12 OCR GCSE Computer Science (J277) exam-style questions on Binary to Hexadecimal Conversion (1.2 Memory & Storage), 30 marks in all. Answer them on paper or print them, then open the mark schemes and example answers to see how each is marked.
Binary numbers can represent different forms of data.
Convert the binary number 01011111 into hexadecimal.
Guidance
Correct answer only
Ignore case
5F
Why: 0101 is 5 and 1111 is F: 5F (1).
515
Why: A digit over 9 is written in denary instead of as a letter (0).
F5
Why: The digits are the wrong way round (0).
Computers represent data in binary form.
Convert the binary number 11101110 into hexadecimal.
Guidance
Correct answer only
Ignore case
EE
Why: 1110 is E and 1110 is E: EE (1).
1414
Why: A digit over 9 is written in denary instead of as a letter (0).
FF
Why: The digits are the wrong way round (0).
Computers store all data as binary.
Convert the binary number 10100101 into hexadecimal.
Guidance
Correct answer only
Ignore case
A5
Why: 1010 is A and 0101 is 5: A5 (1).
105
Why: A digit over 9 is written in denary instead of as a letter (0).
5A
Why: The digits are the wrong way round (0).
Computers store all data as binary.
Convert the binary number 11110000 into hexadecimal.
Guidance
Correct answer only
Ignore case
F0
Why: 1111 is F and 0000 is 0: F0 (1).
150
Why: A digit over 9 is written in denary instead of as a letter (0).
F
Why: The final 0 is left off, which changes the value (0).
Binary numbers can represent different forms of data.
Convert the binary number 00111100 into hexadecimal.
Guidance
Correct answer only
Ignore case
3C
Why: 0011 is 3 and 1100 is C: 3C (1).
312
Why: A digit over 9 is written in denary instead of as a letter (0).
C3
Why: The digits are the wrong way round (0).
Computers store all data as binary.
Convert the binary number 10100000 into hexadecimal.
Guidance
Correct answer only
Ignore case
A0
Why: 1010 is A and 0000 is 0: A0 (1).
100
Why: A digit over 9 is written in denary instead of as a letter (0).
A
Why: The final 0 is left off, which changes the value (0).
Computers store all data as binary.
Each row in the table contains a number written as a denary value, an 8-bit binary value and a 2-digit hexadecimal value. Some values are missing.
Complete the table by writing in the missing value for each number.
| Denary | 8-bit binary | Hexadecimal |
|---|---|---|
| 55 | 00110111 | |
| 10111110 | BE | |
| 178 | B2 | |
| 01101011 | 6B |
1 mark for each completed box
Denary | 8-bit binary | Hexadecimal
55 | 00110111 | 37
190 | 10111110 | BE
178 | 10110010 | B2
107 | 01101011 | 6B
Guidance
Correct answers only – binary must be 8 bits.
Ignore case in hex.
37
190
10110010
107
Why: Every missing value is correct, and the binary is 8 bits (4).
73
190
10110010
214
Why: Rows 2 and 3 are correct (2); row 1 (hexadecimal) has its digits the wrong way round (0) and row 4 (denary) reads the place values from the wrong end (0).
73
125
01001101
214
Why: None of the values is right: row 1 (hexadecimal) has its digits the wrong way round (0); row 2 (denary) reads the place values from the wrong end (0); row 3 (binary) is back to front (0); row 4 (denary) reads the place values from the wrong end (0).
Binary numbers can represent different forms of data.
Each row in the table contains a number written as a denary value, an 8-bit binary value and a 2-digit hexadecimal value. Some values are missing.
Complete the table by writing in the missing value for each number.
| Denary | 8-bit binary | Hexadecimal |
|---|---|---|
| 00111001 | 39 | |
| 209 | D1 | |
| 22 | 16 | |
| 237 | 11101101 |
1 mark for each completed box
Denary | 8-bit binary | Hexadecimal
57 | 00111001 | 39
209 | 11010001 | D1
22 | 00010110 | 16
237 | 11101101 | ED
Guidance
Correct answers only – binary must be 8 bits.
Ignore case in hex.
57
11010001
00010110
ED
Why: Every missing value is correct, and the binary is 8 bits (4).
156
11010001
00010110
1413
Why: Rows 2 and 3 are correct (2); row 1 (denary) reads the place values from the wrong end (0) and row 4 (hexadecimal) has a digit over 9 written in denary (0).
156
10001011
10110
1413
Why: None of the values is right: row 1 (denary) reads the place values from the wrong end (0); row 2 (binary) is back to front (0); row 3 (binary) leaves off the leading 0s, so it is not 8 bits (0); row 4 (hexadecimal) has a digit over 9 written in denary (0).
Binary numbers can represent different forms of data.
