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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 659 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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3 questions · 10 marks

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1Short recall2 marksTopologies Swap Remove

A small office installs a network that uses a star topology, with each device connected to a central switch.

Give two advantages of a star topology.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • If one cable/device fails, the other devices are not affected (1)
  • Fast data transfer/high performance because each device has its own cable/connection (1)
  • Easy to add/remove devices (1)
  • Fault finding is easier because each device has its own cable (1)
  • The switch forwards data only to the destination device, so other devices do not receive it (1)

Do not accept disadvantages, such as the whole network going down if the central switch fails

Do not accept fast/faster/reliable/more reliable on their own, without a reason

Example answers and how they were marked
Full marks2/2

Each device has its own cable to the switch, so if one cable fails the other devices are not affected. It is also easy to add another device.

Why: Failure isolation (1) and easy to add devices (1).

Some marks1/2

It is fast because each device has its own connection.

Why: Fast data transfer qualified by own connection (1), but no second advantage.

No marks0/2

If the central switch fails, the whole network goes down.

Why: This is a disadvantage, not an advantage, so no mark.

2Describe2 marksUser Management Swap Remove

A family shares one computer that has a single hard drive.

Describe how the operating system uses user management to limit the amount of storage space each user is allowed.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • A storage limit/quota is set for each user account (1) so the drive is shared fairly between users (1)
  • The operating system records how much space each user's files are using (1) and refuses to save more files when the limit is reached (1)
  • Each user is given a fixed share/quota of the drive (1) so one user cannot use the space set aside for another (1)

Allow a limit set by an administrator or through the operating system's user management settings; an administrator is not required for credit.

Allow a warning that stops the save; do not award the development for a warning alone where the save is not stopped.

Do not accept responses about passwords/authentication, keeping files separate/folders with no storage limit, deleting old files, compressing files, or buying a larger drive.

Do not accept 'the operating system gives the user a bigger hard drive'.

Do not accept a single global limit for all users; the limit must apply to each user/user account.

Example answers and how they were marked
Full marks2/2

The operating system sets a maximum amount of storage for each user account. When a user reaches this limit, the operating system will not let them save any more files.

Why: Storage limit/quota set for each account (1); saving refused at the limit (1).

Some marks1/2

The operating system sets a maximum amount of storage for each user account.

Why: First point of a storage limit set for each user (1), but no development of what happens when it is reached (0).

No marks0/2

The operating system compresses the user's files so that there is more space on the drive.

Why: Describes compression, which does not limit a user's storage; no creditworthy point.

3Discuss6 marksFetch Decode Execute Cycle Swap Remove

A small robotics company is designing a new robot. The robot's computer uses von Neumann architecture. The engineers are explaining how programs are stored and run.

Discuss how the von Neumann stored program concept and main memory (RAM) are used during the fetch-decode-execute cycle.

Your answer should include:

  • what is meant by the stored program concept
  • the role of RAM in the cycle
  • why the stored program concept is useful.
[6 marks]
Mark scheme

Indicative content

Stored program concept

  • Instructions and data are stored together in the same main memory (RAM).
  • Instructions are fetched one at a time from memory and executed in sequence.
  • The program can be changed by loading different instructions into RAM.
  • The CPU can only execute instructions that are in main memory.

Role of RAM

  • RAM holds the program instructions and the data being used.
  • The address of the next instruction is held in the program counter (PC).
  • The instruction is fetched from RAM using the address bus.
  • The data bus carries the instruction from RAM to the CPU.
  • RAM is volatile, so programs are lost when power is off.
  • RAM is directly accessible by the CPU, unlike secondary storage.

Benefits

  • The same hardware can run many different programs.
  • Programs can be loaded and changed quickly.
  • No need to rewire the computer for a new task.
  • Makes general-purpose computers possible.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)
Example answers and how they were marked
Full marks6/6

The von Neumann stored program concept means that both the program instructions and the data are stored together in the same main memory, RAM. During the fetch-decode-execute cycle, the CPU fetches an instruction from RAM, decodes it in the control unit, and then executes it. The program counter holds the address of the next instruction, and this address is sent along the address bus to RAM. RAM then returns the instruction along the data bus to the CPU. RAM is volatile, so it only holds the program while the robot is powered on. The stored program concept is useful because the robot's computer can run different programs without changing any hardware; new instructions can simply be loaded into RAM. This makes the computer general-purpose and flexible.

Why: Comprehensive understanding: defines stored program concept, explains RAM role with PC, address bus and data bus, applies to robot, and gives benefits. Sustained lines of reasoning. Level 3.

Some marks3/6

The stored program concept is when instructions and data are stored in RAM. The CPU fetches instructions from RAM. The program counter keeps the address of the next instruction. RAM holds the program. The benefit is that you can change the program without rewiring the computer.

Why: Adequate understanding: correct basic points about stored program concept and RAM, with some linkage, but little development or application to the robot's fetch-decode-execute cycle. Level 2.

Some marks1/6

The von Neumann stored program concept is that the CPU uses RAM to store the program. The fetch-decode-execute cycle fetches, decodes and executes. RAM is random access memory. The benefit is that it is fast.

Why: Basic independent points only; no real linkage or application to the robot. Level 1.

Questions by topic

2.1 Binary

Build a paper on this topic 58
Adding Binary Numbers 6 questions Binary and Hexadecimal Basics 10 questions Binary Shifts 6 questions Binary to Denary Conversion 6 questions Binary to Hexadecimal Conversion 6 questions Denary to Binary Conversion 6 questions Denary to Hexadecimal Conversion 6 questions Denary to Negative Binary Conversion 6 questions Hexadecimal to Binary Conversion 6 questions

2.2 Data representation

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Character Sets 18 questions Images 19 questions Sound 19 questions

2.3 Data storage and compression

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Compression 18 questions Units & Conversion 6 questions

3.1 Hardware

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Embedded Systems 17 questions Fetch Decode Execute Cycle 15 questions Primary Memory 15 questions Secondary Memory 15 questions Stored Program Computers 15 questions

3.2 Software

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File Management 18 questions Memory Management 16 questions Peripheral Management 11 questions Process Management 12 questions Purpose & Function of Operating Systems 17 questions Software Basics 13 questions User Management 18 questions Utility Software 19 questions

3.3 Programming languages

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Low and High Level Languages 19 questions Translators 18 questions

4.1 Networks

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Addressing 16 questions LANs & WANs 16 questions Network Speed 5 questions Packet Switching 16 questions Protocols & Layers 17 questions The Internet 16 questions Topologies 17 questions Wired Connections 17 questions Wireless Connections 18 questions

4.2 Network security

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Network Security Risks 18 questions Preventing Network Security Risks 18 questions

5.1 Environmental

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E-waste 17 questions Manufacturing Technology 19 questions

5.2 Ethical and legal

Build a paper on this topic 65
Data Protection Act 17 questions Impact of AI 18 questions Intellectual Property 18 questions Software Licences 12 questions

5.3 Cybersecurity

Malware 8 questions

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