digit/binary place value for binary digit

Allow a single binary digit for a single 0 or 1

Do not accept a group of 8 bits/half a nibble of 4 bits, which describe a byte or a nibble

Do not accept a binary number/binary on its own

Example answers and how they were marked
Full marks2/2

A binary digit that can have the value 0 or 1.

Why: A binary digit (1) and has the value 0 or 1 (1).

Some marks1/2

It is the smallest unit of data storage.

Why: Smallest unit of data storage (1), but does not state that it is a binary digit or that it has the value 0 or 1.

No marks0/2

A group of 8 bits.

Why: Describes a byte, not a bit; no creditworthy point and named in the Do not accept line.

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