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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 604 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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4 questions · 6 marks

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1Multiple choice1 markFetch Decode Execute Cycle Swap Remove

Identify the bus that carries memory addresses from the CPU to main memory. (1)

[1 mark]
  • AAddress bus
  • BControl bus
  • CData bus
  • DProgram counter
Mark scheme
  • A Address bus (1)
  • The only correct answer is A. The correct answer is address bus.
  • B is not correct because the control bus carries control signals
  • C is not correct because the data bus carries data and instructions
  • D is not correct because the program counter holds the address of the next instruction, it does not carry addresses
Example answers and how they were marked
Full marks1/1

A Address bus

Why: Correct option: the address bus carries memory addresses from the CPU to main memory (1).

No marks0/1

C Data bus

Why: Near-miss distractor: the data bus carries data and instructions between the CPU and main memory, not memory addresses (0).

No marks0/1

D Program counter

Why: Misconception: the program counter is a register that holds the address of the next instruction, it does not carry addresses to main memory (0).

2Multiple choice1 markCharacter Sets Swap Remove

Characters are encoded using 7-bit ASCII.

Identify the number of different characters that can be represented using 7-bit ASCII.

[1 mark]
  • A64
  • B127
  • C128
  • D256
Mark scheme
  • C 128 (1)
  • The only correct answer is C. The correct answer is 128.
  • A is not correct because 6 bits give only 64 different combinations
  • B is not correct because 127 is the largest 7-bit value, not the number of characters that 7 bits can represent
  • D is not correct because 256 characters need 8 bits, as used by 8-bit extended ASCII
Example answers and how they were marked
Full marks1/1

C 128

Why: Selects the only correct option (1): 7 bits give 2 to the power of 7, which is 128 different characters.

No marks0/1

D 256

Why: Near miss scoring 0: 256 is the number of characters that 8 bits give in extended ASCII, not 7-bit ASCII.

No marks0/1

B 127

Why: Misconception scoring 0, the off-by-one error the examiners' report describes: 127 is the largest 7-bit value, but 7 bits give 128 different characters.

3Short recall2 marksUnits & Conversion Swap Remove

Data storage is measured in binary multiples.

Define the term bit.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • A binary digit (1)
  • Has the value 0 or 1 (1)
  • The smallest unit of data storage (1)
  • A single 0 or 1 (1)

Allow binary digit/binary place value for binary digit

Allow a single binary digit for a single 0 or 1

Do not accept a group of 8 bits/half a nibble of 4 bits, which describe a byte or a nibble

Do not accept a binary number/binary on its own

Example answers and how they were marked
Full marks2/2

A binary digit that can have the value 0 or 1.

Why: A binary digit (1) and has the value 0 or 1 (1).

Some marks1/2

It is the smallest unit of data storage.

Why: Smallest unit of data storage (1), but does not state that it is a binary digit or that it has the value 0 or 1.

No marks0/2

A group of 8 bits.

Why: Describes a byte, not a bit; no creditworthy point and named in the Do not accept line.

4Calculate2 marksBinary Shifts Swap Remove

Binary, denary and hexadecimal patterns represent numbers.

Complete the table with the result of applying the shift to the binary pattern.

[2 marks]
Binary patternShift8-bit binary result
1010 1100Arithmetic shift right by 1
Mark scheme

Award one mark for each correct nibble in the correct order:

  • 1101 (1)
  • 0110 (1)

0 marks if the response is not 8-bit binary.

Example answers and how they were marked
Full marks2/2

1101 0110

Why: Every bit moves 1 place right, with copies of the sign bit (1) in from the left: both nibbles are correct (2).

Some marks1/2

0101 0110

Why: Fills the gap on the left with 0s, as a logical shift would, instead of copying the sign bit. The second nibble is correct (1); the first is not.

No marks0/2

0101 1000

Why: Shifts the bits the wrong way. Neither nibble is correct.

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