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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 631 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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5 questions · 12 marks

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1Multiple choice1 markPrimary Memory Swap Remove

A computer is running an application. The application's data and instructions are transferred from secondary storage into RAM before the CPU processes them.

Identify the reason for this transfer.

[1 mark]
  • ARAM is non-volatile
  • BRAM is faster to access than secondary storage
  • CRAM has a larger capacity than secondary storage
  • DRAM is cheaper than secondary storage
Mark scheme
  • B RAM is faster to access than secondary storage (1)
  • The only correct answer is B. The correct answer is RAM is faster to access than secondary storage.
  • A is not correct because RAM is volatile
  • C is not correct because RAM has a smaller capacity than secondary storage
  • D is not correct because RAM is more expensive than secondary storage
Example answers and how they were marked
Full marks1/1

B RAM is faster to access than secondary storage

Why: Selects the correct option: RAM is faster to access than secondary storage, so data and instructions can reach the CPU quickly (1).

No marks0/1

A RAM is non-volatile

Why: Near miss: RAM is volatile; this does not explain the transfer into RAM.

No marks0/1

C RAM has a larger capacity than secondary storage

Why: Misconception: assumes primary memory has a larger capacity, but RAM has a smaller capacity than secondary storage.

2Multiple choice1 markSecondary Memory Swap Remove

A company stores films on optical media.

Identify the optical storage medium that can store the most data.

[1 mark]
  • ABlu-ray Disc
  • BCD
  • CDVD
  • DMagnetic tape
Mark scheme
  • A Blu-ray Disc (1)
  • The only correct answer is A. The correct answer is Blu-ray Disc.
  • B is not correct because a CD stores less data than a Blu-ray Disc, up to about 700 MB
  • C is not correct because a DVD stores less data than a Blu-ray Disc, up to about 4.7 GB (single-layer) or 8.4 GB (dual-layer)
  • D is not correct because magnetic tape is not an optical storage medium
Example answers and how they were marked
Full marks1/1

A Blu-ray Disc

Why: Correct option (1): a Blu-ray Disc has the greatest capacity of the optical media.

No marks0/1

C DVD

Why: Near miss scoring 0: a DVD is optical but stores less than a Blu-ray Disc (mark scheme line C). Only A is credited.

No marks0/1

D Magnetic tape

Why: Misconception scoring 0: candidates pick tape for its large capacity but magnetic tape is not an optical storage medium (mark scheme line D).

3Short recall2 marksPrimary Memory Swap Remove

A computer is designed using the von Neumann stored program concept.

Define the term stored program concept.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • The program instructions and data are stored together in main memory/RAM (1)
  • The same memory is used for both instructions and data (1)
  • The instructions are fetched from main memory and executed by the CPU (1)
  • The instructions are fetched and executed one at a time / in sequence (1)
  • The program can be changed/replaced by loading new instructions into memory, without changing the hardware (1)

Do not accept the program is stored in secondary storage / on the hard disk.

Do not accept the program is stored in the CPU / in registers.

Example answers and how they were marked
Full marks2/2

The program instructions and the data are stored together in main memory, and the CPU fetches the instructions one at a time and executes them.

Why: Creditworthy point that instructions and data are stored in the same main memory (1) and the linked point that the CPU fetches and executes them from memory (1).

Some marks1/2

The program is held in the main memory (RAM) so that the computer can run it.

Why: Earns the point that the program instructions are stored in main memory (1), but does not say that the CPU fetches and executes them, so the second mark is not earned.

No marks0/2

The program is stored on the hard disk and loaded into the CPU when it is run.

Why: Both parts are misconceptions named in the Do not accept lines: the stored program concept keeps the instructions in main memory, not on secondary storage or in the CPU.

4Explain2 marksPrimary Memory Swap Remove

RAM is used to store data while a computer is running.

Explain one reason why the data in RAM is lost when a computer is switched off.

[2 marks]
Mark scheme

Award up to two marks for a linked explanation such as:

  • RAM is volatile (memory) (1) because it needs a constant/continuous power supply to hold/store the data it contains (1)
  • Data is held in RAM as electrical states/charges (1) so when the power supply is removed these states cannot be kept/refreshed and the data is lost (1)
  • RAM is used as short-term storage for the data and instructions currently in use (1) because it can only hold them while the computer has power (1)

For both marks, the expansion must follow/associate with the statement and must link the loss of the data to the power supply being removed.

Accept 'RAM is volatile' on its own for the first mark; the second mark is only awarded for a linked reason about the power supply.

Do not accept 'RAM is temporary/short-term memory' or 'RAM is cleared when the computer is switched off' on its own for both marks, as neither gives a reason.

Do not accept answers that say the data is deleted/cleared/erased by the computer or the operating system, or that the data is saved/moved to secondary storage, without saying why the data cannot be kept (e.g. because RAM needs power/is volatile).

Example answers and how they were marked
Full marks2/2

RAM is volatile memory, which means it needs a constant power supply to keep the data it is holding. When the power is switched off, the data is lost.