Complete the table by writing the missing denary, 8-bit binary or hexadecimal values.
| Denary | 8-bit binary | Hexadecimal |
|---|---|---|
| 250 | 11111010 | |
| 10101000 | A8 | |
| 58 | 00111010 | |
| 155 | 9B |
1 mark for each completed box
Denary | 8-bit binary | Hexadecimal
250 | 11111010 | FA
168 | 10101000 | A8
58 | 00111010 | 3A
155 | 10011011 | 9B
Guidance
Correct answers only – binary must be 8 bits.
Ignore case in hex.
FA
168
3A
10011011
Why: Every missing value is correct, and the binary is 8 bits (4).
1510
168
3A
11011001
Why: Rows 2 and 3 are correct (2); row 1 (hexadecimal) has a digit over 9 written in denary (0) and row 4 (binary) is back to front (0).
1510
21
310
11011001
Why: None of the values is right: row 1 (hexadecimal) has a digit over 9 written in denary (0); row 2 (denary) reads the place values from the wrong end (0); row 3 (hexadecimal) has a digit over 9 written in denary (0); row 4 (binary) is back to front (0).
Binary numbers can represent different forms of data.
Each row in the table contains a number written as a denary value, an 8-bit binary value and a 2-digit hexadecimal value. Some values are missing.
Complete the table by writing in the missing value for each number.
| Denary | 8-bit binary | Hexadecimal |
|---|---|---|
| 101 | 65 | |
| 11110000 | F0 | |
| 204 | 11001100 | |
| 217 | D9 |
1 mark for each completed box
Denary | 8-bit binary | Hexadecimal
101 | 01100101 | 65
240 | 11110000 | F0
204 | 11001100 | CC
217 | 11011001 | D9
Guidance
Correct answers only – binary must be 8 bits.
Ignore case in hex.
01100101
240
CC
11011001
Why: Every missing value is correct, and the binary is 8 bits (4).
1100101
240
CC
10011011
Why: Rows 2 and 3 are correct (2); row 1 (binary) leaves off the leading 0s, so it is not 8 bits (0) and row 4 (binary) is back to front (0).
1100101
15
1212
10011011
Why: None of the values is right: row 1 (binary) leaves off the leading 0s, so it is not 8 bits (0); row 2 (denary) reads the place values from the wrong end (0); row 3 (hexadecimal) has a digit over 9 written in denary (0); row 4 (binary) is back to front (0).
Computers store all data as binary.
Each row in the table contains a number written as a denary value, an 8-bit binary value and a 2-digit hexadecimal value. Some values are missing.
Complete the table by writing in the missing value for each number.
| Denary | 8-bit binary | Hexadecimal |
|---|---|---|
| 28 | 1C | |
| 10101000 | A8 | |
| 198 | 11000110 | |
| 158 | 9E |
1 mark for each completed box
Denary | 8-bit binary | Hexadecimal
28 | 00011100 | 1C
168 | 10101000 | A8
198 | 11000110 | C6
158 | 10011110 | 9E
Guidance
Correct answers only – binary must be 8 bits.
Ignore case in hex.
00011100
168
C6
10011110
Why: Every missing value is correct, and the binary is 8 bits (4).
11100
168
C6
01111001
Why: Rows 2 and 3 are correct (2); row 1 (binary) leaves off the leading 0s, so it is not 8 bits (0) and row 4 (binary) is back to front (0).
11100
21
126
01111001
Why: None of the values is right: row 1 (binary) leaves off the leading 0s, so it is not 8 bits (0); row 2 (denary) reads the place values from the wrong end (0); row 3 (hexadecimal) has a digit over 9 written in denary (0); row 4 (binary) is back to front (0).
Computers store all data as binary.
Each row in the table contains a number written as a denary value, an 8-bit binary value and a 2-digit hexadecimal value. Some values are missing.
Complete the table by writing in the missing value for each number.
| Denary | 8-bit binary | Hexadecimal |
|---|---|---|
| 122 | 01111010 | |
| 00111111 | 3F | |
| 107 | 01101011 | |
| 225 | E1 |
1 mark for each completed box
Denary | 8-bit binary | Hexadecimal
122 | 01111010 | 7A
63 | 00111111 | 3F
107 | 01101011 | 6B
225 | 11100001 | E1
Guidance
Correct answers only – binary must be 8 bits.
Ignore case in hex.
7A
63
6B
11100001
Why: Every missing value is correct, and the binary is 8 bits (4).
710
63
6B
10000111
Why: Rows 2 and 3 are correct (2); row 1 (hexadecimal) has a digit over 9 written in denary (0) and row 4 (binary) is back to front (0).
710
252
611
10000111
Why: None of the values is right: row 1 (hexadecimal) has a digit over 9 written in denary (0); row 2 (denary) reads the place values from the wrong end (0); row 3 (hexadecimal) has a digit over 9 written in denary (0); row 4 (binary) is back to front (0).
Teachers: print these as a worksheet with the mark schemes at the end, and sign your school up to set your classes activities on Binary to Hexadecimal Conversion.
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