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Edexcel GCSE Computer Science (1CP2) Exam Questions

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4 questions · 15 marks

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1Short recall2 marksPrimary Memory Swap Remove

A computer is designed using the von Neumann stored program concept.

Define the term stored program concept.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • The program instructions and data are stored together in main memory/RAM (1)
  • The same memory is used for both instructions and data (1)
  • The instructions are fetched from main memory and executed by the CPU (1)
  • The instructions are fetched and executed one at a time / in sequence (1)
  • The program can be changed/replaced by loading new instructions into memory, without changing the hardware (1)

Do not accept the program is stored in secondary storage / on the hard disk.

Do not accept the program is stored in the CPU / in registers.

Example answers and how they were marked
Full marks2/2

The program instructions and the data are stored together in main memory, and the CPU fetches the instructions one at a time and executes them.

Why: Creditworthy point that instructions and data are stored in the same main memory (1) and the linked point that the CPU fetches and executes them from memory (1).

Some marks1/2

The program is held in the main memory (RAM) so that the computer can run it.

Why: Earns the point that the program instructions are stored in main memory (1), but does not say that the CPU fetches and executes them, so the second mark is not earned.

No marks0/2

The program is stored on the hard disk and loaded into the CPU when it is run.

Why: Both parts are misconceptions named in the Do not accept lines: the stored program concept keeps the instructions in main memory, not on secondary storage or in the CPU.

2Short recall1 markSecondary Memory Swap Remove

Data is stored on optical discs as pits and lands.

Name the component in an optical disc drive that reads this data.

[1 mark]
Mark scheme

Award one mark for:

  • Laser (1)

Allow laser beam

Do not accept read/write head

Do not accept pits

Do not accept lands

Do not accept reflective surface

Do not accept magnet/magnetic

Example answers and how they were marked
Full marks1/1

Laser

Why: Laser is the creditworthy answer (1).

No marks0/1

A read/write head

Why: Read/write head is not accepted by the mark scheme; it reads magnetic media, not optical discs, so no marks are awarded.

No marks0/1

Pits and lands

Why: Pits and lands are what the laser reads, not the component that reads the data, so the mark scheme does not accept them.

3Discuss6 marksSecondary Memory Swap Remove

A school is buying new computers. Each computer needs storage for the operating system, applications and students' work. The computers have RAM and will be used in classrooms.

Discuss the role of secondary storage in these computers.

Your answer should include:

  • why secondary storage is needed
  • the difference between primary and secondary storage
  • a suitable type of secondary storage for the school's computers and a reason why it is suitable.
[6 marks]
Mark scheme

Indicative content

Why secondary storage is needed

  • Secondary storage is non-volatile, so it keeps the operating system, applications and students' work when the power is turned off.
  • It stores programs and files that are not currently in use, so they are not lost when the computer is switched off.
  • It provides a larger capacity than primary storage for files such as students' work, videos and photographs.
  • It allows each computer to keep many students' files and the software the school has installed.

The difference between primary and secondary storage

  • Primary storage (RAM) is volatile and directly accessible by the CPU; secondary storage is non-volatile and not directly accessible by the CPU.
  • RAM holds the data and instructions currently in use; secondary storage holds data and programs long term.
  • Primary storage is faster but smaller and more expensive per gigabyte; secondary storage is slower but larger and cheaper.
  • The school's computers need both: RAM to run the operating system and applications, and secondary storage to keep them when the computer is switched off.

A suitable type of secondary storage for the school's computers and a reason why it is suitable

  • A solid state drive (SSD) is suitable because it has no moving parts, so it is durable and quiet, and has fast read/write speeds, which helps the computers start up quickly.
  • A magnetic hard disk drive (HDD) is suitable because it is cheap and offers a very large capacity, which is useful for storing many students' files.
  • Either type could be used; a small SSD for the operating system and applications plus a large HDD for files would balance speed and cost.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Additional guidance

  • Award credit for a type of secondary storage only when a reason is given that is linked to the school's computers; a named type alone (e.g. 'SSD') is not creditworthy. Do not accept RAM as secondary storage or the claim that secondary storage is the same as RAM. Do not accept CD/DVD/Blu-ray as the main storage for the school's computers because their capacity is too low and write speeds are slow.
  • For Level 3, the answer must cover all three bullets and apply at least one point to the school's computers. A 6-mark answer is well developed with sustained reasoning and a justified choice; a 5-mark answer covers all three but with limited development or application. Comparisons of speed and cost between primary and secondary storage are creditworthy as part of the difference.
Example answers and how they were marked
Full marks6/6

The school needs secondary storage because it is non-volatile, so the operating system, applications and students' work stay on the computer when the power is turned off. RAM is volatile and only holds data currently in use, while secondary storage keeps files long term. Secondary storage is also larger and cheaper per gigabyte than RAM, so it can hold many students' files. An SSD would be suitable because it has no moving parts, so it is durable in a classroom, and it has fast read/write speeds, so the computers start up quickly. A magnetic HDD would give a larger capacity for the same cost, which is useful for storing videos.

