Menu

Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 693 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

Build a paper

Topics (none ticked: all of them)
Question types (none ticked: all of them)

Practice paper

4 questions · 11 marks

Pick again
Print
1Multiple choice1 markPrimary Memory Swap Remove

A computer is running an application. The application's data and instructions are transferred from secondary storage into RAM before the CPU processes them.

Identify the reason for this transfer.

[1 mark]
  • ARAM is non-volatile
  • BRAM is faster to access than secondary storage
  • CRAM has a larger capacity than secondary storage
  • DRAM is cheaper than secondary storage
Mark scheme
  • B RAM is faster to access than secondary storage (1)
  • The only correct answer is B. The correct answer is RAM is faster to access than secondary storage.
  • A is not correct because RAM is volatile
  • C is not correct because RAM has a smaller capacity than secondary storage
  • D is not correct because RAM is more expensive than secondary storage
Example answers and how they were marked
Full marks1/1

B RAM is faster to access than secondary storage

Why: Selects the correct option: RAM is faster to access than secondary storage, so data and instructions can reach the CPU quickly (1).

No marks0/1

A RAM is non-volatile

Why: Near miss: RAM is volatile; this does not explain the transfer into RAM.

No marks0/1

C RAM has a larger capacity than secondary storage

Why: Misconception: assumes primary memory has a larger capacity, but RAM has a smaller capacity than secondary storage.

2Short recall2 marksSecondary Memory Swap Remove

A computer uses secondary storage to keep programs and data.

Give two examples of secondary storage devices that store data using magnetic media.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • Hard disk drive/HDD (1)
  • External/portable hard disk drive (1)
  • Magnetic tape drive (1)
  • Magnetic tape (1)

Allow a named device or the storage media type, e.g. hard disk/hard disc for hard disk drive, tape for magnetic tape

Allow floppy disk/floppy disk drive

Do not accept solid state devices (SSD, USB flash drive/memory stick, SD card/memory card) or optical media (CD/DVD/Blu-ray) as these do not store data using magnetism

Example answers and how they were marked
Full marks2/2

Hard disk drive and magnetic tape

Why: Hard disk drive (1) and magnetic tape (1) are both magnetic secondary storage, so both marks are awarded.

Some marks1/2

Hard disk drive and SD card

Why: Hard disk drive is magnetic (1); an SD card is solid state, not magnetic, so the second mark is not awarded.

No marks0/2

CD and DVD

Why: Both are optical media, which the mark scheme says not to accept, so no marks are awarded.

3Explain2 marksPrimary Memory Swap Remove

A computer follows the von Neumann stored program concept. A program's instructions are stored on secondary storage before the program is run.

Explain one reason why the instructions of a program must be held in RAM before they can be executed.

[2 marks]
Mark scheme

Award up to two marks for a linked explanation such as:

  • The CPU can only fetch/read instructions from main memory/RAM (1) so the instructions of a running program must be copied/loaded into RAM before they can be executed (1)
  • RAM is faster to access than secondary storage (1) so the instructions can be fetched quickly enough for the CPU to execute them (1)
  • The CPU needs the instructions in RAM to fetch and execute them (1) because the fetch-decode-execute cycle reads each instruction from main memory/RAM (1)
  • The address of the next instruction is sent to RAM on the address bus (1) so the instruction can be transferred to the CPU/registers for decoding/execution (1)

For both marks, the expansion must follow/associate with the statement.

Allow the point and reason in either order if they are linked.

Do not accept answers that only say the CPU needs instructions, or that RAM is faster, without linking this to fetching/executing the instructions.

Do not accept answers that only say RAM holds data and instructions without linking this to the fetch-decode-execute cycle.

Do not accept 'RAM is permanent/non-volatile storage, so the instructions are kept safe' - RAM is volatile.

The response does not need to name the address bus or the fetch stage for full marks; a linked reason that explains why instructions must be in RAM (for example, the CPU can only fetch from RAM, or RAM is faster than secondary storage) is enough.

Example answers and how they were marked
Full marks2/2

The CPU can only fetch instructions from main memory, so the instructions of a running program must be copied into RAM before they can be executed.

Why: Linked point (1) for the CPU only being able to fetch instructions from main memory/RAM, and reason (1) for instructions being copied into RAM before execution.

Some marks1/2

The CPU can only fetch instructions from main memory.

Why: Point (1) only; there is no linked reason that explains why this means the instructions must be held in RAM before execution, such as RAM being faster than secondary storage.

No marks0/2

Instructions are kept in RAM because RAM is permanent storage and does not lose the instructions when the power is turned off.

