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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 693 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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3 questions · 4 marks

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1Multiple choice1 markSecondary Memory Swap Remove

A computer has both primary and secondary storage.

Identify the role of secondary storage.

[1 mark]
  • ATo store data and programs permanently
  • BTo store data and instructions currently in use
  • CTo carry out calculations on data
  • DTo allow the CPU to access programs directly
Mark scheme
  • A To store data and programs permanently (1)
  • The only correct answer is A. The correct answer is to store data and programs permanently.
  • B is not correct because storing the data and instructions currently in use is the role of primary storage/RAM, which is volatile, not the role of secondary storage
  • C is not correct because calculations on data are carried out by the CPU, not by secondary storage
  • D is not correct because secondary storage is not directly accessible by the CPU; data must first be copied into RAM
Example answers and how they were marked
Full marks1/1

A To store data and programs permanently

Why: Correct option (1): storing data and programs permanently is the role of secondary storage, which is non-volatile.

No marks0/1

B To store data and instructions currently in use

Why: Near miss scoring 0: this describes primary storage/RAM, which is volatile, and is not the role of secondary storage (line B of the mark scheme). Only A is credited.

No marks0/1

D To allow the CPU to access programs directly

Why: Misconception scoring 0: candidates think the CPU reads programs straight from secondary storage, but secondary storage is not directly accessible by the CPU (line D).

2Short recall1 markPrimary Memory Swap Remove

Computers use RAM to store the data and instructions that are in use.

Name the term used to describe memory that loses its contents when the power is switched off.

[1 mark]
Mark scheme

Award one mark for:

  • Volatile (1)

Allow volatile memory / it is volatile.

Do not accept non-volatile, ROM, RAM or temporary/short term memory on their own, as these are not the term asked for.

Example answers and how they were marked
Full marks1/1

Volatile

Why: Correct term for memory that loses its contents when the power is switched off (1).

No marks0/1

Temporary memory

Why: Describes what such memory does but is not the term asked for; 'temporary memory' is on the Do not accept line, so no mark.

No marks0/1

Non-volatile

Why: Non-volatile memory keeps its contents when the power is switched off, the opposite of what the question describes; it is explicitly not accepted.

3Describe2 marksFetch Decode Execute Cycle Swap Remove

The control unit is one component of the CPU.

Describe the role of the control unit in the fetch-decode-execute cycle.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • Decodes instructions (1) to determine what action/operation is required (1)
  • Sends control signals (1) along the control bus to coordinate/control the actions of other components (1)
  • Controls the fetch stage (1) by causing the next instruction to be fetched from main memory/RAM (1)
  • Controls the execute stage (1) by telling the ALU/other components when to carry out the required operation (1)

Do not accept responses relating to how the control unit affects performance, such as increasing clock speed.

Do not accept responses that describe the role of the ALU, registers or clock instead of the control unit.

Do not accept responses about the ALU performing calculations unless the control unit controlling the ALU is also stated.

Example answers and how they were marked
Full marks2/2

The control unit decodes instructions to determine what action is required.

Why: Linked point (1) and development (1): decodes instructions and determines the required action.

Some marks1/2

The control unit controls the fetch stage of the cycle.

Why: Point only (1): controls the fetch stage, but no linked development.

No marks0/2

The control unit carries out arithmetic and logical operations on data.

Why: No creditworthy point: describes the role of the ALU, which the mark scheme rejects.

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