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Edexcel GCSE Computer Science (1CP2) Exam Questions

Build a practice paper from 693 exam-style questions, each with its mark scheme and example answers. Print it, or answer it on paper and then open the mark schemes. Or browse the questions by topic.

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3 questions · 6 marks

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1Short recall2 marksCharacter Sets Swap Remove

A computer uses a character set to represent text.

Define the term character set.

[2 marks]
Mark scheme

Award one mark for any of the following up to a maximum of two marks:

  • A set/collection of characters (1)
  • (Characters such as) letters, digits and symbols/punctuation (1)
  • Each character is represented by a unique code/binary value (1)
  • A standard set of characters so that text can be exchanged between computer systems (1)

Allow 'a list of characters that a computer can represent' for the first mark.

Do not accept a program/software that converts text into binary.

Do not accept 'a set of binary codes' on its own.

Example answers and how they were marked
Full marks2/2

A set of characters, such as letters, digits and punctuation, where each character is represented by a unique binary code.

Why: Set/collection of characters with examples (1) and each character has a unique code (1).

Some marks1/2

A set of letters and symbols that a computer can use to represent text.

Why: Awarded for the set/collection of characters (1); no creditworthy point saying each character has its own unique code (0).

No marks0/2

A program that converts the keys pressed on a keyboard into binary.

Why: Describes software that converts text, not a set of characters; the Do not accept line applies.

2Describe2 marksTranslators Swap Remove

A compiler and an interpreter both translate source code.

Describe one difference between what a compiler produces and what an interpreter produces.

[2 marks]
Mark scheme

Award up to two marks for a linked description such as:

  • A compiler produces object code/machine code/an executable (file) (1) whereas an interpreter produces no object code/translated file (1)
  • A compiler produces a machine code file (1) that can be run on its own/without the compiler/translator being present (1)
  • An interpreter produces no object code/file (1) because it translates and executes each line instead of saving translated code (1)
  • The compiler's output can be saved/stored (1) and run again later, while interpreted code has to be translated again each time it is run (1)

Allow binary for machine code.

Allow executable/an executable for object code.

Do not accept responses about translating the whole program, reporting errors or the speed of execution.

Do not accept 'the interpreter translates/executes one line at a time' on its own: this is how it translates, not what it produces. It earns the development only when linked to no object code/translated file being produced.

Do not accept the interpreter producing object code/an executable.

Example answers and how they were marked
Full marks2/2

A compiler produces object code, which is saved as a file, whereas an interpreter does not produce a file because it translates and executes each line.

Why: Compiler produces object code (1) contrasted with the interpreter producing no object code/translated file (1).

Some marks1/2

The compiler produces machine code.

Why: Machine code/object code produced (1); there is no contrast with the interpreter, so the development is not earned.

No marks0/2

The interpreter produces object code for each line it translates.

Why: Reverses the translators' outputs: the interpreter produces no object code, so nothing is creditworthy.

3Convert2 marksDenary to Binary Conversion Swap Remove

Computer systems manipulate bit patterns.

Convert the denary number 140 to 8-bit binary.

[2 marks]
Mark scheme

Award one mark for each correct nibble in the correct order:

  • 1000 (1)
  • 1100 (1)

0 marks if the response is not 8-bit binary.

Example answers and how they were marked
Full marks2/2

1000 1100

Why: 140 = 128 + 8 + 4: both nibbles are correct (2).

Some marks1/2

1000 1101

Why: Converts 141 instead (a slip in adding up the place values). The first nibble is correct (1); the second is not.

No marks0/2

0011 0001

Why: The bits are written in reverse, smallest place value first. Neither nibble is correct.

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