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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 693 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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3 questions · 4 marks

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1Multiple choice1 markAddressing Swap Remove

A technician is checking the IP addresses of the devices on a network.

Identify the valid IPv4 address.

[1 mark]
  • A192.168.1
  • B192.168.1.1
  • C192.168.1.1.1
  • D192.168.1.256
Mark scheme
  • B 192.168.1.1 (1)
  • The only correct answer is B. The correct answer is 192.168.1.1.
  • A is not correct because it is an incomplete address with only three numbers, not four
  • C is not correct because it is an address with five numbers, not four
  • D is not correct because it contains 256, which is outside the range 0 to 255
Example answers and how they were marked
Full marks1/1

B 192.168.1.1

Why: Correct option (1): an IPv4 address is four numbers, each from 0 to 255, separated by dots.

No marks0/1

D 192.168.1.256

Why: Near miss: it has four numbers but 256 is outside the range 0 to 255 (mark scheme line D), so no mark.

No marks0/1

A 192.168.1

Why: It has only three numbers, so it is not a complete IPv4 address (mark scheme line A), so no mark.

2Short recall1 markAddressing Swap Remove

An IPv4 address is made up of four 8-bit numbers separated by dots.

State the range of values that each number in an IPv4 address can have.

[1 mark]
Mark scheme

Award one mark for:

  • 0 to 255 (1)

Allow 0–255 / 0-255 / between 0 and 255 / 0 and 255.

Do not accept 1 to 255 (0 is a valid value).

Do not accept any range that includes 256, e.g. 0 to 256.

Example answers and how they were marked
Full marks1/1

0 to 255

Why: Gives the correct range (1).

No marks0/1

1 to 255

Why: Near miss: excludes 0, which is a valid value; the Do not accept line applies.

No marks0/1

0 to 256

Why: Includes 256, which is not valid; the Do not accept line applies.

3Describe2 marksWireless Connections Swap Remove

An office has one wireless access point that employees connect their laptops to.

Describe how connecting more devices to the wireless access point can affect the speed and latency of the network.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • The bandwidth/capacity of the access point is shared between all the connected devices (1) so each device gets less bandwidth as more devices connect, which reduces the speed of data transfer (1)
  • The devices have to take turns to transmit (contention) (1) so each device waits longer before it can send data, which increases latency (1)
  • The access point can only support a maximum number of connections (1) so once this limit is reached, further devices cannot connect to the network (1)

Allow 'contention' as an alternative to devices having to take turns to transmit.

Allow 'the network becomes slower' as the second mark only where it is linked to shared bandwidth, to devices taking turns to transmit or to the maximum number of connections.

Do not accept a response that only states the network becomes slower, or that there are more devices/more traffic, without saying how this affects performance.

Do not accept responses about range or interference unless they are linked to the number of connected devices.

Example answers and how they were marked
Full marks2/2

All of the connected devices share the bandwidth of the access point, so as more devices are added each device gets less bandwidth and data is transferred more slowly.

Why: Shared bandwidth point (1) developed into the effect on the speed of data transfer (1).

Some marks1/2

The bandwidth of the access point has to be shared between all the devices that are connected to it.

Why: Correct point that bandwidth is shared (1), but there is no development saying how this affects the speed or latency, so only one mark.

No marks0/2

Each device gets its own bandwidth from the access point, so adding more devices does not change the speed.

Why: Misconception that bandwidth is not shared, so no creditworthy point is made.

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