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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 604 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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3 questions · 5 marks

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1Multiple choice1 markSound Swap Remove

A sound wave is sampled and the amplitude of each sample is stored using 2 bits.

Identify the number of different amplitude values that can be stored for each sample.

[1 mark]
  • A2
  • B4
  • C8
  • D16
Mark scheme
  • B 4 (1)
  • The only correct answer is B. The correct answer is 4 (2 bits give 2^2 = 4 values).
  • A is not correct because 2 is the number of bits used to store each sample
  • C is not correct because 8 different amplitude values would need 3 bits
  • D is not correct because 16 different amplitude values would need 4 bits
Example answers and how they were marked
Full marks1/1

B 4

Why: Selects the only correct option (1).

No marks0/1

C 8

Why: Near miss: 8 values would need 3 bits, one more than this recording uses (0).

No marks0/1

A 2

Why: Typical misconception: 2 is the number of bits, not the number of amplitude values those bits can store (0).

2Short recall2 marksFetch Decode Execute Cycle Swap Remove

The control unit is one component of the CPU.

Give two roles of the control unit during the fetch-decode-execute cycle.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • Decodes the instruction / works out what the instruction is (1)
  • Sends control signals to the other components (of the CPU) (1)
  • Coordinates/controls the activities of the CPU (1)
  • Directs the timing of the other components / controls when each component acts (1)

Do not accept carrying out arithmetic or logical operations, as this is the role of the ALU.

Do not accept holding/storing the data or instructions, as this is the role of the registers/main memory.

Example answers and how they were marked
Full marks2/2

It decodes each instruction and sends control signals to the other components to tell them what to do.

Why: Decodes the instruction (1) and sends control signals to the other components (1).

Some marks1/2

It decodes the instructions and carries out the calculations.

Why: Decoding the instruction (1); the calculations are carried out by the ALU, so the second part earns nothing.

No marks0/2

It stores the data that the CPU is working on.

Why: Storing data is the role of the registers/main memory, not the control unit, so no point is creditworthy.

3Describe2 marksFile Management Swap Remove

A user saves a new file into a folder that already contains files.

Describe how the operating system prevents a new file overwriting an existing file.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • Checks/compares the new file (name)/filename against the names of files already in the folder/directory (1) to see if the name is already in use (1)
  • Refuses to save/allow the new file when the (file) name already exists (1) so the existing file is not replaced/overwritten (1)
  • Prompts/asks the user to choose/enter a different (file) name (1) so both files can be saved without one replacing the other (1)

A point without a linked development can earn one mark.

For both marks, the development must follow/associate with the point.

Do not accept responses about defragmentation.

Do not accept the operating system making a backup copy, or warning the user that a file may be overwritten, without saying that the (file) name is checked or the new file is not saved.

Do not accept responses about process management or saving files to RAM.

Do not award a second mark for repeating the question, e.g. 'it stops the new file overwriting the existing file'.

Example answers and how they were marked
Full marks2/2

It checks the new file name against the names of files already in the folder (1) to see whether the name is already in use (1).

Why: Linked point (1) and development (1).

Some marks1/2

It checks the file name against the names already in the folder.

Why: Creditworthy point (1) on its own; no linked development, so one mark.

No marks0/2

It defragments the disk so there is room for the new file.

Why: Defragmentation is not accepted by the mark scheme.

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