12 OCR GCSE Computer Science (J277) exam-style questions on Hexadecimal to Binary Conversion (1.2 Memory & Storage), 30 marks in all. Answer them on paper or print them, then open the mark schemes and example answers to see how each is marked.
Computers represent data in binary form.
Convert the hexadecimal number 7E into 8-bit binary.
Guidance
Correct answer only – binary must be 8 bits.
01111110
Why: 7 is 0111 and E is 1110 (1).
11100111
Why: The two nibbles are in the wrong order (0).
7 14
Why: Writes the denary value of each digit instead of its 4 bits (0).
Binary numbers can represent different forms of data.
Convert the hexadecimal number D6 into 8-bit binary.
Guidance
Correct answer only – binary must be 8 bits.
11010110
Why: D is 1101 and 6 is 0110 (1).
01101101
Why: The two nibbles are in the wrong order (0).
13 6
Why: Writes the denary value of each digit instead of its 4 bits (0).
Computers store all data as binary.
Convert the hexadecimal number 1F into 8-bit binary.
Guidance
Correct answer only – binary must be 8 bits.
00011111
Why: 1 is 0001 and F is 1111 (1).
11110001
Why: The two nibbles are in the wrong order (0).
1 15
Why: Writes the denary value of each digit instead of its 4 bits (0).
Computers store all data as binary.
Convert the hexadecimal number B4 into 8-bit binary.
Guidance
Correct answer only – binary must be 8 bits.
10110100
Why: B is 1011 and 4 is 0100 (1).
01001011
Why: The two nibbles are in the wrong order (0).
11 4
Why: Writes the denary value of each digit instead of its 4 bits (0).
Computers store all data as binary.
Convert the hexadecimal number A2 into 8-bit binary.
Guidance
Correct answer only – binary must be 8 bits.
10100010
Why: A is 1010 and 2 is 0010 (1).
00101010
Why: The two nibbles are in the wrong order (0).
10 2
Why: Writes the denary value of each digit instead of its 4 bits (0).
Binary numbers can represent different forms of data.
Convert the hexadecimal number ED into 8-bit binary.
Guidance
Correct answer only – binary must be 8 bits.
11101101
Why: E is 1110 and D is 1101 (1).
11011110
Why: The two nibbles are in the wrong order (0).
14 13
Why: Writes the denary value of each digit instead of its 4 bits (0).
Computers represent data in binary form.
Complete the table by writing the missing denary, 8-bit binary or hexadecimal values.
| Denary | 8-bit binary | Hexadecimal |
|---|---|---|
| 188 | 10111100 | |
| 10101111 | AF | |
| 211 | 11010011 | |
| 255 | FF |
1 mark for each completed box
Denary | 8-bit binary | Hexadecimal
188 | 10111100 | BC
175 | 10101111 | AF
211 | 11010011 | D3
255 | 11111111 | FF
Guidance
Correct answers only – binary must be 8 bits.
Ignore case in hex.
BC
175
D3
11111111
Why: Every missing value is correct, and the binary is 8 bits (4).
1112
175
D3
11111110
Why: Rows 2 and 3 are correct (2); row 1 (hexadecimal) has a digit over 9 written in denary (0) and row 4 (binary) has its last bit wrong (0).
1112
245
133
11111110
Why: None of the values is right: row 1 (hexadecimal) has a digit over 9 written in denary (0); row 2 (denary) reads the place values from the wrong end (0); row 3 (hexadecimal) has a digit over 9 written in denary (0); row 4 (binary) has its last bit wrong (0).
Binary numbers can represent different forms of data.
Complete the table by writing the missing denary, 8-bit binary or hexadecimal values.
| Denary | 8-bit binary | Hexadecimal |
|---|---|---|
| 63 | 3F | |
| 00111101 | 3D | |
| 85 | 01010101 | |
| 143 | 10001111 |
1 mark for each completed box
Denary | 8-bit binary | Hexadecimal
63 | 00111111 | 3F
61 | 00111101 | 3D
85 | 01010101 | 55
143 | 10001111 | 8F
Guidance
Correct answers only – binary must be 8 bits.
Ignore case in hex.
00111111
61
55
8F
Why: Every missing value is correct, and the binary is 8 bits (4).
111111
61
55
815
Why: Rows 2 and 3 are correct (2); row 1 (binary) leaves off the leading 0s, so it is not 8 bits (0) and row 4 (hexadecimal) has a digit over 9 written in denary (0).
111111
188
56
815
Why: None of the values is right: row 1 (binary) leaves off the leading 0s, so it is not 8 bits (0); row 2 (denary) reads the place values from the wrong end (0); row 3 (hexadecimal) is a slip in working out the last digit (0); row 4 (hexadecimal) has a digit over 9 written in denary (0).
Computers represent data in binary form.
