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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 604 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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3 questions · 6 marks

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1Multiple choice1 markSecondary Memory Swap Remove

A computer has both primary and secondary storage.

Identify the role of secondary storage.

[1 mark]
  • ATo store data and programs permanently
  • BTo store data and instructions currently in use
  • CTo carry out calculations on data
  • DTo allow the CPU to access programs directly
Mark scheme
  • A To store data and programs permanently (1)
  • The only correct answer is A. The correct answer is to store data and programs permanently.
  • B is not correct because storing the data and instructions currently in use is the role of primary storage/RAM, which is volatile, not the role of secondary storage
  • C is not correct because calculations on data are carried out by the CPU, not by secondary storage
  • D is not correct because secondary storage is not directly accessible by the CPU; data must first be copied into RAM
Example answers and how they were marked
Full marks1/1

A To store data and programs permanently

Why: Correct option (1): storing data and programs permanently is the role of secondary storage, which is non-volatile.

No marks0/1

B To store data and instructions currently in use

Why: Near miss scoring 0: this describes primary storage/RAM, which is volatile, and is not the role of secondary storage (line B of the mark scheme). Only A is credited.

No marks0/1

D To allow the CPU to access programs directly

Why: Misconception scoring 0: candidates think the CPU reads programs straight from secondary storage, but secondary storage is not directly accessible by the CPU (line D).

2Short recall2 marksUnits & Conversion Swap Remove

A solid state drive has a capacity of 5 gibibytes.

Give an expression to calculate the number of bits in 5 gibibytes. You do not need to do the calculation.

[2 marks]
Mark scheme

Award one mark for each of:

  • 5 × 1024^3 / 5 × 1024 × 1024 × 1024 / 5 × 2^30, for the number of bytes (1)
  • A fully correct expression with × 8 to convert bytes to bits, in any order, e.g. 5 × 1024^3 × 8, 8 × 5 × 2^30 (1)

Accept 5 × 1 073 741 824 × 8.

Accept 5 × 2^33 or 42 949 672 960 as a fully correct expression (2 marks).

Do not accept 5 × 1000^3 × 8, which uses decimal multiples.

Do not accept ÷ 8, which converts bits to bytes.

Example answers and how they were marked
Full marks2/2

8 × 5 × 2^30

Why: 5 × 2^30 is the number of bytes (1) and × 8 converts bytes to bits (1).

Some marks1/2

5 × 2^30

Why: Correct number of bytes using the binary multiple 2^30 (1), but no conversion to bits.

No marks0/2

5 × 1000^3 × 8

Why: Uses decimal 1000^3 instead of binary 1024^3, so the expression is not fully correct; no creditworthy point.

3Calculate3 marksAdding Binary Numbers Swap Remove

Binary patterns can represent numbers.

(a)

Complete the table to show the 8-bit result of the binary addition.

[2 marks]
1286432168421
11011011
11011100
Mark scheme

Award one mark for each correct nibble in the correct order:

  • 1011 (1)
  • 0111 (1)

0 marks if the response is not 8-bit binary.

Ignore a carry shown beyond the eighth bit.

Example answers and how they were marked
Full marks2/2

1011 0111

Why: 219 + 220 = 439, which needs 9 bits; the 8 bits that are kept are both correct (2).

Some marks1/2

0000 0111

Why: Forgets to carry the 1s. The second nibble is correct (1); the first is not.

No marks0/2

1101 1111

Why: Never carries. Neither nibble is correct.

(b)

State the name of the error that occurs when this addition is carried out.

[1 mark]
Mark scheme

Award one mark for:

  • overflow (error) (1)
Example answers and how they were marked
Full marks1/1

Overflow

Why: The result needs more bits than are available (1).

No marks0/1

Underflow

Why: A near miss: the result is too big for 8 bits, not too small.

No marks0/1

A syntax error

Why: A syntax error is a mistake in a program's code, not in arithmetic.

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