Why: Linked point (1) for 'RAM is volatile memory' and reason (1) for needing a constant power supply to hold the data.

Some marks1/2

The data in RAM is lost because RAM is volatile memory.

Why: Point (1) for 'RAM is volatile' but no linked reason about the power supply, and the mark scheme states that 'RAM is volatile' alone earns only the first mark.

No marks0/2

The data is deleted from RAM by the operating system when the computer is shut down so that the memory is free for next time.

Why: No creditworthy point: the answer says the data is deleted without saying why it cannot be kept, which the mark scheme's 'Do not accept' line rules out.

5Discuss6 marksStored Program Computers Swap Remove

A school is buying new desktop computers for its computer science classroom. The teacher explains that each computer uses the von Neumann stored program concept: the program instructions and the data are stored together in main memory, and the CPU runs each instruction by carrying out the fetch-decode-execute cycle.

Discuss the role of the control unit, the arithmetic logic unit (ALU) and registers in the fetch-decode-execute cycle.

Your answer should include:

  • how an instruction is fetched from main memory and decoded
  • how the ALU executes an instruction
  • how registers are used during the cycle.
[6 marks]
Mark scheme

Indicative content

Fetching and decoding an instruction

  • The register that holds the address of the next instruction (the program counter) contains the address of the instruction to be fetched.
  • This address is sent to main memory (RAM) and the instruction is copied from main memory into a register inside the CPU.
  • The program counter is updated so that it holds the address of the next instruction in the program.
  • The control unit decodes the instruction that has been fetched, working out which operation is required and which data or registers are needed.
  • The control unit sends control signals to coordinate the other components as the instruction is carried out.
  • The control unit decides what happens next, for example after a comparison it decides whether the next instruction is the following one or a jump.

The arithmetic logic unit (ALU) executes an instruction

  • The control unit directs the arithmetic logic unit (ALU) to carry out the operation.
  • The ALU performs arithmetic operations such as addition, subtraction, multiplication and division, for example adding two values in a program written by the class.
  • The ALU performs logical operations such as comparing two values to see if they are equal or whether one is greater than the other.
  • The result of the operation carried out by the ALU is passed back and stored in a register.
  • The ALU operates on data that has been fetched from main memory; it does not fetch the instruction and it does not decide which instruction is next.

Registers

  • Registers are small, very fast memory locations inside the CPU.
  • They hold the data, addresses and results that the CPU is working on during the cycle.
  • Registers are used in every stage of the cycle, not only when the ALU produces a result.
  • Because registers are inside the CPU they can be read and written much faster than main memory during the cycle.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)
  • A Level 3 answer must link the roles of all three components to the fetch, decode and execute stages. An answer that links only one component to a stage, with the other points listed separately, is Level 1 (1–2 marks); an answer that links two of the components to stages is Level 2 (3–4 marks). A point repeated under more than one heading is credited once only.
  • Accept 'the program counter', 'the address register' or 'a register holding the address of the next instruction' as the register that holds the address of the next instruction. Do not accept 'the control unit performs the calculations', 'the ALU controls the timing of the CPU' / 'the ALU sends the clock signal' or 'registers are in main memory (RAM)'.
Example answers and how they were marked
Full marks6/6

In the fetch stage, a register called the program counter holds the address of the next instruction and this address is sent to main memory. The instruction is copied from main memory into a register in the CPU and the program counter is updated so that it points to the next instruction. The control unit then decodes the instruction in the decode stage, working out which operation is required and which data or registers are needed, and it sends control signals to coordinate the other components. In the execute stage the control unit directs the ALU to carry out the operation the class's program needs: the ALU does arithmetic, such as adding two values, or a logical comparison, such as checking whether one value is greater than another, and it does not decide what happens next, the control unit does. The result from the ALU is stored in a register, and because registers hold the data, addresses and results at every stage, the cycle can repeat with the next instruction.

Why: Level 3: the role of each component is linked to the stage it works in (program counter and registers in fetch, control unit decoding and deciding next, ALU executing and its result stored in a register) across all three stages, with the classroom context.

Some marks2/6

The control unit decodes the instruction in the decode stage. The ALU does maths and logic, such as addition and comparing numbers. Registers store data inside the CPU. In the fetch stage the instruction is fetched from the RAM and put into the CPU.

Why: Level 1: several correct basic points that the mark scheme credits (the instruction is fetched from main memory into the CPU, the control unit decodes the instruction, the ALU does arithmetic and logical operations, registers store data) but only the control unit is linked to a stage of the cycle, so the answer is top of Level 1.

Some marks1/6

The control unit decodes instructions. The ALU controls the timing of the CPU and sends the clock signal. Registers are in the RAM and they store the program.

Why: Level 1: one basic point, that the control unit decodes instructions (1). The other statements are on the do-not-accept list (the ALU does not control the timing of the CPU or send the clock signal, and registers are in the CPU, not main memory), so they earn no credit.

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