Why: Covers all three bullets: why secondary storage is needed (non-volatile, stores OS/apps/work, larger capacity), the difference from RAM (volatile, directly accessible, faster, smaller), and suitable types (SSD durable and fast; HDD cheap and high capacity) applied to the school's computers. Sustained and well structured. Level 3.

Some marks3/6

Secondary storage is needed to store data when the power is off. It is non-volatile, unlike RAM which is volatile. RAM is directly accessed by the CPU and is faster, but secondary storage is bigger. The school could use a hard disk because it has a lot of space.

Why: All three bullets covered with basic points: non-volatile storage when power off (1), difference volatile vs non-volatile (1), HDD with reason of capacity (1). Limited development and application to the school, so low Level 2, 3 marks.

Some marks1/6

Secondary storage is non-volatile so it keeps data when the power is off. It is the same as RAM, which is why it is fast. The school should use a CD because it is cheap and portable.

Why: One creditworthy basic point: non-volatile keeps data (1). Misconception that secondary storage is the same as RAM, and CD is not accepted as suitable main storage, so Level 1.

4Discuss6 marksStored Program Computers Swap Remove

A college is buying new computers for its computer science classroom. A technician explains that the CPU uses three buses to communicate with main memory and other components.

Discuss the role of the address bus, the data bus and the control bus in the fetch-decode-execute cycle.

Your answer should include:

  • what each bus carries
  • the direction in which each bus carries it
  • the role of the buses in the fetch-decode-execute cycle.
[6 marks]
Mark scheme

Indicative content

What each bus carries

  • The address bus carries the address of a memory location that the CPU wants to read from or write to.
  • The data bus carries data and instructions between the CPU and main memory, and between the CPU and other components such as the input and output controllers.
  • The control bus carries control signals, such as read and write, that coordinate the activities of the computer.
  • The clock is a separate component that sends regular pulses, and the control bus carries the signals that keep the other components in time with those pulses.

Direction

  • The address bus is one-way, carrying addresses from the CPU to main memory.
  • The data bus is two-way, so data and instructions can travel both to and from the CPU.
  • The control bus carries control signals from the control unit to the other components, and it is not the clock signal itself.
  • The number of bits in the address bus determines how many memory locations can be addressed, and the number of bits in the data bus determines how much can be transferred at one time.

The role of the buses in the fetch-decode-execute cycle

  • Fetch: the address of the next instruction, held in a register in the CPU, is placed on the address bus so that main memory knows which location to read.
  • Fetch: the control unit sends a read signal on the control bus to main memory.
  • Fetch: the instruction held in that location is returned to the CPU on the data bus.
  • Decode: the control unit decodes the instruction and sends control signals on the control bus to set up the other components, for example telling the ALU which operation to carry out.
  • Execute: the address of any data needed is placed on the address bus, a read or write signal is sent on the control bus, and the data itself travels between the CPU and main memory on the data bus.
  • The cycle repeats, with each step taking place in time with a pulse from the clock.

Level 3 responses must cover all three buses and link them to the fetch-decode-execute cycle, including the fetch stage and at least one of the decode and execute stages. Answers that describe each bus correctly but link none of them to a stage of the cycle are limited to Level 1.

Do not accept 'the address bus carries data', 'the data bus carries addresses', 'the data bus carries instructions only during the fetch stage', 'the control bus carries the clock signal' or 'the control bus is the clock'; the clock is a separate component whose pulses the control signals coordinate with.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)
Example answers and how they were marked
Full marks6/6

At the start of the fetch stage the address of the next instruction, which is held in a register, is placed on the address bus, which is one-way, so that main memory knows which location to read. The control unit sends a read signal on the control bus, and the instruction held at that address is returned to the CPU on the data bus, which is two-way. In the decode stage the control unit works out what the instruction means and sends control signals on the control bus to set up the other components, for example telling the ALU which operation to carry out. In the execute stage, if the instruction needs data from memory, the address of that data is placed on the address bus, a read or write signal is sent on the control bus and the data itself travels on the data bus. Every step happens on a pulse from the clock, which is a separate component, and the control bus carries the signals that keep the components in time with it. The widths of the buses matter too: more address bits mean more memory locations can be addressed and more data bits mean more can be moved at once.

Why: Level 3 (6 marks): all three buses are covered, with what each carries and its direction, and each is linked to the fetch, decode and execute stages, plus the role of the clock and the effect of bus widths.

Some marks2/6

The address bus carries addresses from the CPU to the memory and it is one-way. The data bus carries data and it is two-way. The control bus carries control signals. During the fetch stage the CPU fetches the instruction from memory using these buses.

Why: Level 1 (2 marks): each bus is named with a basic correct statement (address bus carries addresses one-way, data bus is two-way, control bus carries control signals), but no bus is linked to a stage of the cycle, so the guidance line limits this to Level 1; the general mention of the fetch stage is not tied to any bus.

No marks0/6

The address bus carries the data to the CPU. The data bus carries the addresses to the memory. The control bus is the clock that makes the CPU run faster.

Why: Level 0 (0 marks): the address bus and data bus roles are swapped, which the scheme says not to accept, and the control bus is wrongly described as the clock, which is also not accepted, so there is no rewardable content.

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