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Edexcel GCSE Computer Science (1CP2) Exam Questions

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4 questions · 12 marks

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1Short recall2 marksSecondary Memory Swap Remove

A computer uses secondary storage to keep programs and data.

Give two examples of secondary storage devices that store data using magnetic media.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • Hard disk drive/HDD (1)
  • External/portable hard disk drive (1)
  • Magnetic tape drive (1)
  • Magnetic tape (1)

Allow a named device or the storage media type, e.g. hard disk/hard disc for hard disk drive, tape for magnetic tape

Allow floppy disk/floppy disk drive

Do not accept solid state devices (SSD, USB flash drive/memory stick, SD card/memory card) or optical media (CD/DVD/Blu-ray) as these do not store data using magnetism

Example answers and how they were marked
Full marks2/2

Hard disk drive and magnetic tape

Why: Hard disk drive (1) and magnetic tape (1) are both magnetic secondary storage, so both marks are awarded.

Some marks1/2

Hard disk drive and SD card

Why: Hard disk drive is magnetic (1); an SD card is solid state, not magnetic, so the second mark is not awarded.

No marks0/2

CD and DVD

Why: Both are optical media, which the mark scheme says not to accept, so no marks are awarded.

2Describe2 marksSecondary Memory Swap Remove

A laptop uses a solid state drive (SSD) for secondary storage.

Describe how data is stored on a solid state drive.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • Data is stored on (flash) memory chips/cells (1) as a pattern of electrical charges (1)
  • A current/voltage forces electrons through a barrier (1) so that they are trapped (or not trapped) to hold/represent a value (1)
  • Cells with a trapped charge and cells with no trapped charge (1) represent 1s and 0s/binary (1)
  • The trapped charge remains when the power is turned off (1) so the data is not lost/it is non-volatile (1)

Do not accept responses that describe magnetic storage, e.g. magnetised platters, spinning disks or read/write heads, or optical storage, e.g. lasers, pits and lands.

Do not award a mark for 'it is solid state' or 'it has no moving parts' without a description of how the data is stored.

Do not award a mark for restating the stem, e.g. 'a laptop uses an SSD' or 'an SSD uses flash memory'.

'Data is stored as electrical charges' on its own, with no reference to memory chips/cells or to how the charge is held, earns a maximum of one mark (1).

A response that only describes electrons being trapped, with no link to how the value/data is represented, earns one mark (1). The second mark needs a link such as trapped and not trapped charge representing 1s and 0s, or the trapped charge being kept so the data is not lost.

Example answers and how they were marked
Full marks2/2

A current is used to force electrons through a barrier so that they become trapped, and a cell with a trapped charge or a cell with no trapped charge represents a 1 or a 0.

Why: Linked description: a current forces electrons through a barrier (1) and trapped/not trapped charge represents 1s and 0s (1).

Some marks1/2

The data is stored in flash memory chips.

Why: Gives the creditworthy point that data is stored on flash memory chips (1) but does not develop it, e.g. by saying the data is held as electrical charges or by describing trapped electrons.

No marks0/2

The data is stored as magnetised areas on a spinning platter.

Why: This describes magnetic storage, which the mark scheme says not to accept for a solid state drive.

3Explain2 marksPrimary Memory Swap Remove

A technician increases the amount of RAM in a laptop from 8 GiB to 16 GiB.

Explain one benefit of increasing the amount of RAM in a computer.

[2 marks]
Mark scheme

Award up to two marks for a linked explanation such as:

  • More applications/programs can be open/run at the same time (1) because more instructions and data can be held in main memory at once (1)
  • Programs run faster (1) because the CPU does not have to wait for instructions/data to be read/transferred from slower secondary storage (1)
  • The CPU waits/idles for less time (1) because instructions and data can be transferred to the CPU more quickly from RAM (1)

For both marks, the expansion must follow/associate with the statement.

Do not accept 'more files/photos/documents can be stored' or 'the computer has more storage' - this is a benefit of secondary storage, not RAM.

Do not accept 'the CPU becomes faster' or 'the clock speed increases'.

Example answers and how they were marked
Full marks2/2

More programs can be open at the same time because more instructions and data can be held in main memory at once.

Why: Linked point (1) for more programs running at the same time and reason (1) for more instructions and data being held in main memory at once.

