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Edexcel GCSE Computer Science (1CP2) Exam Questions

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4 questions · 16 marks

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1Short recall2 marksSecondary Memory Swap Remove

A computer uses secondary storage to keep programs and data.

Give two examples of secondary storage devices that store data using magnetic media.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • Hard disk drive/HDD (1)
  • External/portable hard disk drive (1)
  • Magnetic tape drive (1)
  • Magnetic tape (1)

Allow a named device or the storage media type, e.g. hard disk/hard disc for hard disk drive, tape for magnetic tape

Allow floppy disk/floppy disk drive

Do not accept solid state devices (SSD, USB flash drive/memory stick, SD card/memory card) or optical media (CD/DVD/Blu-ray) as these do not store data using magnetism

Example answers and how they were marked
Full marks2/2

Hard disk drive and magnetic tape

Why: Hard disk drive (1) and magnetic tape (1) are both magnetic secondary storage, so both marks are awarded.

Some marks1/2

Hard disk drive and SD card

Why: Hard disk drive is magnetic (1); an SD card is solid state, not magnetic, so the second mark is not awarded.

No marks0/2

CD and DVD

Why: Both are optical media, which the mark scheme says not to accept, so no marks are awarded.

2Explain2 marksEmbedded Systems Swap Remove

An engine control unit (ECU) in a car is an embedded system.

Explain one benefit of using an embedded system for the engine control unit instead of a general purpose computer.

[2 marks]
Mark scheme

Award up to two marks for a linked explanation such as:

  • (The ECU) is more reliable/less likely to crash (1) because it only runs the one program/has a single purpose (1)
  • (The ECU) cannot be affected by other software/viruses (1) because it cannot run other software/it can only run the program it was made for (1)
  • (The ECU) is cheaper (1) because it has limited processing resources/less memory/simple components (1)
  • (The ECU) uses less power (1) because it has limited processing resources/a simpler processor (1)
  • (The ECU) is smaller (1) because it has fewer components/less memory than a general purpose computer (1)

For both marks, the expansion must follow/associate with the statement.

A suitable benefit stated on its own earns one mark.

Do not accept a description or a location given as the reason, e.g. 'because it is part of the car', 'because it is inside the engine', 'because it is embedded'.

Do not accept a description of an embedded system on its own as the benefit, e.g. 'it does one specific job' or 'it is part of the car'.

Do not accept 'it is faster'/'it has a more powerful processor' as embedded systems have limited processing resources.

Example answers and how they were marked
Full marks2/2

It is more reliable than a general purpose computer because it only runs the one program so it will not crash and stop the engine working.

Why: Benefit stated (1) with a linked reason (1); the reason shows why only running one program makes it reliable.

Some marks1/2

It is more reliable because it is part of the car's engine.

Why: Only the benefit earns a mark (1); being part of the car is a location, not a linked reason why it is reliable.

No marks0/2

It is faster than a general purpose computer because it is embedded in the engine.

Why: Misconception that an embedded system is faster; embedded systems have limited processing resources, so neither point nor reason is creditworthy.

3Discuss6 marksFetch Decode Execute Cycle Swap Remove

A school is upgrading the desktop computers in its computer science classroom. Each computer has a CPU, main memory and buses. The technician is explaining how the CPU uses these components during the fetch-decode-execute cycle.

Discuss how the CPU uses its components and the buses during the fetch-decode-execute cycle.

Your answer should consider:

  • the role of the CPU and registers
  • the role of the address bus, data bus and control bus
  • the role of the clock.
[6 marks]
Mark scheme

Indicative content

The role of the CPU and registers

  • The control unit decodes the instruction fetched from main memory and controls the other components during the cycle.
  • The ALU carries out arithmetic and logical operations during the execute stage, such as adding two values held in registers.
  • Registers hold the data, addresses and results that the CPU is working on during the cycle.
  • The program counter holds the address of the next instruction to be fetched, so it is incremented after each fetch.
  • The memory address register holds the address of the memory location that is about to be read or written.
  • The memory data register holds the instruction or data that has been fetched from or is being written to main memory.

