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Edexcel GCSE Computer Science (1CP2) Exam Questions

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4 questions · 16 marks

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1Short recall2 marksSecondary Memory Swap Remove

A computer uses secondary storage to keep programs and data.

Give two examples of secondary storage devices that store data using magnetic media.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • Hard disk drive/HDD (1)
  • External/portable hard disk drive (1)
  • Magnetic tape drive (1)
  • Magnetic tape (1)

Allow a named device or the storage media type, e.g. hard disk/hard disc for hard disk drive, tape for magnetic tape

Allow floppy disk/floppy disk drive

Do not accept solid state devices (SSD, USB flash drive/memory stick, SD card/memory card) or optical media (CD/DVD/Blu-ray) as these do not store data using magnetism

Example answers and how they were marked
Full marks2/2

Hard disk drive and magnetic tape

Why: Hard disk drive (1) and magnetic tape (1) are both magnetic secondary storage, so both marks are awarded.

Some marks1/2

Hard disk drive and SD card

Why: Hard disk drive is magnetic (1); an SD card is solid state, not magnetic, so the second mark is not awarded.

No marks0/2

CD and DVD

Why: Both are optical media, which the mark scheme says not to accept, so no marks are awarded.

2Describe2 marksStored Program Computers Swap Remove

A computer is based on the von Neumann stored program concept.

Describe how the CPU uses main memory (RAM) during the fetch-decode-execute cycle.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • The program's instructions (and the data it uses) are held in main memory/RAM (1) so the CPU fetches both the instructions and the data from that one memory (1)
  • The CPU fetches the next instruction from main memory/RAM (1) using the address of the memory location that holds it (1)
  • The CPU reads/fetches data from main memory/RAM (1) when an instruction needs it and writes the result back to main memory/RAM (1)
  • The program's instructions are held in main memory/RAM while the program runs (1) and the CPU fetches them one at a time/one after another to be decoded and executed (1)

Allow 'memory' for main memory/RAM.

Allow 'gets' for fetches/reads.

For both marks, the development must say what the CPU does with the contents of main memory (fetches/reads/writes), not just that main memory is used.

Do not accept answers about the program being stored in secondary storage, such as on a hard drive, or about it being loaded from there.

Do not accept benefits such as the computer running faster or being easier for the user.

Do not accept naming CPU components (control unit, arithmetic logic unit, registers) or buses on their own, without saying what is stored or fetched.

Do not accept 'the computer stores data' on its own, without a link to the instructions of a program.

Example answers and how they were marked
Full marks2/2

The program's instructions and the data it uses are both held in the same main memory (RAM), so the CPU can fetch the instructions and the data it needs from that one memory.

Why: Linked point (1) that instructions and data are stored together in main memory, with the development (1) that the CPU fetches both from the same memory.

Some marks1/2

The CPU fetches the instructions from main memory so that they are processed more quickly.

Why: The first point earns (1) for the CPU fetching instructions from main memory. The second statement is a benefit (speed), which the 'Do not accept benefits' line rules out, so it earns nothing.

No marks0/2

The control unit decodes each instruction and the ALU carries out the calculations.

Why: Both statements name CPU components without saying what is stored, fetched or written, which the mark scheme tells examiners not to accept, so neither earns a mark.

3Discuss6 marksSecondary Memory Swap Remove

An independent film studio sells its films on discs. It also offers the same films as downloads. The studio is deciding whether to keep selling films on optical discs.

Discuss the use of optical storage for selling films.

Your answer should include:

  • how data is stored on optical media
  • the benefits of optical discs for selling films
  • the drawbacks of optical discs for selling films.

You do not need to consider other types of secondary storage.

[6 marks]
Mark scheme

Indicative content

How data is stored on optical media

  • Data is stored as pits and lands burnt or pressed into a spiral track on the disc.
  • A laser beam is shone at the disc and the light that is reflected back is measured; pits and lands reflect the light differently.
  • The differences in the reflected light are read as binary 1s and 0s.

Benefits of optical discs for selling films

  • Optical discs are cheap to mass produce once the master disc has been pressed, so the studio can sell each film at a low price.
  • A disc is small and light, so a customer can easily store it, carry it home or give it as a gift.
  • A Blu-ray disc can hold a whole high-definition film (up to 50 GB), so a customer can watch the film without an internet connection.
  • Artwork can be printed on the disc and its case, which helps the studio sell the film.

Drawbacks of optical discs for selling films

  • A DVD holds only about 8.4 GB, so a high-definition film with extra features may not fit on one and the studio would need to sell it on a Blu-ray instead.
  • Optical discs are easily scratched, which can cause read errors so the film will not play.
  • Many modern devices, such as some laptops, no longer have a disc drive, so some customers would not be able to play the film.
  • Discs can be affected by heat and sunlight, so they may deteriorate over time.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Additional guidance

  • Level 2 requires points to be linked or developed, for example a benefit or drawback explained in terms of the studio or its customers. An answer that only lists basic, independent points, with no linkage, is limited to Level 1.
  • Level 3 requires all three areas and a judgement about whether the studio should keep selling films on optical discs. Do not credit magnetic storage or solid state storage as a description of how optical media stores data; credit these only where they are compared with optical media.
Example answers and how they were marked
Full marks6/6

Optical media stores data as pits and lands burnt into a spiral track. A laser beam is shone at the disc and the reflected light is measured; pits and lands reflect it differently, and this pattern is read as binary 1s and 0s. Optical discs are cheap to mass produce, so the studio can sell each film at a low price, and a disc is small and light so a customer can store it or give it as a gift. A Blu-ray holds a whole high-definition film and can be played without an internet connection. However, a DVD may not hold a high-definition film with extra features, so the studio would need a Blu-ray, and discs are easily scratched, which can cause read errors so the film will not play. Many modern laptops have no disc drive, so some customers could not play the film. Overall the studio should keep selling discs as well as downloads, because the discs are cheap to produce and give customers a copy that works without an internet connection, even though some customers will prefer to download.

