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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 687 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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3 questions · 4 marks

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1Multiple choice1 markLow and High Level Languages Swap Remove

Programming languages can be either high-level or low-level.

Identify the low-level programming language.

[1 mark]
  • AAssembly language
  • BC#
  • CJava
  • DPython
Mark scheme
  • A Assembly language (1)
  • The only correct answer is A. The correct answer is assembly language.
  • B is not correct because C# is a high-level language
  • C is not correct because Java is a high-level language
  • D is not correct because Python is a high-level language
Example answers and how they were marked
Full marks1/1

A Assembly language

Why: Correct option: assembly language uses mnemonics and is a low-level language (1).

No marks0/1

D Python

Why: Near miss: Python is a high-level language, so no mark is awarded.

No marks0/1

C Java

Why: Misconception: Java is a high-level language because it uses statements that look like English, so no mark.

2Short recall1 markLow and High Level Languages Swap Remove

A high-level language uses statements that look like English or maths.

State what a single statement in a high-level language is usually translated into.

[1 mark]
Mark scheme

Award one mark for:

  • Several/multiple machine code instructions (1)

The answer must refer to instructions.

Do not accept machine code on its own.

Do not accept binary on its own.

Do not accept 'one or more machine code instructions' as it does not show that one statement becomes several instructions.

Do not accept assembly code/compiled code/low-level code on their own.

Do not accept 'a line of code'/'a statement' as this repeats the question.

Example answers and how they were marked
Full marks1/1

Several machine code instructions

Why: Matches the creditworthy point that one high-level statement translates into several machine code instructions (1).

No marks0/1

Machine code

Why: Near-miss: gives the type of code but not that one statement becomes several instructions; mark scheme does not accept machine code on its own.

No marks0/1

Binary

Why: Misconception: high-level statements are translated into machine code instructions, not just binary; not accepted.

3Explain2 marksTranslators Swap Remove

An interpreter translates and executes high-level code.

Explain why an interpreted program must be translated again each time it is run.

[2 marks]
Mark scheme

Award up to two marks for a linked explanation such as:

  • No object code/machine code file is stored/saved (1) so there is no translated program to run on the next occasion (1)
  • The translation is only temporary/is lost when the program ends (1) because each line is translated as the program runs (1)
  • No executable file is created/saved (1) so the whole program has to be translated again every time it is run (1)
  • The interpreter translates each line while the program is running (1) so nothing is kept that could be run without the interpreter (1)

For both marks, the expansion must follow/associate with the statement.

Do not accept 'it is interpreted' or 'it is not compiled' without saying that no object code/executable is stored/saved.

Do not accept 'the source code is high-level so it must be translated' or 'the source code has to be turned into machine code' on its own, as this is true of any translation.

Do not accept answers about the source code being deleted.

Example answers and how they were marked
Full marks2/2

The interpreter does not store an object code file, so there is no machine code file to run on the next occasion.

Why: No object code stored (1) linked to no translated program for the next run (1).

Some marks1/2

No object code is saved.

Why: Point that nothing is stored (1) but no linked reason saying why this means the program must be translated again.

No marks0/2

It has to be translated again because the interpreter deletes the source code after each run.

Why: Incorrect: the interpreter does not delete the source code; no mark scheme point.

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