The role of the address bus, data bus and control bus

  • The address bus carries the address of the memory location that the CPU needs to access from the CPU to main memory.
  • The address bus is one-way, so addresses are only sent from the CPU to main memory.
  • The data bus carries instructions and data between the CPU and main memory, so it is bi-directional.
  • The width of the data bus affects how many bits can be transferred at one time.
  • The control bus carries control signals such as read and write signals, so main memory knows whether the CPU wants to read an instruction or write data.
  • The control bus carries signals from the control unit to coordinate the components during the fetch-decode-execute cycle.

The role of the clock

  • The clock sends regular pulses that synchronise the actions of the CPU and main memory.
  • Each clock pulse triggers the next step of the fetch-decode-execute cycle, so the stages happen in the correct order.
  • The clock provides a regular timing signal so that the fetch-decode-execute cycle repeats at a steady rate.
  • The clock is separate from the control bus; the control bus carries control signals, while the clock provides timing pulses.
  • Do not credit the address bus storing addresses, the data bus storing data, or the control bus controlling the computer without naming a control signal; do not credit clock speed affecting performance as a role in the cycle.
  • Level 3 responses must cover all three bullets and link them to the fetch-decode-execute cycle; Level 2 answers may identify roles but link them only partly to the cycle.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)
Example answers and how they were marked
Full marks6/6

The control unit decodes each instruction that is fetched from main memory and then controls the other components to execute it. The program counter holds the address of the next instruction, and this address is copied to the memory address register before it is sent along the address bus. The address bus carries this address from the CPU to main memory, and it is one-way. The data bus then carries the instruction back from main memory to the CPU; it is bi-directional, so it can also carry data to be written. The memory data register holds the instruction that has been fetched. The control bus carries read and write signals from the control unit, so memory knows whether the CPU wants to read an instruction or write data. During the execute stage, the ALU performs arithmetic or logical operations on data held in registers. The clock sends regular pulses that synchronise each stage, so one fetch, decode or execute step happens on each tick and the cycle repeats in the correct order.

Why: Comprehensive understanding of the CPU, registers, all three buses and the clock, with sustained application to the fetch-decode-execute cycle. Level 3.

Some marks4/6

The address bus carries the address of the next instruction from the program counter to main memory so it can be fetched. The data bus carries the instruction back to the CPU, and it is bi-directional. The control unit decodes the instruction. The clock sends pulses to keep the stages in order.

Why: Adequate understanding of some roles with some linkage to the fetch-decode-execute cycle, but the control bus, ALU and most registers are not covered. Level 2.

Some marks1/6

The data bus carries data between the CPU and RAM. The address bus stores the addresses that the CPU needs. The control bus controls the computer. The clock is the speed of the CPU.

Why: One basic, independent point (the data bus carries data) (1). The address bus does not store addresses, the control bus point names no control signal and clock speed is not a role in the cycle, so no further credit. Level 1.

4Discuss6 marksEmbedded Systems Swap Remove

A supermarket is replacing its staffed checkouts with self-service checkouts. Each checkout has a touchscreen, a barcode scanner and weighing scales. The supermarket wants the checkouts to be reliable and quick to respond.

Discuss why the supermarket should use embedded systems in its self-service checkouts rather than general-purpose computers.

Your answer should consider:

  • the characteristics of embedded systems
  • what self-service checkouts use embedded systems for
  • how embedded systems compare with general-purpose computers

You do not need to consider the cost of the materials used in the checkout.

[6 marks]
Mark scheme

Indicative content

Characteristics of embedded systems

  • An embedded system performs a single, dedicated task, so each self-service checkout is built only to scan, weigh and price items and cannot be used for any other job.
  • An embedded system has limited processing resources and storage, which is enough for the checkout to scan barcodes, weigh items and display prices.
  • An embedded system normally has a simple operating system held in ROM, so a checkout is less likely to fail while a customer is using it.
  • Embedded systems have low power consumption, so a row of checkouts can be left running all day without using much electricity.
  • Embedded systems are small and low cost per unit, so one can be built into each checkout unit and the supermarket can afford one at every till.
  • An embedded system has a limited user interface, so the checkout only shows its own screens to the customer.
  • The firmware of an embedded system is not normally changed by the customer, although a technician can update it when the supermarket changes the checkout's software.