Each row in the table contains a number written as a denary value, an 8-bit binary value and a 2-digit hexadecimal value. Some values are missing.
Complete the table by writing in the missing value for each number.
| Denary | 8-bit binary | Hexadecimal |
|---|---|---|
| 150 | 96 | |
| 189 | 10111101 | |
| 208 | 11010000 | |
| 11010010 | D2 |
1 mark for each completed box
Denary | 8-bit binary | Hexadecimal
150 | 10010110 | 96
189 | 10111101 | BD
208 | 11010000 | D0
210 | 11010010 | D2
Guidance
Correct answers only – binary must be 8 bits.
Ignore case in hex.
10010110
BD
D0
210
Why: Every missing value is correct, and the binary is 8 bits (4).
01101001
BD
D0
75
Why: Rows 2 and 3 are correct (2); row 1 (binary) is back to front (0) and row 4 (denary) reads the place values from the wrong end (0).
01101001
1113
130
75
Why: None of the values is right: row 1 (binary) is back to front (0); row 2 (hexadecimal) has a digit over 9 written in denary (0); row 3 (hexadecimal) has a digit over 9 written in denary (0); row 4 (denary) reads the place values from the wrong end (0).
Computers store all data as binary.
Complete the table by writing the missing denary, 8-bit binary or hexadecimal values.
| Denary | 8-bit binary | Hexadecimal |
|---|---|---|
| 162 | A2 | |
| 60 | 3C | |
| 71 | 01000111 | |
| 10110011 | B3 |
1 mark for each completed box
Denary | 8-bit binary | Hexadecimal
162 | 10100010 | A2
60 | 00111100 | 3C
71 | 01000111 | 47
179 | 10110011 | B3
Guidance
Correct answers only – binary must be 8 bits.
Ignore case in hex.
10100010
00111100
47
179
Why: Every missing value is correct, and the binary is 8 bits (4).
01000101
00111100
47
205
Why: Rows 2 and 3 are correct (2); row 1 (binary) is back to front (0) and row 4 (denary) reads the place values from the wrong end (0).
01000101
111100
74
205
Why: None of the values is right: row 1 (binary) is back to front (0); row 2 (binary) leaves off the leading 0s, so it is not 8 bits (0); row 3 (hexadecimal) has its digits the wrong way round (0); row 4 (denary) reads the place values from the wrong end (0).
Computers represent data in binary form.
Each row in the table contains a number written as a denary value, an 8-bit binary value and a 2-digit hexadecimal value. Some values are missing.
Complete the table by writing in the missing value for each number.
| Denary | 8-bit binary | Hexadecimal |
|---|---|---|
| 10101110 | AE | |
| 172 | 10101100 | |
| 230 | E6 | |
| 201 | 11001001 |
1 mark for each completed box
Denary | 8-bit binary | Hexadecimal
174 | 10101110 | AE
172 | 10101100 | AC
230 | 11100110 | E6
201 | 11001001 | C9
Guidance
Correct answers only – binary must be 8 bits.
Ignore case in hex.
174
AC
11100110
C9
Why: Every missing value is correct, and the binary is 8 bits (4).
117
AC
11100110
129
Why: Rows 2 and 3 are correct (2); row 1 (denary) reads the place values from the wrong end (0) and row 4 (hexadecimal) has a digit over 9 written in denary (0).
117
1012
01100111
129
Why: None of the values is right: row 1 (denary) reads the place values from the wrong end (0); row 2 (hexadecimal) has a digit over 9 written in denary (0); row 3 (binary) is back to front (0); row 4 (hexadecimal) has a digit over 9 written in denary (0).
Computers represent data in binary form.
Complete the table by writing the missing denary, 8-bit binary or hexadecimal values.
| Denary | 8-bit binary | Hexadecimal |
|---|---|---|
| 75 | 4B | |
| 11110111 | F7 | |
| 32 | 00100000 | |
| 225 | E1 |
1 mark for each completed box
Denary | 8-bit binary | Hexadecimal
75 | 01001011 | 4B
247 | 11110111 | F7
32 | 00100000 | 20
225 | 11100001 | E1
Guidance
Correct answers only – binary must be 8 bits.
Ignore case in hex.
01001011
247
20
11100001
Why: Every missing value is correct, and the binary is 8 bits (4).
1001011
247
20
10000111
Why: Rows 2 and 3 are correct (2); row 1 (binary) leaves off the leading 0s, so it is not 8 bits (0) and row 4 (binary) is back to front (0).
1001011
239
02
10000111
Why: None of the values is right: row 1 (binary) leaves off the leading 0s, so it is not 8 bits (0); row 2 (denary) reads the place values from the wrong end (0); row 3 (hexadecimal) has its digits the wrong way round (0); row 4 (binary) is back to front (0).
Teachers: print these as a worksheet with the mark schemes at the end, and sign your school up to set your classes activities on Hexadecimal to Binary Conversion.
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