Why: Misconception: RAM is described as permanent/non-volatile, which the mark scheme's 'Do not accept' line rules out; no creditworthy linked point.

4Discuss6 marksStored Program Computers Swap Remove

A college is buying new computers for its computer science classroom. A technician explains that the CPU uses three buses to communicate with main memory and other components.

Discuss the role of the address bus, the data bus and the control bus in the fetch-decode-execute cycle.

Your answer should include:

  • what each bus carries
  • the direction in which each bus carries it
  • the role of the buses in the fetch-decode-execute cycle.
[6 marks]
Mark scheme

Indicative content

What each bus carries

  • The address bus carries the address of a memory location that the CPU wants to read from or write to.
  • The data bus carries data and instructions between the CPU and main memory, and between the CPU and other components such as the input and output controllers.
  • The control bus carries control signals, such as read and write, that coordinate the activities of the computer.
  • The clock is a separate component that sends regular pulses, and the control bus carries the signals that keep the other components in time with those pulses.

Direction

  • The address bus is one-way, carrying addresses from the CPU to main memory.
  • The data bus is two-way, so data and instructions can travel both to and from the CPU.
  • The control bus carries control signals from the control unit to the other components, and it is not the clock signal itself.
  • The number of bits in the address bus determines how many memory locations can be addressed, and the number of bits in the data bus determines how much can be transferred at one time.

The role of the buses in the fetch-decode-execute cycle

  • Fetch: the address of the next instruction, held in a register in the CPU, is placed on the address bus so that main memory knows which location to read.
  • Fetch: the control unit sends a read signal on the control bus to main memory.
  • Fetch: the instruction held in that location is returned to the CPU on the data bus.
  • Decode: the control unit decodes the instruction and sends control signals on the control bus to set up the other components, for example telling the ALU which operation to carry out.
  • Execute: the address of any data needed is placed on the address bus, a read or write signal is sent on the control bus, and the data itself travels between the CPU and main memory on the data bus.
  • The cycle repeats, with each step taking place in time with a pulse from the clock.

Level 3 responses must cover all three buses and link them to the fetch-decode-execute cycle, including the fetch stage and at least one of the decode and execute stages. Answers that describe each bus correctly but link none of them to a stage of the cycle are limited to Level 1.

Do not accept 'the address bus carries data', 'the data bus carries addresses', 'the data bus carries instructions only during the fetch stage', 'the control bus carries the clock signal' or 'the control bus is the clock'; the clock is a separate component whose pulses the control signals coordinate with.

Levels

  • Level 0 (0 marks): No rewardable content.
  • Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
  • Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
  • Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)
Example answers and how they were marked
Full marks6/6

At the start of the fetch stage the address of the next instruction, which is held in a register, is placed on the address bus, which is one-way, so that main memory knows which location to read. The control unit sends a read signal on the control bus, and the instruction held at that address is returned to the CPU on the data bus, which is two-way. In the decode stage the control unit works out what the instruction means and sends control signals on the control bus to set up the other components, for example telling the ALU which operation to carry out. In the execute stage, if the instruction needs data from memory, the address of that data is placed on the address bus, a read or write signal is sent on the control bus and the data itself travels on the data bus. Every step happens on a pulse from the clock, which is a separate component, and the control bus carries the signals that keep the components in time with it. The widths of the buses matter too: more address bits mean more memory locations can be addressed and more data bits mean more can be moved at once.

Why: Level 3 (6 marks): all three buses are covered, with what each carries and its direction, and each is linked to the fetch, decode and execute stages, plus the role of the clock and the effect of bus widths.

Some marks2/6

The address bus carries addresses from the CPU to the memory and it is one-way. The data bus carries data and it is two-way. The control bus carries control signals. During the fetch stage the CPU fetches the instruction from memory using these buses.

Why: Level 1 (2 marks): each bus is named with a basic correct statement (address bus carries addresses one-way, data bus is two-way, control bus carries control signals), but no bus is linked to a stage of the cycle, so the guidance line limits this to Level 1; the general mention of the fetch stage is not tied to any bus.

No marks0/6

The address bus carries the data to the CPU. The data bus carries the addresses to the memory. The control bus is the clock that makes the CPU run faster.

Why: Level 0 (0 marks): the address bus and data bus roles are swapped, which the scheme says not to accept, and the control bus is wrongly described as the clock, which is also not accepted, so there is no rewardable content.

Questions by topic

More ways to revise Edexcel GCSE Computer Science (1CP2)

Teachers: build a paper, print it with the mark schemes at the end, and sign your school up to set your classes activities on every topic.

Fetch Decode Explain isn't affiliated with or endorsed by Pearson Edexcel.