Why: Explains how data is stored on optical media using pits, lands, reflected light and binary (AO1); gives benefits applied to selling films (cheap mass production, portability, Blu-ray holds a film and plays offline) and drawbacks (DVD capacity, scratches causing read errors, no disc drive in modern laptops); ends with a sustained judgement and recommendation, so it meets the Level 3 guidance.

Some marks2/6

Optical storage uses a laser to read pits and lands. It is cheap to make discs, so the studio can sell them cheaply. Discs are portable. But they can be scratched and damaged. Some computers don't have a disc drive.

Why: Basic point about how data is stored, a laser reading pits and lands (1), plus basic points about benefits (cheap to produce, portable) and drawbacks (scratched, no disc drive), but the points are independent and undeveloped with no linkage or application to the studio, so it is the top of Level 1: 2 marks.

No marks0/6

Optical storage uses magnets to store data. The film studio should use optical discs because they are very fast and have a large capacity. They are not affected by scratches.

Why: No creditworthy points. Confuses optical storage with magnetic storage; claims it is fast, has a large capacity and is not affected by scratches, all of which are incorrect. Level 0.

4Discuss6 marksStored Program Computers Swap Remove

A school is buying new desktop computers for its computer science classroom. The teacher explains that each computer uses the von Neumann stored program concept: the program instructions and the data are stored together in main memory, and the CPU runs each instruction by carrying out the fetch-decode-execute cycle.

Discuss the role of the control unit, the arithmetic logic unit (ALU) and registers in the fetch-decode-execute cycle.

Your answer should include:

  • how an instruction is fetched from main memory and decoded
  • how the ALU executes an instruction
  • how registers are used during the cycle.
[6 marks]
Mark scheme

Indicative content

Fetching and decoding an instruction

  • The register that holds the address of the next instruction (the program counter) contains the address of the instruction to be fetched.
  • This address is sent to main memory (RAM) and the instruction is copied from main memory into a register inside the CPU.
  • The program counter is updated so that it holds the address of the next instruction in the program.
  • The control unit decodes the instruction that has been fetched, working out which operation is required and which data or registers are needed.
  • The control unit sends control signals to coordinate the other components as the instruction is carried out.
  • The control unit decides what happens next, for example after a comparison it decides whether the next instruction is the following one or a jump.

The arithmetic logic unit (ALU) executes an instruction

  • The control unit directs the arithmetic logic unit (ALU) to carry out the operation.
  • The ALU performs arithmetic operations such as addition, subtraction, multiplication and division, for example adding two values in a program written by the class.
  • The ALU performs logical operations such as comparing two values to see if they are equal or whether one is greater than the other.
  • The result of the operation carried out by the ALU is passed back and stored in a register.
  • The ALU operates on data that has been fetched from main memory; it does not fetch the instruction and it does not decide which instruction is next.

Registers

  • Registers are small, very fast memory locations inside the CPU.
  • They hold the data, addresses and results that the CPU is working on during the cycle.
  • Registers are used in every stage of the cycle, not only when the ALU produces a result.
  • Because registers are inside the CPU they can be read and written much faster than main memory during the cycle.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)
  • A Level 3 answer must link the roles of all three components to the fetch, decode and execute stages. An answer that links only one component to a stage, with the other points listed separately, is Level 1 (1–2 marks); an answer that links two of the components to stages is Level 2 (3–4 marks). A point repeated under more than one heading is credited once only.
  • Accept 'the program counter', 'the address register' or 'a register holding the address of the next instruction' as the register that holds the address of the next instruction. Do not accept 'the control unit performs the calculations', 'the ALU controls the timing of the CPU' / 'the ALU sends the clock signal' or 'registers are in main memory (RAM)'.
Example answers and how they were marked
Full marks6/6

In the fetch stage, a register called the program counter holds the address of the next instruction and this address is sent to main memory. The instruction is copied from main memory into a register in the CPU and the program counter is updated so that it points to the next instruction. The control unit then decodes the instruction in the decode stage, working out which operation is required and which data or registers are needed, and it sends control signals to coordinate the other components. In the execute stage the control unit directs the ALU to carry out the operation the class's program needs: the ALU does arithmetic, such as adding two values, or a logical comparison, such as checking whether one value is greater than another, and it does not decide what happens next, the control unit does. The result from the ALU is stored in a register, and because registers hold the data, addresses and results at every stage, the cycle can repeat with the next instruction.

Why: Level 3: the role of each component is linked to the stage it works in (program counter and registers in fetch, control unit decoding and deciding next, ALU executing and its result stored in a register) across all three stages, with the classroom context.

Some marks2/6

The control unit decodes the instruction in the decode stage. The ALU does maths and logic, such as addition and comparing numbers. Registers store data inside the CPU. In the fetch stage the instruction is fetched from the RAM and put into the CPU.

Why: Level 1: several correct basic points that the mark scheme credits (the instruction is fetched from main memory into the CPU, the control unit decodes the instruction, the ALU does arithmetic and logical operations, registers store data) but only the control unit is linked to a stage of the cycle, so the answer is top of Level 1.

Some marks1/6

The control unit decodes instructions. The ALU controls the timing of the CPU and sends the clock signal. Registers are in the RAM and they store the program.

Why: Level 1: one basic point, that the control unit decodes instructions (1). The other statements are on the do-not-accept list (the ALU does not control the timing of the CPU or send the clock signal, and registers are in the CPU, not main memory), so they earn no credit.

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