Uses of embedded systems in the checkout

  • The checkout uses an embedded system to read the barcode scanner, so the correct price for each item is found quickly.
  • The checkout uses an embedded system to read the weighing scales, so the weight of the items can be checked against the product that was scanned.
  • The checkout uses an embedded system to control the touchscreen that shows the customer what to do and how much to pay.
  • The checkout uses an embedded system to respond quickly to each scan, because it only carries out the checkout's own tasks, which keeps the queues moving.
  • The checkout uses an embedded system so that it keeps working for long periods without being restarted, which means customers can use it without a member of staff.

Comparison with general-purpose computers

  • A general-purpose computer can run many different programs, whereas the checkout's embedded system runs one dedicated program, so it cannot be used for other jobs.
  • A general-purpose computer loads a full operating system when it starts and has other software running, so it can slow down or need restarting, whereas the checkout is not slowed down by other programs.
  • A general-purpose computer has far more processing power and memory than the checkout needs, so using one would be more expensive and would take up more space than an embedded system.
  • A general-purpose computer is designed for users to install new software, but the checkout's embedded system runs fixed firmware, so customers cannot change what the checkout does.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Level 3 responses must consider both the characteristics of embedded systems and what the checkout uses them for, and must make a comparison with a general-purpose computer. Answers that only list characteristics or checkout tasks without linking them to the checkout are limited to Level 1.

Do not accept claims that embedded systems are faster than general-purpose computers or that they can run many different programs, as embedded systems have limited processing resources and carry out a single, dedicated task.

Example answers and how they were marked
Full marks6/6

An embedded system performs a single, dedicated task, so each self-service checkout is built only to scan items, weigh them and show prices. This suits the supermarket because the checkout does one job well instead of being used for anything else. The checkout uses its embedded system to read the barcode scanner, so the correct price is found quickly, and to read the weighing scales, so the weight of the items can be checked against the product that was scanned. It also controls the touchscreen that shows the customer what to do.

Embedded systems have limited processing resources and storage, which is more than enough for these tasks. Because they use a simple operating system held in ROM, they are less likely to fail while a customer is using them, so customers do not need a member of staff. They also have low power consumption, so a row of checkouts can run all day without using much electricity, and they are small and low cost per unit, so the supermarket can afford one at every till.

A general-purpose computer, by contrast, runs many programs and loads a full operating system, so it can slow down or need restarting and it is more expensive and bigger than the checkout needs. The embedded system runs fixed firmware, so customers cannot install software on the checkout, which keeps it reliable and quick to respond, and this is why it meets the supermarket's requirements better.

Why: Comprehensive understanding with sustained lines of reasoning: characteristics (single dedicated task, limited resources, simple operating system in ROM, low power, small and low cost) and uses (scanner, scales, touchscreen) are all applied to the checkout, and each is compared with a general-purpose computer. Meets the Level 3 guidance for a 6-mark answer.

Some marks2/6

Embedded systems are small and cheap. The checkout needs to scan items and weigh them. An embedded system can do this. It is reliable. A general-purpose computer could also do it but might crash more.

Why: Basic, independent points with little linkage or application: one characteristic (small and cheap), one use (scanning and weighing) and a brief comparison (a general-purpose computer might crash more). No line of reasoning is developed, so it is Level 1, top of the band, not Level 2.

No marks0/6

Embedded systems are better than normal computers because they are faster and can run lots of different programs. The checkout needs to be fast so it should use an embedded system.

Why: Level 0. Both claims are misconceptions that the mark scheme tells examiners not to accept (embedded systems have limited processing resources and run a single, dedicated program), and the last sentence only repeats the stem's requirement for quick responses, so there is no rewardable content.

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