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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 693 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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2 questions · 2 marks

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1Multiple choice1 markLANs & WANs Swap Remove

Identify a characteristic of a local area network (LAN).

[1 mark]
  • AIt connects devices in different countries
  • BIt covers a large geographical area
  • CIt is owned by the organisation that uses it
  • DIt only uses wireless connections
Mark scheme
  • C It is owned by the organisation that uses it (1)
  • The only correct answer is C. The correct answer is that a LAN is owned by the organisation that uses it.
  • A is not correct because connecting devices in different countries is a characteristic of a WAN
  • B is not correct because a LAN covers a small geographical area
  • D is not correct because a LAN can use wired or wireless connections
Example answers and how they were marked
Full marks1/1

C It is owned by the organisation that uses it

Why: Correct option: a LAN uses infrastructure owned by the organisation that uses it (1).

No marks0/1

A It connects devices in different countries

Why: This describes a WAN, not a LAN (0).

No marks0/1

B It covers a large geographical area

Why: Confuses a LAN with a WAN; a LAN covers a small geographical area (0).

2Short recall1 markCharacter Sets Swap Remove

A computer can store a maximum of 80 bits for a text message. Each character is stored using 7-bit ASCII.

State the maximum number of whole characters that can be stored in the message.

[1 mark]
Mark scheme

Award one mark for:

  • 11 (characters) (1)

Allow 11 remainder 3.

Allow 80 ÷ 7 = 11.428... rounded down to 11.

Do not accept 11.4 or 12 (rounding up or giving a decimal answer).

Do not award an unevaluated calculation such as 80 ÷ 7 with no answer.

Example answers and how they were marked
Full marks1/1

11

Why: Correct: 80 ÷ 7 = 11 remainder 3, so 11 whole characters can be stored (1).

No marks0/1

11.4

Why: Near miss: gives a decimal result rather than the number of whole characters; the mark scheme does not accept 11.4.

No marks0/1

12

Why: Rounds up to 12, but 12 characters would need 84 bits, more than the 80 available; the mark scheme does not accept 12.

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