Some marks1/2

Programs will run faster.

Why: Point (1) only; no linked reason such as the CPU not having to wait for data from slower secondary storage.

No marks0/2

There will be more space to save files and documents on the laptop.

Why: Misconception: the benefit given is a benefit of secondary storage, which the mark scheme's 'Do not accept' line rules out.

4Discuss6 marksFetch Decode Execute Cycle Swap Remove

A school is upgrading the desktop computers in its computer science classroom. Each computer has a CPU, main memory and buses. The technician is explaining how the CPU uses these components during the fetch-decode-execute cycle.

Discuss how the CPU uses its components and the buses during the fetch-decode-execute cycle.

Your answer should consider:

  • the role of the CPU and registers
  • the role of the address bus, data bus and control bus
  • the role of the clock.
[6 marks]
Mark scheme

Indicative content

The role of the CPU and registers

  • The control unit decodes the instruction fetched from main memory and controls the other components during the cycle.
  • The ALU carries out arithmetic and logical operations during the execute stage, such as adding two values held in registers.
  • Registers hold the data, addresses and results that the CPU is working on during the cycle.
  • The program counter holds the address of the next instruction to be fetched, so it is incremented after each fetch.
  • The memory address register holds the address of the memory location that is about to be read or written.
  • The memory data register holds the instruction or data that has been fetched from or is being written to main memory.

The role of the address bus, data bus and control bus

  • The address bus carries the address of the memory location that the CPU needs to access from the CPU to main memory.
  • The address bus is one-way, so addresses are only sent from the CPU to main memory.
  • The data bus carries instructions and data between the CPU and main memory, so it is bi-directional.
  • The width of the data bus affects how many bits can be transferred at one time.
  • The control bus carries control signals such as read and write signals, so main memory knows whether the CPU wants to read an instruction or write data.
  • The control bus carries signals from the control unit to coordinate the components during the fetch-decode-execute cycle.

The role of the clock

  • The clock sends regular pulses that synchronise the actions of the CPU and main memory.
  • Each clock pulse triggers the next step of the fetch-decode-execute cycle, so the stages happen in the correct order.
  • The clock provides a regular timing signal so that the fetch-decode-execute cycle repeats at a steady rate.
  • The clock is separate from the control bus; the control bus carries control signals, while the clock provides timing pulses.
  • Do not credit the address bus storing addresses, the data bus storing data, or the control bus controlling the computer without naming a control signal; do not credit clock speed affecting performance as a role in the cycle.
  • Level 3 responses must cover all three bullets and link them to the fetch-decode-execute cycle; Level 2 answers may identify roles but link them only partly to the cycle.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)
Example answers and how they were marked
Full marks6/6

The control unit decodes each instruction that is fetched from main memory and then controls the other components to execute it. The program counter holds the address of the next instruction, and this address is copied to the memory address register before it is sent along the address bus. The address bus carries this address from the CPU to main memory, and it is one-way. The data bus then carries the instruction back from main memory to the CPU; it is bi-directional, so it can also carry data to be written. The memory data register holds the instruction that has been fetched. The control bus carries read and write signals from the control unit, so memory knows whether the CPU wants to read an instruction or write data. During the execute stage, the ALU performs arithmetic or logical operations on data held in registers. The clock sends regular pulses that synchronise each stage, so one fetch, decode or execute step happens on each tick and the cycle repeats in the correct order.

Why: Comprehensive understanding of the CPU, registers, all three buses and the clock, with sustained application to the fetch-decode-execute cycle. Level 3.

Some marks4/6

The address bus carries the address of the next instruction from the program counter to main memory so it can be fetched. The data bus carries the instruction back to the CPU, and it is bi-directional. The control unit decodes the instruction. The clock sends pulses to keep the stages in order.

Why: Adequate understanding of some roles with some linkage to the fetch-decode-execute cycle, but the control bus, ALU and most registers are not covered. Level 2.

Some marks1/6

The data bus carries data between the CPU and RAM. The address bus stores the addresses that the CPU needs. The control bus controls the computer. The clock is the speed of the CPU.

Why: One basic, independent point (the data bus carries data) (1). The address bus does not store addresses, the control bus point names no control signal and clock speed is not a role in the cycle, so no further credit. Level 1.

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