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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 693 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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3 questions · 4 marks

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1Multiple choice1 markUnits & Conversion Swap Remove

A computer stores data in binary.

Identify the number of bits in one kibibyte.

[1 mark]
  • A1024
  • B8000
  • C8192
  • D8 388 608
Mark scheme
  • C 8192 (1)
  • The only correct answer is C. The correct answer is 8192.
  • A is not correct because 1024 is the number of bytes in a kibibyte
  • B is not correct because 8000 is the number of bits in 1000 bytes
  • D is not correct because 8 388 608 is the number of bits in a mebibyte
Example answers and how they were marked
Full marks1/1

C 8192

Why: Correct: one kibibyte is 1024 bytes and 1024 × 8 = 8192 bits (1).

No marks0/1

A 1024

Why: Near miss: 1024 is the number of bytes in a kibibyte, not the number of bits (0).

No marks0/1

B 8000

Why: Typical misconception: uses 1000 bytes for a kibibyte, giving 1000 × 8 = 8000 bits (0).

2Short recall2 marksTopologies Swap Remove

Mesh is a type of network topology.

State two characteristics of a mesh topology.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • Each node/device has multiple direct connections to other nodes/devices (in a full mesh, every node is connected directly to every other node) (1)
  • There is no central device/switch (1)
  • Nodes act as routers/relay data for other nodes / data can take multiple/different routes to its destination / data can still be sent if a connection/node fails (1)
  • More connections/cables are needed as the number of nodes increases (1)
  • The network can be expanded without disrupting existing devices (1)

Allow answers that refer to full or partial mesh.

Allow 'more connections/cables are needed' and 'can be expanded' as characteristics (they may be described as advantages or disadvantages).

Do not accept 'more secure' or 'no collisions' without qualification.

Do not accept 'fast' or 'reliable' without qualification.

Do not accept all devices connect to one main cable (this describes a bus topology).

Do not accept it uses a central switch/hub or data is sent through a central hub (this describes a star topology).

Do not accept 'expensive' without qualification (e.g. because more cables/connections are needed).

Example answers and how they were marked
Full marks2/2

Each device is connected to several other devices, and data can be sent along more than one route.

Why: Multiple direct connections (1) and data can take multiple routes (1).

Some marks1/2

There is no central switch.

Why: No central device credited (1), but only one characteristic given.

No marks0/2

Data is sent through a central hub.

Why: Misconception: this describes a star topology, not a mesh topology.

3Convert1 markDenary to Hexadecimal Conversion Swap Remove

Computer systems manipulate bit patterns.

Convert the hexadecimal number D5 to denary.

[1 mark]
Mark scheme

Award one mark for:

  • 213 (1)
Example answers and how they were marked
Full marks1/1

213

Why: 13 × 16 + 5 = 213 (1).

No marks0/1

93

Why: Takes the right-hand digit as the 16s, so the value is wrong.

No marks0/1

18

Why: Adds the two digits instead of multiplying the first by 16.

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