Edexcel GCSE Computer Science (1CP2) Exam Questions

• B To reduce the time taken to transmit a file (1)
• The only correct answer is B. The correct answer is to reduce the time taken to transmit a file.
• A is not correct because compression reduces file size, which can reduce the number of packets sent
• C is not correct because lossy compression can reduce the quality of a file
• D is not correct because encryption, not compression, can make a file harder to open

Award one mark for:

• Router (1)

Allow routers (plural).

Allow minor spelling errors that are clearly router, e.g. rooter.

Do not accept switch, hub (these forward data within a network, not between networks), modem or server.

Do not accept gateway on its own.

Award one mark for:

• 224 (1)

Award one mark for any of the following up to a maximum of two marks:

• (Only) 128 different characters can be represented / 7 bits give 2^7 = 128 different codes (1)
• It cannot represent characters from languages other than English / non-English alphabets, e.g. Greek, Chinese (1)
• It cannot represent accented characters, e.g. é, ñ (1)
• It cannot represent symbols or emoji that are not in the ASCII character set (1)

Award a maximum of one mark for the last three bullets, as they are all examples of characters that fall outside the 128 ASCII codes.

Allow 'it can only represent 128 characters, so some characters are missing' for the first bullet.

Do not accept 'it uses 7 bits' / 'it only uses 7 bits' on its own, without saying what this limits.

Do not accept 'it can only store a limited amount of text' / 'it can only store short messages', as 7 bits limits the number of characters available, not the length of a message.

Do not accept 'it can only represent the characters in the ASCII character set', as this repeats the question.

Do not accept 'it is old/out of date' or 'it cannot store numbers'.

Award one mark for each of:

• 5 × 1024^3 / 5 × 1024 × 1024 × 1024 / 5 × 2^30, for the number of bytes (1)
• A fully correct expression with × 8 to convert bytes to bits, in any order, e.g. 5 × 1024^3 × 8, 8 × 5 × 2^30 (1)

Accept 5 × 1 073 741 824 × 8.

Accept 5 × 2^33 or 42 949 672 960 as a fully correct expression (2 marks).

Do not accept 5 × 1000^3 × 8, which uses decimal multiples.

Do not accept ÷ 8, which converts bits to bytes.

Award up to two marks for a linked description such as:

• The user enters a username/user ID and password/PIN (1) which is compared with the account details the operating system has stored (1)
• The operating system keeps a file/list/database of users and their passwords (1) to check the login details the user enters against (1)
• The operating system compares the entered details with the details stored for that user (1) and if they do not match, access is refused/denied (1)
• The entered details are checked against the access rights stored for that user (1) so access is only allowed when the details are correct (1)

Do not award for 'it asks for a password' on its own, without saying what the password is checked against.

A stored list/file of users and passwords with no check of the login details earns one mark only.

Do not accept responses about file management, such as finding or opening the user's files.

Award one mark for each correct nibble in the correct order:

• 1100 (1)
• 0111 (1)

0 marks if the response is not 8-bit binary.

Indicative content

Control unit and ALU

• The control unit fetches and decodes each instruction that the new computers are running, so it works out which operation has to be carried out.
• The control unit sends control signals to the ALU and to main memory over the control bus so that the other components carry out the instruction.
• The control unit receives the clock signal, so each stage of the cycle begins on a clock tick.
• The ALU carries out arithmetic operations, such as adding two values, and logical operations, such as comparing two values, during the execute stage.
• The ALU is the component that performs the calculations that a program running on the new computers needs.
• The data the ALU works on is held in registers, and the result of the operation is stored in a register such as the accumulator.

Registers

• Registers are small, very fast memory locations inside the CPU that hold the instructions and data the CPU is working on.
• The program counter holds the address of the next instruction to be fetched, and it is incremented each time an instruction is fetched.
• The memory address register (MAR) holds the address of the main memory location that is to be read from or written to during the fetch stage.
• The memory data register (MDR) holds the instruction or data brought from main memory (RAM) over the data bus before it is decoded.
• The accumulator holds the result of an operation carried out by the ALU.
• Because registers are inside the CPU, the CPU can keep working on a value without going back to slower main memory during the cycle.

Working together as the cycle repeats

• In the fetch stage, the address of the next instruction is copied from the program counter into the memory address register and sent to main memory over the address bus, and the instruction comes back over the data bus into the memory data register.
• In the decode stage the control unit interprets the instruction and works out which components are needed for it.
• In the execute stage the control unit signals the ALU or main memory so that the instruction is carried out, and the result is held in a register.
• The clock sends a regular pulse so that the fetch, decode and execute stages of each instruction happen in step.
• The program counter is then incremented, so the cycle repeats with the address of the next instruction to be fetched.

Levels

• Level 0 (0 marks): No rewardable content.
• Level 1 (1–2 marks): Basic, independent points are made, showing elements of understanding of key concepts/principles of computer science. (AO1) The discussion will contain basic information with little linkage between points made or application to the context. (AO2)
• Level 2 (3–4 marks): Demonstrates adequate understanding of key concepts/principles of computer science. (AO1) The discussion shows some linkages and lines of reasoning with some structure and application to the context. (AO2)
• Level 3 (5–6 marks): Demonstrates comprehensive understanding of key concepts/principles of computer science to support the discussion being presented. (AO1) The discussion is well developed, with sustained lines of reasoning that are coherent and logically structured, and which clearly apply to the context. (AO2)

Additional guidance

• A list of correct but independent roles, with no linkage between the components and no reference to the stages of the cycle, is limited to Level 1; an answer that gives the roles of the components but does not link them to the fetch, decode and execute stages is limited to Level 2; a Level 3 answer must cover the control unit/ALU and registers and link them to the stages of the cycle.
• Award no credit for 'the control unit is the brain of the CPU', 'the ALU stores data' or 'registers are the same as RAM'; accept the program counter, MAR, MDR and accumulator as examples of registers, accept the clock, address bus, data bus and control bus where they are linked to a stage of the cycle, and accept 'main memory' or 'RAM' as equivalent.